Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 Solution

STEP 0: Pre-Calculation Summary
Formula Used
Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3)
Qpd = 37.4*A^(3/4)*Sm^(2/3)
This formula uses 3 Variables
Variables Used
Peak discharge of a D-h Unit hydrograph - (Measured in Cubic Meter per Second) - Peak discharge of a D-h Unit hydrograph is the maximum volume flow rate displays in a unit hydrograph.
Area of Catchment - (Measured in Square Meter) - Area of Catchment is the geographical area from which water flows into a particular point, such as a well, stream, or reservoir.
Weighted Mean Slope - Weighted Mean Slope derived for peak discharge is calculated by multiplying the weight (or probability) associated with a particular event or outcome.
STEP 1: Convert Input(s) to Base Unit
Area of Catchment: 3 Square Kilometer --> 3000000 Square Meter (Check conversion ​here)
Weighted Mean Slope: 0.010471 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Qpd = 37.4*A^(3/4)*Sm^(2/3) --> 37.4*3000000^(3/4)*0.010471^(2/3)
Evaluating ... ...
Qpd = 129034.145348582
STEP 3: Convert Result to Output's Unit
129034.145348582 Cubic Meter per Second --> No Conversion Required
FINAL ANSWER
129034.145348582 129034.1 Cubic Meter per Second <-- Peak discharge of a D-h Unit hydrograph
(Calculation completed in 00.020 seconds)

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The Indian Practice Calculators

Weighted Mean Slope given Peak Discharge of D-h Unit Hydrograph
​ LaTeX ​ Go Weighted Mean Slope = (Peak discharge of a D-h Unit hydrograph/(37.4*Area of Catchment^(3/4)))^(3/2)
Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028
​ LaTeX ​ Go Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3)
Catchment Area given Peak Discharge of D-h Unit Hydrograph
​ LaTeX ​ Go Area of Catchment = (Peak discharge of a D-h Unit hydrograph/1.79)^(4/3)
Peak Discharge of D-h Unit Hydrograph
​ LaTeX ​ Go Peak discharge of a D-h Unit hydrograph = 1.79*Area of Catchment^(3/4)

Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 Formula

​LaTeX ​Go
Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3)
Qpd = 37.4*A^(3/4)*Sm^(2/3)

What is Basin lag?

Basin lag time, defined as the elapsed time between the occurrences of the centroids of the effective rainfall. and of the storm runoff hydrograph, is an important factor in determining the time to peak of the unit. hydrograph and the intensity of peak discharge.

What is D-h Unit Hydrograph?

The unit hydrograph represents the lumped response of the catchment to a unit rainfall excess of D-h duration to produce a direct runoff hydrograph. It relates only the direct runoff to rainfall excess. Hence the volume of water contained in the unit hydrograph must be equal to the rainfall excess.

How to Calculate Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028?

Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 calculator uses Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3) to calculate the Peak discharge of a D-h Unit hydrograph, The Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 formula is defined as the maximum volume flow rate passing a particular location during a storm event, for the Indian Practice. Peak discharge of a D-h Unit hydrograph is denoted by Qpd symbol.

How to calculate Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 using this online calculator? To use this online calculator for Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028, enter Area of Catchment (A) & Weighted Mean Slope (Sm) and hit the calculate button. Here is how the Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 calculation can be explained with given input values -> 129034.1 = 37.4*3000000^(3/4)*0.010471^(2/3).

FAQ

What is Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028?
The Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 formula is defined as the maximum volume flow rate passing a particular location during a storm event, for the Indian Practice and is represented as Qpd = 37.4*A^(3/4)*Sm^(2/3) or Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3). Area of Catchment is the geographical area from which water flows into a particular point, such as a well, stream, or reservoir & Weighted Mean Slope derived for peak discharge is calculated by multiplying the weight (or probability) associated with a particular event or outcome.
How to calculate Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028?
The Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028 formula is defined as the maximum volume flow rate passing a particular location during a storm event, for the Indian Practice is calculated using Peak discharge of a D-h Unit hydrograph = 37.4*Area of Catchment^(3/4)*Weighted Mean Slope^(2/3). To calculate Peak Discharge of D-h Unit Hydrograph for Weighted Mean Slope Lesser than 0.0028, you need Area of Catchment (A) & Weighted Mean Slope (Sm). With our tool, you need to enter the respective value for Area of Catchment & Weighted Mean Slope and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Peak discharge of a D-h Unit hydrograph?
In this formula, Peak discharge of a D-h Unit hydrograph uses Area of Catchment & Weighted Mean Slope. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Peak discharge of a D-h Unit hydrograph = 1.79*Area of Catchment^(3/4)
  • Peak discharge of a D-h Unit hydrograph = (Area of Catchment)*(1.56/Lag Time of a 1-h Unit Hydrograph)^(1/0.9)
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