Power Factor using Area of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)))
PF = sqrt(((4)*(P^2)*ρ*L)/(A*Ploss*(Vm^2)))
This formula uses 1 Functions, 7 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Power Factor - The power factor of an AC electrical power system is defined as the ratio of the real power absorbed by the load to the apparent power flowing in the circuit.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
PF = sqrt(((4)*(P^2)*ρ*L)/(A*Ploss*(Vm^2))) --> sqrt(((4)*(300^2)*1.7E-05*24)/(1.28*2.67*(230^2)))
Evaluating ... ...
PF = 0.028503151449111
STEP 3: Convert Result to Output's Unit
0.028503151449111 --> No Conversion Required
FINAL ANSWER
0.028503151449111 0.028503 <-- Power Factor
(Calculation completed in 00.004 seconds)

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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Power and Power Factor Calculators

Power Transmitted using Area of X-Section (1-Phase 2-Wire US)
​ LaTeX ​ Go Power Transmitted = sqrt((Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*Line Losses*((cos(Phase Difference))^2))/(4*Resistivity*Length of Underground AC Wire))
Power Transmitted using Volume of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Power Transmitted = sqrt(Line Losses*Volume Of Conductor*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(8*Resistivity*(Length of Underground AC Wire)^2))
Power Factor using Area of X-Section (1-Phase 2-Wire US)
​ LaTeX ​ Go Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)))
Power Factor using Volume of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Power Factor = sqrt((2)*Constant Underground AC/Volume Of Conductor)

Power Factor using Area of X-Section (1-Phase 2-Wire US) Formula

​LaTeX ​Go
Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2)))
PF = sqrt(((4)*(P^2)*ρ*L)/(A*Ploss*(Vm^2)))

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Power Factor using Area of X-Section (1-Phase 2-Wire US)?

Power Factor using Area of X-Section (1-Phase 2-Wire US) calculator uses Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))) to calculate the Power Factor, The Power Factor using Area of X-Section (1-Phase 2-Wire US) formula is defined as the cosine of the angle between the voltage phasor and current phasor in an AC circuit. Power Factor is denoted by PF symbol.

How to calculate Power Factor using Area of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Power Factor using Area of X-Section (1-Phase 2-Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (Ploss) & Maximum Voltage Underground AC (Vm) and hit the calculate button. Here is how the Power Factor using Area of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.028503 = sqrt(((4)*(300^2)*1.7E-05*24)/(1.28*2.67*(230^2))).

FAQ

What is Power Factor using Area of X-Section (1-Phase 2-Wire US)?
The Power Factor using Area of X-Section (1-Phase 2-Wire US) formula is defined as the cosine of the angle between the voltage phasor and current phasor in an AC circuit and is represented as PF = sqrt(((4)*(P^2)*ρ*L)/(A*Ploss*(Vm^2))) or Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Line Losses is defined as the total losses occurring in an Underground AC line when in use & Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
How to calculate Power Factor using Area of X-Section (1-Phase 2-Wire US)?
The Power Factor using Area of X-Section (1-Phase 2-Wire US) formula is defined as the cosine of the angle between the voltage phasor and current phasor in an AC circuit is calculated using Power Factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire)/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))). To calculate Power Factor using Area of X-Section (1-Phase 2-Wire US), you need Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (Ploss) & Maximum Voltage Underground AC (Vm). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire, Line Losses & Maximum Voltage Underground AC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Power Factor?
In this formula, Power Factor uses Power Transmitted, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire, Line Losses & Maximum Voltage Underground AC. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Power Factor = sqrt((2)*Constant Underground AC/Volume Of Conductor)
  • Power Factor = (sqrt(2)*Power Transmitted)/(Maximum Voltage Underground AC*Current Underground AC)
  • Power Factor = (2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)
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