Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load Calculator

✖Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit.ⓘ Peak Input Voltage SP [V_(max)]			+10% -10%
✖Angular Frequency refers to the angular displacement per unit of time in a rectifier circuit.ⓘ Angular Frequency [ω]			+10% -10%
✖Inductance is the tendency of an electric conductor to oppose a change in the electric current flowing through it.ⓘ Inductance [L]			+10% -10%

✖Peak load current is defined as the root mean square value of the output current.ⓘ Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load [I_max]

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Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load Solution

STEP 0: Pre-Calculation Summary

Formula Used

Peak Load Current = (2*Peak Input Voltage SP)/(Angular Frequency*Inductance)
I_max = (2*V_(max))/(ω*L)
This formula uses 4 Variables

Variables Used

Peak Load Current - (Measured in Ampere) - Peak load current is defined as the root mean square value of the output current.
Peak Input Voltage SP - (Measured in Volt) - Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit.
Angular Frequency - (Measured in Radian per Second) - Angular Frequency refers to the angular displacement per unit of time in a rectifier circuit.
Inductance - (Measured in Henry) - Inductance is the tendency of an electric conductor to oppose a change in the electric current flowing through it.

STEP 1: Convert Input(s) to Base Unit

Peak Input Voltage SP: 221 Volt --> 221 Volt No Conversion Required
Angular Frequency: 30 Radian per Second --> 30 Radian per Second No Conversion Required
Inductance: 3.0378 Henry --> 3.0378 Henry No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

I_max = (2*V_(max))/(ω*L) --> (2*221)/(30*3.0378)

Evaluating ... ...

I_max = 4.85000109728532

STEP 3: Convert Result to Output's Unit

4.85000109728532 Ampere --> No Conversion Required

FINAL ANSWER

4.85000109728532 ≈ 4.850001 Ampere <-- Peak Load Current

(Calculation completed in 00.020 seconds)

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Created by Parminder Singh

Chandigarh University (CU), Punjab

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< Half Wave Calculators

Average Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go Average Load Current SP = Peak Input Voltage SP/(pi*Resistance SP)

RMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go RMS Load Current SP = Peak Input Voltage SP/(2*Resistance SP)

Average Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go Average Output Voltage Half = Peak Input Voltage SP/pi

RMS Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go RMS Output Voltage Half = Peak Input Voltage SP/2

Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load Formula

LaTeX Go

Peak Load Current = (2*Peak Input Voltage SP)/(Angular Frequency*Inductance)
I_max = (2*V_(max))/(ω*L)

Do half wave rectifier with inductive load conducts for full input wave?

Yes, for positive half cycle diode is conducting so input voltage and output voltage is equal because of parallel to each other in same circuit, hence the inductor stores the energy during the positive half of input and during negative half it starts discharging and then rectifier starts conducting again but it is due to the inductor and not the negative half of input.

How to Calculate Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load?

Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load calculator uses Peak Load Current = (2*Peak Input Voltage SP)/(Angular Frequency*Inductance) to calculate the Peak Load Current, The Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load formula is defined as the maximum value that the alternating load current can acquire when the load is inductive in nature. Peak Load Current is denoted by I_max symbol.

How to calculate Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load using this online calculator? To use this online calculator for Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load, enter Peak Input Voltage SP (V_(max)), Angular Frequency (ω) & Inductance (L) and hit the calculate button. Here is how the Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load calculation can be explained with given input values -> 4.850001 = (2*221)/(30*3.0378).

FAQ

What is Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load?

The Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load formula is defined as the maximum value that the alternating load current can acquire when the load is inductive in nature and is represented as I_max = (2*V_(max))/(ω*L) or Peak Load Current = (2*Peak Input Voltage SP)/(Angular Frequency*Inductance). Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit, Angular Frequency refers to the angular displacement per unit of time in a rectifier circuit & Inductance is the tendency of an electric conductor to oppose a change in the electric current flowing through it.

How to calculate Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load?

The Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load formula is defined as the maximum value that the alternating load current can acquire when the load is inductive in nature is calculated using Peak Load Current = (2*Peak Input Voltage SP)/(Angular Frequency*Inductance). To calculate Peak Load Current in Single Phase Half Wave Diode Rectifier with Inductive Load, you need Peak Input Voltage SP (V_(max)), Angular Frequency (ω) & Inductance (L). With our tool, you need to enter the respective value for Peak Input Voltage SP, Angular Frequency & Inductance and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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