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Percent Enantiomeric Excess Considering Amount of Enantiomer Calculator

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Optical Activity Isomerism

✖Moles of R is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.ⓘ Moles of R [R]			+10% -10%
✖Moles of S is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.ⓘ Moles of S [S]			+10% -10%

✖Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other.ⓘ Percent Enantiomeric Excess Considering Amount of Enantiomer [%ee]

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Percent Enantiomeric Excess Considering Amount of Enantiomer Solution

STEP 0: Pre-Calculation Summary

Formula Used

Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100
%ee = (abs(R-S)/(R+S))*100
This formula uses 1 Functions, 3 Variables

Functions Used

abs - The absolute value of a number is its distance from zero on the number line. It's always a positive value, as it represents the magnitude of a number without considering its direction., abs(Number)

Variables Used

Percent Enantiomeric Excess - Percent Enantiomeric Excess is a measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other.
Moles of R - (Measured in Mole) - Moles of R is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.
Moles of S - (Measured in Mole) - Moles of S is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.

STEP 1: Convert Input(s) to Base Unit

Moles of R: 12.8 Mole --> 12.8 Mole No Conversion Required
Moles of S: 5.6 Mole --> 5.6 Mole No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

%ee = (abs(R-S)/(R+S))*100 --> (abs(12.8-5.6)/(12.8+5.6))*100

Evaluating ... ...

%ee = 39.1304347826087

STEP 3: Convert Result to Output's Unit

39.1304347826087 --> No Conversion Required

FINAL ANSWER

39.1304347826087 ≈ 39.13043 <-- Percent Enantiomeric Excess

(Calculation completed in 00.004 seconds)

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< Optical Activity Calculators

Specific Rotation of Optically Active Compound

LaTeX Go Specific Rotation = Observed Rotation/(Length Of Sample Tube*Concentration of Solution in Polarimeter)

Percent Enantiomeric Excess

LaTeX Go Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100

Enantiomeric Excess

LaTeX Go Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)

Optical Purity

LaTeX Go Optical Purity = (Observed Specific Rotation/Maximum Specific Rotation)*100

Percent Enantiomeric Excess Considering Amount of Enantiomer Formula

LaTeX Go

Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100
%ee = (abs(R-S)/(R+S))*100

What are R and S?

To name the enantiomers of a compound unambiguously, their names must include the "handedness" of the molecule. The method for this is formally known as R/S nomenclature. The letters "R" and "S" are determined by applying the Cahn-Ingold-Prelog (CIP) rules. The optical activity (+/-) can also be communicated in the name, but must be empirically derived.

How to Calculate Percent Enantiomeric Excess Considering Amount of Enantiomer?

Percent Enantiomeric Excess Considering Amount of Enantiomer calculator uses Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100 to calculate the Percent Enantiomeric Excess, The Percent Enantiomeric Excess Considering Amount of Enantiomer formula is defined as measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other. Percent Enantiomeric Excess is denoted by %ee symbol.

How to calculate Percent Enantiomeric Excess Considering Amount of Enantiomer using this online calculator? To use this online calculator for Percent Enantiomeric Excess Considering Amount of Enantiomer, enter Moles of R (R) & Moles of S (S) and hit the calculate button. Here is how the Percent Enantiomeric Excess Considering Amount of Enantiomer calculation can be explained with given input values -> 45.45455 = (abs(12.8-5.6)/(12.8+5.6))*100.

FAQ

What is Percent Enantiomeric Excess Considering Amount of Enantiomer?

The Percent Enantiomeric Excess Considering Amount of Enantiomer formula is defined as measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other and is represented as %ee = (abs(R-S)/(R+S))*100 or Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100. Moles of R is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance & Moles of S is the unit of measurement for amount of substance, a quantity proportional to the number of elementary entities of a substance.

How to calculate Percent Enantiomeric Excess Considering Amount of Enantiomer?

The Percent Enantiomeric Excess Considering Amount of Enantiomer formula is defined as measurement of purity used for chiral substances. It reflects the percent to which a sample contains one enantiomer in greater amounts than the other is calculated using Percent Enantiomeric Excess = (abs(Moles of R-Moles of S)/(Moles of R+Moles of S))*100. To calculate Percent Enantiomeric Excess Considering Amount of Enantiomer, you need Moles of R (R) & Moles of S (S). With our tool, you need to enter the respective value for Moles of R & Moles of S and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Percent Enantiomeric Excess?

In this formula, Percent Enantiomeric Excess uses Moles of R & Moles of S. We can use 1 other way(s) to calculate the same, which is/are as follows -

Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100

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