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Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid Calculator

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✖The Weight of Liquid A in a mixture of immiscible liquids.ⓘ Weight of Liquid A [W_A]			+10% -10%
✖The Molecular Mass of Liquid B in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid B [M_B]			+10% -10%
✖Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.ⓘ Vapor Pressure of Pure Component B [P_B°]			+10% -10%
✖The Molecular Mass of Liquid A in a mixture of immiscible liquids.ⓘ Molecular Mass of Liquid A [M_A]			+10% -10%
✖The Weight of Liquid B in a mixture of immiscible liquids.ⓘ Weight of Liquid B [W_B]			+10% -10%

✖Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.ⓘ Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid [P_A°]

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Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid Solution

STEP 0: Pre-Calculation Summary

Formula Used

Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)
P_A° = (W_A*M_B*P_B°)/(M_A*W_B)
This formula uses 6 Variables

Variables Used

Vapor Pressure of Pure Component A - (Measured in Pascal) - Vapor Pressure of Pure Component A is the pressure exerted by a liquid or solid molecules of only A in a closed system in which they are in equilibrium with the vapour phase.
Weight of Liquid A - (Measured in Kilogram) - The Weight of Liquid A in a mixture of immiscible liquids.
Molecular Mass of Liquid B - (Measured in Kilogram) - The Molecular Mass of Liquid B in a mixture of immiscible liquids.
Vapor Pressure of Pure Component B - (Measured in Pascal) - Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase.
Molecular Mass of Liquid A - (Measured in Kilogram) - The Molecular Mass of Liquid A in a mixture of immiscible liquids.
Weight of Liquid B - (Measured in Kilogram) - The Weight of Liquid B in a mixture of immiscible liquids.

STEP 1: Convert Input(s) to Base Unit

Weight of Liquid A: 0.5 Gram --> 0.0005 Kilogram (Check conversion here)
Molecular Mass of Liquid B: 31.8 Gram --> 0.0318 Kilogram (Check conversion here)
Vapor Pressure of Pure Component B: 0.25 Pascal --> 0.25 Pascal No Conversion Required
Molecular Mass of Liquid A: 14.72 Gram --> 0.01472 Kilogram (Check conversion here)
Weight of Liquid B: 0.1 Gram --> 0.0001 Kilogram (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_A° = (W_A*M_B*P_B°)/(M_A*W_B) --> (0.0005*0.0318*0.25)/(0.01472*0.0001)

Evaluating ... ...

P_A° = 2.70040760869565

STEP 3: Convert Result to Output's Unit

2.70040760869565 Pascal --> No Conversion Required

FINAL ANSWER

2.70040760869565 ≈ 2.700408 Pascal <-- Vapor Pressure of Pure Component A

(Calculation completed in 00.004 seconds)

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< Immiscible Liquids Calculators

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid

LaTeX Go Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B)

Ratio of Partial Vapour Pressures of 2 Immiscible Liquids given Weight and Molecular Mass

LaTeX Go Ratio of Partial Pressures of 2 Immiscible Liquids = (Weight of Liquid A*Molecular Mass of Liquid B)/(Weight of Liquid B*Molecular Mass of Liquid A)

Total Pressure of Mixture of Two Immiscible Liquids

LaTeX Go Total Pressure of Mixture of Immiscible Liquids = Vapor Pressure of Pure Component A+Vapor Pressure of Pure Component B

Ratio of Partial Pressure of 2 Immiscible Liquids given Number of Moles

LaTeX Go Ratio of Partial Pressures of 2 Immiscible Liquids = Number of Moles of Liquid A/Number of Moles of Liquid B

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid Formula

LaTeX Go

How does both liquids contribute to pressure of a mixture of 2 immiscible liquids?

Obviously if you have two immiscible liquids in a closed flask and keep everything still, the vapor pressure you measure will simply be the vapor pressure of the one which is floating on top. There is no way that the bottom liquid can turn to vapor. The top one is sealing it in. For the purposes of the rest of this topic, we always assume that the mixture is being stirred or agitated in some way so that the two liquids are broken up into drops. At any one time there will be drops of both liquids on the surface. That means that both of them contribute to the overall vapor pressure of the mixture.

How to Calculate Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid?

Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid calculator uses Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B) to calculate the Vapor Pressure of Pure Component A, The Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid considering A as unknown parameter and B as known parameter. Vapor Pressure of Pure Component A is denoted by P_A° symbol.

How to calculate Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid using this online calculator? To use this online calculator for Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid, enter Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Vapor Pressure of Pure Component B (P_B°), Molecular Mass of Liquid A (M_A) & Weight of Liquid B (W_B) and hit the calculate button. Here is how the Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid calculation can be explained with given input values -> 2.700408 = (0.0005*0.0318*0.25)/(0.01472*0.0001).

FAQ

What is Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid?

The Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid considering A as unknown parameter and B as known parameter and is represented as P_A° = (W_A*M_B*P_B°)/(M_A*W_B) or Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B). The Weight of Liquid A in a mixture of immiscible liquids, The Molecular Mass of Liquid B in a mixture of immiscible liquids, Vapor Pressure of Pure Component B is the pressure exerted by a liquid or solid molecules of only B in a closed system in which they are in equilibrium with the vapour phase, The Molecular Mass of Liquid A in a mixture of immiscible liquids & The Weight of Liquid B in a mixture of immiscible liquids.

How to calculate Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid?

The Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid considering A as unknown parameter and B as known parameter is calculated using Vapor Pressure of Pure Component A = (Weight of Liquid A*Molecular Mass of Liquid B*Vapor Pressure of Pure Component B)/(Molecular Mass of Liquid A*Weight of Liquid B). To calculate Partial Vapour Pressure of Immiscible Liquid given Partial Pressure of other Liquid, you need Weight of Liquid A (W_A), Molecular Mass of Liquid B (M_B), Vapor Pressure of Pure Component B (P_B°), Molecular Mass of Liquid A (M_A) & Weight of Liquid B (W_B). With our tool, you need to enter the respective value for Weight of Liquid A, Molecular Mass of Liquid B, Vapor Pressure of Pure Component B, Molecular Mass of Liquid A & Weight of Liquid B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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