Perimeter of Octagon given Short Diagonal Calculator

✖The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.ⓘ Short Diagonal of Octagon [d_Short]

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✖The Perimeter of Octagon is the total length of all the boundary lines of the Regular Octagon.ⓘ Perimeter of Octagon given Short Diagonal [P]

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Perimeter of Octagon given Short Diagonal Solution

STEP 0: Pre-Calculation Summary

Formula Used

Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2))
P = (8*d_Short)/sqrt(2+sqrt(2))
This formula uses 1 Functions, 2 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Perimeter of Octagon - (Measured in Meter) - The Perimeter of Octagon is the total length of all the boundary lines of the Regular Octagon.
Short Diagonal of Octagon - (Measured in Meter) - The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.

STEP 1: Convert Input(s) to Base Unit

Short Diagonal of Octagon: 18 Meter --> 18 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P = (8*d_Short)/sqrt(2+sqrt(2)) --> (8*18)/sqrt(2+sqrt(2))

Evaluating ... ...

P = 77.9322384210524

STEP 3: Convert Result to Output's Unit

77.9322384210524 Meter --> No Conversion Required

FINAL ANSWER

77.9322384210524 ≈ 77.93224 Meter <-- Perimeter of Octagon

(Calculation completed in 00.020 seconds)

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Created by Mona Gladys

St Joseph's College (SJC), Bengaluru

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Verified by Shweta Patil

Walchand College of Engineering (WCE), Sangli

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< Perimeter of Octagon Calculators

Perimeter of Octagon given Long Diagonal

LaTeX Go Perimeter of Octagon = (8*Long Diagonal of Octagon)/sqrt(4+(2*sqrt(2)))

Perimeter of Octagon given Short Diagonal

LaTeX Go Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2))

Perimeter of Octagon given Medium Diagonal

LaTeX Go Perimeter of Octagon = (8*Medium Diagonal of Octagon)/(1+sqrt(2))

Perimeter of Octagon

LaTeX Go Perimeter of Octagon = 8*Edge Length of Octagon

Perimeter of Octagon given Short Diagonal Formula

LaTeX Go

Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2))
P = (8*d_Short)/sqrt(2+sqrt(2))

What is an Octagon?

Octagon is a polygon in geometry, which has 8 sides and 8 angles. That means the number of vertices is 8 and the number of edges is 8. All the sides are joined with each other end-to-end to form a shape. These sides are in a straight line form; they are not curved or disjoint with each other. Each interior angle of a regular octagon is 135° and each exterior angle will be 45°.

How to Calculate Perimeter of Octagon given Short Diagonal?

Perimeter of Octagon given Short Diagonal calculator uses Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2)) to calculate the Perimeter of Octagon, The Perimeter of Octagon given Short Diagonal formula is defined as the total length of all the boundary lines of the Regular Octagon and calculated using the short diagonal of the Octagon. Perimeter of Octagon is denoted by P symbol.

How to calculate Perimeter of Octagon given Short Diagonal using this online calculator? To use this online calculator for Perimeter of Octagon given Short Diagonal, enter Short Diagonal of Octagon (d_Short) and hit the calculate button. Here is how the Perimeter of Octagon given Short Diagonal calculation can be explained with given input values -> 77.93224 = (8*18)/sqrt(2+sqrt(2)).

FAQ

What is Perimeter of Octagon given Short Diagonal?

The Perimeter of Octagon given Short Diagonal formula is defined as the total length of all the boundary lines of the Regular Octagon and calculated using the short diagonal of the Octagon and is represented as P = (8*d_Short)/sqrt(2+sqrt(2)) or Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2)). The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.

How to calculate Perimeter of Octagon given Short Diagonal?

The Perimeter of Octagon given Short Diagonal formula is defined as the total length of all the boundary lines of the Regular Octagon and calculated using the short diagonal of the Octagon is calculated using Perimeter of Octagon = (8*Short Diagonal of Octagon)/sqrt(2+sqrt(2)). To calculate Perimeter of Octagon given Short Diagonal, you need Short Diagonal of Octagon (d_Short). With our tool, you need to enter the respective value for Short Diagonal of Octagon and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Perimeter of Octagon?

In this formula, Perimeter of Octagon uses Short Diagonal of Octagon. We can use 3 other way(s) to calculate the same, which is/are as follows -

Perimeter of Octagon = 8*Edge Length of Octagon
Perimeter of Octagon = (8*Long Diagonal of Octagon)/sqrt(4+(2*sqrt(2)))
Perimeter of Octagon = (8*Medium Diagonal of Octagon)/(1+sqrt(2))

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