Polar moment of inertia of circular cross section Calculator

✖Diameter of circular section of shaft is the diameter of the circular cross-section of the specimen.ⓘ Diameter of circular section of shaft [d_c]

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✖Polar moment of inertia for circular section is the measure of the specimen's resistance to torsion.ⓘ Polar moment of inertia of circular cross section [J]

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Polar moment of inertia of circular cross section Solution

STEP 0: Pre-Calculation Summary

Formula Used

Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32
J = pi*(d_c^4)/32
This formula uses 1 Constants, 2 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Polar moment of inertia for circular section - (Measured in Meter⁴) - Polar moment of inertia for circular section is the measure of the specimen's resistance to torsion.
Diameter of circular section of shaft - (Measured in Meter) - Diameter of circular section of shaft is the diameter of the circular cross-section of the specimen.

STEP 1: Convert Input(s) to Base Unit

Diameter of circular section of shaft: 34 Millimeter --> 0.034 Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

J = pi*(d_c^4)/32 --> pi*(0.034^4)/32

Evaluating ... ...

J = 1.31194480010237E-07

STEP 3: Convert Result to Output's Unit

1.31194480010237E-07 Meter⁴ -->131194.480010237 Millimeter⁴ (Check conversion here)

FINAL ANSWER

131194.480010237 ≈ 131194.5 Millimeter⁴ <-- Polar moment of inertia for circular section

(Calculation completed in 00.004 seconds)

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Created by Vaibhav Malani

National Institute of Technology (NIT), Tiruchirapalli

Vaibhav Malani has created this Calculator and 600+ more calculators!

Verified by Chilvera Bhanu Teja

Institute of Aeronautical Engineering (IARE), Hyderabad

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< Design of Shaft for Torsional Moment Calculators

Angle of twist of shaft in radians given torque, length of shaft, polar moment of inertia

LaTeX Go Angle of twist of shaft = (Torsional moment on shaft*Length of Shaft)/(Polar moment of inertia for circular section*Modulus of Rigidity)

Torsional shear stress in shaft due to torsional moment

LaTeX Go Torsional shear stress in twisted shaft = Torsional moment on shaft*Radial Distance from Axis of Rotation/Polar moment of inertia for circular section

Polar moment of inertia of hollow circular cross-section

LaTeX Go Polar moment of inertia for circular section = pi*((Outer Diameter of Hollow Circular Section^4)-(Inner Diameter of Hollow Circular Section^4))/32

Polar moment of inertia of circular cross section

LaTeX Go Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32

Polar moment of inertia of circular cross section Formula

LaTeX Go

Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32
J = pi*(d_c^4)/32

What is polar moment of inertia?

The polar moment of inertia, also known as second polar moment of area, is a quantity used to describe resistance to torsional deformation (deflection), in cylindrical objects (or segments of cylindrical object) with an invariant cross-section and no significant warping or out-of-plane deformation.

How to Calculate Polar moment of inertia of circular cross section?

Polar moment of inertia of circular cross section calculator uses Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32 to calculate the Polar moment of inertia for circular section, The Polar moment of inertia of circular cross section formula basically describes the cylindrical object's (including its segments) resistance to torsional deformation when torque is applied in a plane that is parallel to the cross-section area or in a plane that is perpendicular to the object's central axis. Polar moment of inertia for circular section is denoted by J symbol.

How to calculate Polar moment of inertia of circular cross section using this online calculator? To use this online calculator for Polar moment of inertia of circular cross section, enter Diameter of circular section of shaft (d_c) and hit the calculate button. Here is how the Polar moment of inertia of circular cross section calculation can be explained with given input values -> 1.3E+17 = pi*(0.034^4)/32.

FAQ

What is Polar moment of inertia of circular cross section?

The Polar moment of inertia of circular cross section formula basically describes the cylindrical object's (including its segments) resistance to torsional deformation when torque is applied in a plane that is parallel to the cross-section area or in a plane that is perpendicular to the object's central axis and is represented as J = pi*(d_c^4)/32 or Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32. Diameter of circular section of shaft is the diameter of the circular cross-section of the specimen.

How to calculate Polar moment of inertia of circular cross section?

The Polar moment of inertia of circular cross section formula basically describes the cylindrical object's (including its segments) resistance to torsional deformation when torque is applied in a plane that is parallel to the cross-section area or in a plane that is perpendicular to the object's central axis is calculated using Polar moment of inertia for circular section = pi*(Diameter of circular section of shaft^4)/32. To calculate Polar moment of inertia of circular cross section, you need Diameter of circular section of shaft (d_c). With our tool, you need to enter the respective value for Diameter of circular section of shaft and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Polar moment of inertia for circular section?

In this formula, Polar moment of inertia for circular section uses Diameter of circular section of shaft. We can use 2 other way(s) to calculate the same, which is/are as follows -

Polar moment of inertia for circular section = pi*((Outer Diameter of Hollow Circular Section^4)-(Inner Diameter of Hollow Circular Section^4))/32
Polar moment of inertia for circular section = Torsional moment on shaft*Radial Distance from Axis of Rotation/Torsional shear stress in twisted shaft

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