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pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature Calculator

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✖The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1.ⓘ Normality of Solution 1 [N₁]			+10% -10%
✖The Volume of Solution 1 gives the volume of solution 1 in liters.ⓘ Volume of Solution 1 [V₁]			+10% -10%
✖The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2.ⓘ Normality of Solution 2 [N₂]			+10% -10%
✖The Volume of Solution 2 gives the volume of the solution 2 in liters.ⓘ Volume of Solution 2 [V₂]			+10% -10%

✖The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale.ⓘ pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature [pOH]

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pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature Solution

STEP 0: Pre-Calculation Summary

Formula Used

Negative Log of Hydroxyl Concentration = 14+log10((Normality of Solution 1*Volume of Solution 1-Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2))
pOH = 14+log10((N₁*V₁-N₂*V₂)/(V₁+V₂))
This formula uses 1 Functions, 5 Variables

Functions Used

log10 - The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function., log10(Number)

Variables Used

Negative Log of Hydroxyl Concentration - The Negative Log of Hydroxyl Concentration gives us the value of hydroxyl concentration on the pH scale.
Normality of Solution 1 - (Measured in Mole per Cubic Meter) - The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1.
Volume of Solution 1 - (Measured in Cubic Meter) - The Volume of Solution 1 gives the volume of solution 1 in liters.
Normality of Solution 2 - (Measured in Mole per Cubic Meter) - The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2.
Volume of Solution 2 - (Measured in Cubic Meter) - The Volume of Solution 2 gives the volume of the solution 2 in liters.

STEP 1: Convert Input(s) to Base Unit

Normality of Solution 1: 0.0008 Equivalents per Liter --> 0.8 Mole per Cubic Meter (Check conversion here)
Volume of Solution 1: 0.00025 Liter --> 2.5E-07 Cubic Meter (Check conversion here)
Normality of Solution 2: 0.0005 Equivalents per Liter --> 0.5 Mole per Cubic Meter (Check conversion here)
Volume of Solution 2: 0.0001 Liter --> 1E-07 Cubic Meter (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

pOH = 14+log10((N₁*V₁-N₂*V₂)/(V₁+V₂)) --> 14+log10((0.8*2.5E-07-0.5*1E-07)/(2.5E-07+1E-07))

Evaluating ... ...

pOH = 13.6320232147054

STEP 3: Convert Result to Output's Unit

13.6320232147054 --> No Conversion Required

FINAL ANSWER

13.6320232147054 ≈ 13.63202 <-- Negative Log of Hydroxyl Concentration

(Calculation completed in 00.004 seconds)

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< Acidity and pH Scale Calculators

pH given Concentration of Hydrogen Ion

LaTeX Go Negative Log of Hydronium Concentration = -log10(Concentration of Hydrogen Ion)

pH given Activity of Hydrogen Ion

LaTeX Go Negative Log of Hydronium Concentration = -log10(Activity of Hydrogen Ion)

Concentration of Hydrogen Ion given pH

LaTeX Go Concentration of Hydrogen Ion = 10^(-Negative Log of Hydronium Concentration)

Activity of Hydrogen Ion given pH

LaTeX Go Activity of Hydrogen Ion = 10^(-Negative Log of Hydronium Concentration)

pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature Formula

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What is pOH scale?

pOH is a measure of hydroxide ion (OH-) concentration. It is used to express the alkalinity of a solution. Aqueous solutions at 25 degrees Celsius with pOH less than 7 are alkaline, pOH greater than 7 is acidic and pOH equal to 7 is neutral. pOH ranges from 1 to 14.

How to Calculate pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature?

pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature calculator uses Negative Log of Hydroxyl Concentration = 14+log10((Normality of Solution 1*Volume of Solution 1-Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)) to calculate the Negative Log of Hydroxyl Concentration, pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature formula is defined as negative base-10 logarithm of concentration of hydroxyl ion of solution which is calculated using normality and volume of strong acid and strong base denoted as 1 and 2 respectively, where N2V2 is greater than N1V1 which means solution 2 is more basic than solution 1. Negative Log of Hydroxyl Concentration is denoted by pOH symbol.

How to calculate pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature using this online calculator? To use this online calculator for pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature, enter Normality of Solution 1 (N₁), Volume of Solution 1 (V₁), Normality of Solution 2 (N₂) & Volume of Solution 2 (V₂) and hit the calculate button. Here is how the pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature calculation can be explained with given input values -> 13.87506 = 14+log10((0.8*2.5E-07-0.5*1E-07)/(2.5E-07+1E-07)).

FAQ

What is pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature?

pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature formula is defined as negative base-10 logarithm of concentration of hydroxyl ion of solution which is calculated using normality and volume of strong acid and strong base denoted as 1 and 2 respectively, where N2V2 is greater than N1V1 which means solution 2 is more basic than solution 1 and is represented as pOH = 14+log10((N₁*V₁-N₂*V₂)/(V₁+V₂)) or Negative Log of Hydroxyl Concentration = 14+log10((Normality of Solution 1*Volume of Solution 1-Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)). The Normality of Solution 1 is described as the number of gram or mole equivalents of solution 1 present in one liter of solution 1, The Volume of Solution 1 gives the volume of solution 1 in liters, The Normality of Solution 2 is described as the number of gram or mole equivalents of solution 2 present in one liter of solution 2 & The Volume of Solution 2 gives the volume of the solution 2 in liters.

How to calculate pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature?

pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature formula is defined as negative base-10 logarithm of concentration of hydroxyl ion of solution which is calculated using normality and volume of strong acid and strong base denoted as 1 and 2 respectively, where N2V2 is greater than N1V1 which means solution 2 is more basic than solution 1 is calculated using Negative Log of Hydroxyl Concentration = 14+log10((Normality of Solution 1*Volume of Solution 1-Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2)). To calculate pOH of Mixture of Strong Acid and Strong Base when Solution is Basic in Nature, you need Normality of Solution 1 (N₁), Volume of Solution 1 (V₁), Normality of Solution 2 (N₂) & Volume of Solution 2 (V₂). With our tool, you need to enter the respective value for Normality of Solution 1, Volume of Solution 1, Normality of Solution 2 & Volume of Solution 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Negative Log of Hydroxyl Concentration?

In this formula, Negative Log of Hydroxyl Concentration uses Normality of Solution 1, Volume of Solution 1, Normality of Solution 2 & Volume of Solution 2. We can use 2 other way(s) to calculate the same, which is/are as follows -

Negative Log of Hydroxyl Concentration = -log10(Concentration of Hydroxyl Ion)
Negative Log of Hydroxyl Concentration = -log10((Normality of Solution 1*Volume of Solution 1+Normality of Solution 2*Volume of Solution 2)/(Volume of Solution 1+Volume of Solution 2))

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