Polar Moment of Inertia of Hollow Circular Shaft Solution

STEP 0: Pre-Calculation Summary
Formula Used
Polar Moment of Inertia of shaft = (pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32
Jshaft = (pi*(douter^(4)-dinner^(4)))/32
This formula uses 1 Constants, 3 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Polar Moment of Inertia of shaft - (Measured in Meter⁴) - Polar Moment of Inertia of shaft is the measure of object resistance to torsion.
Outer Diameter of Shaft - (Measured in Meter) - Outer Diameter of Shaft is defined as the length of the longest chord of the surface of the hollow circular shaft.
Inner Diameter of Shaft - (Measured in Meter) - The Inner Diameter of Shaft is defined as the length of the longest chord inside the hollow shaft.
STEP 1: Convert Input(s) to Base Unit
Outer Diameter of Shaft: 4000 Millimeter --> 4 Meter (Check conversion ​here)
Inner Diameter of Shaft: 1000 Millimeter --> 1 Meter (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Jshaft = (pi*(douter^(4)-dinner^(4)))/32 --> (pi*(4^(4)-1^(4)))/32
Evaluating ... ...
Jshaft = 25.0345664582937
STEP 3: Convert Result to Output's Unit
25.0345664582937 Meter⁴ --> No Conversion Required
FINAL ANSWER
25.0345664582937 25.03457 Meter⁴ <-- Polar Moment of Inertia of shaft
(Calculation completed in 00.004 seconds)

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Created by Kethavath Srinath
Osmania University (OU), Hyderabad
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National Institute Of Technology (NIT), Hamirpur
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Design of Hollow Shaft Calculators

Tensile Stress in Hollow Shaft when Subjected to Axial Force
​ Go Tensile Stress in Hollow Shaft = Axial Force on Hollow Shaft/(pi/4*(Outer Diameter of Hollow Shaft^2-Inner Diameter of Hollow Shaft^2))
Inner Diameter of Hollow Shaft given Ratio of Diameters
​ Go Inner Diameter of Hollow Shaft = Ratio of Inner to Outer Diameter of Hollow Shaft*Outer Diameter of Hollow Shaft
Ratio of Inner Diameter to Outer Diameter
​ Go Ratio of Inner to Outer Diameter of Hollow Shaft = Inner Diameter of Hollow Shaft/Outer Diameter of Hollow Shaft
Outer Diameter given Ratio of Diameters
​ Go Outer Diameter of Hollow Shaft = Inner Diameter of Hollow Shaft/Ratio of Inner to Outer Diameter of Hollow Shaft

Polar Moment of Inertia of Hollow Circular Shaft Formula

Polar Moment of Inertia of shaft = (pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32
Jshaft = (pi*(douter^(4)-dinner^(4)))/32

Define polar moment of inertia?

Polar Moment of Inertia is a measure of an object’s capacity to oppose or resist torsion when some amount of torque is applied to it on a specified axis. Torsion, on the other hand, is nothing but the twisting of an object due to an applied torque. Polar moment of inertia basically describes the cylindrical object’s (including its segments) resistance to torsional deformation when torque is applied in a plane that is parallel to the cross-section area or in a plane that is perpendicular to the object’s central axis.

How to Calculate Polar Moment of Inertia of Hollow Circular Shaft?

Polar Moment of Inertia of Hollow Circular Shaft calculator uses Polar Moment of Inertia of shaft = (pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32 to calculate the Polar Moment of Inertia of shaft, The Polar moment of inertia of hollow circular shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation. Polar Moment of Inertia of shaft is denoted by Jshaft symbol.

How to calculate Polar Moment of Inertia of Hollow Circular Shaft using this online calculator? To use this online calculator for Polar Moment of Inertia of Hollow Circular Shaft, enter Outer Diameter of Shaft (douter) & Inner Diameter of Shaft (dinner) and hit the calculate button. Here is how the Polar Moment of Inertia of Hollow Circular Shaft calculation can be explained with given input values -> 25.03457 = (pi*(4^(4)-1^(4)))/32.

FAQ

What is Polar Moment of Inertia of Hollow Circular Shaft?
The Polar moment of inertia of hollow circular shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation and is represented as Jshaft = (pi*(douter^(4)-dinner^(4)))/32 or Polar Moment of Inertia of shaft = (pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32. Outer Diameter of Shaft is defined as the length of the longest chord of the surface of the hollow circular shaft & The Inner Diameter of Shaft is defined as the length of the longest chord inside the hollow shaft.
How to calculate Polar Moment of Inertia of Hollow Circular Shaft?
The Polar moment of inertia of hollow circular shaft formula is a quantity used to describe resistance to torsional deformation, in cylindrical objects (or segments of the cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation is calculated using Polar Moment of Inertia of shaft = (pi*(Outer Diameter of Shaft^(4)-Inner Diameter of Shaft^(4)))/32. To calculate Polar Moment of Inertia of Hollow Circular Shaft, you need Outer Diameter of Shaft (douter) & Inner Diameter of Shaft (dinner). With our tool, you need to enter the respective value for Outer Diameter of Shaft & Inner Diameter of Shaft and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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