Period of Flow given Energy through Hydraulic Turbines Solution

STEP 0: Pre-Calculation Summary
Formula Used
Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower)
Tw = ETurbines/(9.81*qflow*(HWater-hlocation)*η)
This formula uses 6 Variables
Variables Used
Time Period of Progressive Wave - (Measured in Second) - Time period of progressive wave is the time taken by a wave to complete one oscillation.
Energy through Hydraulic Turbines - (Measured in Joule) - Energy through Hydraulic Turbines describes the power generated by the turbine.
Rate of Flow - (Measured in Cubic Meter per Second) - Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.
Head of Water - (Measured in Meter) - Head of Water is defined as the height of water columns.
Head Loss due to Friction - (Measured in Meter) - The Head Loss due to Friction occurs due to the effect of the fluid's viscosity near the surface of the pipe or duct.
Efficiency of Hydropower - Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
STEP 1: Convert Input(s) to Base Unit
Energy through Hydraulic Turbines: 522.36 Newton Meter --> 522.36 Joule (Check conversion ​here)
Rate of Flow: 32 Cubic Meter per Second --> 32 Cubic Meter per Second No Conversion Required
Head of Water: 2.3 Meter --> 2.3 Meter No Conversion Required
Head Loss due to Friction: 1.5 Meter --> 1.5 Meter No Conversion Required
Efficiency of Hydropower: 0.8 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Tw = ETurbines/(9.81*qflow*(HWater-hlocation)*η) --> 522.36/(9.81*32*(2.3-1.5)*0.8)
Evaluating ... ...
Tw = 2.59998566513761
STEP 3: Convert Result to Output's Unit
2.59998566513761 Second --> No Conversion Required
FINAL ANSWER
2.59998566513761 2.599986 Second <-- Time Period of Progressive Wave
(Calculation completed in 00.004 seconds)

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Assessment of Available Power Calculators

Amount of Hydropower
​ LaTeX ​ Go Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000
Head Loss given Amount of Hydropower
​ LaTeX ​ Go Head Loss due to Friction = ((Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))-Head of Water)
Head given Amount of Hydropower
​ LaTeX ​ Go Head of Water = (Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))+Head Loss due to Friction
Efficiency of Hydropower Station given Amount of Hydropower
​ LaTeX ​ Go Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))

Period of Flow given Energy through Hydraulic Turbines Formula

​LaTeX ​Go
Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower)
Tw = ETurbines/(9.81*qflow*(HWater-hlocation)*η)

What is meant by Rate of Flow of Water?

The Flow rate of a liquid is a measure of the volume of liquid that moves in a certain amount of time. The flow rate depends on the area of the section.

How to Calculate Period of Flow given Energy through Hydraulic Turbines?

Period of Flow given Energy through Hydraulic Turbines calculator uses Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower) to calculate the Time Period of Progressive Wave, The Period of Flow given Energy through Hydraulic Turbines is defined as the time taken by complete cycle of wave to pass point. Time Period of Progressive Wave is denoted by Tw symbol.

How to calculate Period of Flow given Energy through Hydraulic Turbines using this online calculator? To use this online calculator for Period of Flow given Energy through Hydraulic Turbines, enter Energy through Hydraulic Turbines (ETurbines), Rate of Flow (qflow), Head of Water (HWater), Head Loss due to Friction (hlocation) & Efficiency of Hydropower (η) and hit the calculate button. Here is how the Period of Flow given Energy through Hydraulic Turbines calculation can be explained with given input values -> 2.681067 = 522.36/(9.81*32*(2.3-1.5)*0.8).

FAQ

What is Period of Flow given Energy through Hydraulic Turbines?
The Period of Flow given Energy through Hydraulic Turbines is defined as the time taken by complete cycle of wave to pass point and is represented as Tw = ETurbines/(9.81*qflow*(HWater-hlocation)*η) or Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower). Energy through Hydraulic Turbines describes the power generated by the turbine, Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc, Head of Water is defined as the height of water columns, The Head Loss due to Friction occurs due to the effect of the fluid's viscosity near the surface of the pipe or duct & Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
How to calculate Period of Flow given Energy through Hydraulic Turbines?
The Period of Flow given Energy through Hydraulic Turbines is defined as the time taken by complete cycle of wave to pass point is calculated using Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower). To calculate Period of Flow given Energy through Hydraulic Turbines, you need Energy through Hydraulic Turbines (ETurbines), Rate of Flow (qflow), Head of Water (HWater), Head Loss due to Friction (hlocation) & Efficiency of Hydropower (η). With our tool, you need to enter the respective value for Energy through Hydraulic Turbines, Rate of Flow, Head of Water, Head Loss due to Friction & Efficiency of Hydropower and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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