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Osmotic Pressure given Relative Lowering of Vapour Pressure Calculator

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✖The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.ⓘ Relative Lowering of Vapour Pressure [Δp]			+10% -10%
✖Temperature is the degree or intensity of heat present in a substance or object.ⓘ Temperature [T]			+10% -10%
✖Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.ⓘ Molar Volume [V_m]			+10% -10%

✖The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.ⓘ Osmotic Pressure given Relative Lowering of Vapour Pressure [π]

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Osmotic Pressure given Relative Lowering of Vapour Pressure Solution

STEP 0: Pre-Calculation Summary

Formula Used

Osmotic Pressure = (Relative Lowering of Vapour Pressure*[R]*Temperature)/Molar Volume
π = (Δp*[R]*T)/V_m
This formula uses 1 Constants, 4 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Osmotic Pressure - (Measured in Pascal) - The Osmotic Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.
Relative Lowering of Vapour Pressure - The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute.
Temperature - (Measured in Kelvin) - Temperature is the degree or intensity of heat present in a substance or object.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.

STEP 1: Convert Input(s) to Base Unit

Relative Lowering of Vapour Pressure: 0.052 --> No Conversion Required
Temperature: 298 Kelvin --> 298 Kelvin No Conversion Required
Molar Volume: 51.6 Cubic Meter per Mole --> 51.6 Cubic Meter per Mole No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

π = (Δp*[R]*T)/V_m --> (0.052*[R]*298)/51.6

Evaluating ... ...

π = 2.49691691338959

STEP 3: Convert Result to Output's Unit

2.49691691338959 Pascal --> No Conversion Required

FINAL ANSWER

2.49691691338959 ≈ 2.496917 Pascal <-- Osmotic Pressure

(Calculation completed in 00.020 seconds)

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< Osmotic Pressure Calculators

Osmotic Pressure given Volume and Osmotic Pressure of Two Substances

LaTeX Go Osmotic Pressure = ((Osmotic Pressure of Particle 1*Volume of Particle 1)+(Osmotic Pressure of Particle 2*Volume of Particle 2))/([R]*Temperature)

Moles of Solute given Osmotic Pressure

LaTeX Go Number of Moles of Solute = (Osmotic Pressure*Volume of Solution)/([R]*Temperature)

Density of Solution given Osmotic Pressure

LaTeX Go Density of Solution = Osmotic Pressure/([g]*Equilibrium Height)

Equilibrium Height given Osmotic Pressure

LaTeX Go Equilibrium Height = Osmotic Pressure/([g]*Density of Solution)

< Important Formulas of Colligative Properties Calculators

Osmotic Pressure given Depression in Freezing Point

LaTeX Go Osmotic Pressure = (Molar Enthalpy of Fusion*Depression in Freezing Point*Temperature)/(Molar Volume*(Solvent Freezing Point^2))

Osmotic Pressure given Concentration of Two Substances

LaTeX Go Osmotic Pressure = (Concentration of Particle 1+Concentration of Particle 2)*[R]*Temperature

Osmotic Pressure for Non Electrolyte

LaTeX Go Osmotic Pressure = Molar Concentration of Solute*[R]*Temperature

Osmotic Pressure given Density of Solution

LaTeX Go Osmotic Pressure = Density of Solution*[g]*Equilibrium Height

Osmotic Pressure given Relative Lowering of Vapour Pressure Formula

LaTeX Go

Osmotic Pressure = (Relative Lowering of Vapour Pressure*[R]*Temperature)/Molar Volume
π = (Δp*[R]*T)/V_m

Why osmotic pressure is important?

Osmotic pressure is of vital importance in biology as the cell's membrane is selective toward many of the solutes found in living organisms. When a cell is placed in a hypertonic solution, water actually flows out of the cell into the surrounding solution thereby causing the cells to shrink and lose its turgidity.

How to Calculate Osmotic Pressure given Relative Lowering of Vapour Pressure?

Osmotic Pressure given Relative Lowering of Vapour Pressure calculator uses Osmotic Pressure = (Relative Lowering of Vapour Pressure*[R]*Temperature)/Molar Volume to calculate the Osmotic Pressure, The Osmotic Pressure given Relative Lowering of Vapour Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in pure solvent by osmosis. Osmotic Pressure is denoted by π symbol.

How to calculate Osmotic Pressure given Relative Lowering of Vapour Pressure using this online calculator? To use this online calculator for Osmotic Pressure given Relative Lowering of Vapour Pressure, enter Relative Lowering of Vapour Pressure (Δp), Temperature (T) & Molar Volume (V_m) and hit the calculate button. Here is how the Osmotic Pressure given Relative Lowering of Vapour Pressure calculation can be explained with given input values -> 7.202645 = (0.052*[R]*298)/51.6.

FAQ

What is Osmotic Pressure given Relative Lowering of Vapour Pressure?

The Osmotic Pressure given Relative Lowering of Vapour Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in pure solvent by osmosis and is represented as π = (Δp*[R]*T)/V_m or Osmotic Pressure = (Relative Lowering of Vapour Pressure*[R]*Temperature)/Molar Volume. The Relative Lowering of Vapour Pressure is the lowering of vapour pressure of pure solvent on addition of solute, Temperature is the degree or intensity of heat present in a substance or object & Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.

How to calculate Osmotic Pressure given Relative Lowering of Vapour Pressure?

The Osmotic Pressure given Relative Lowering of Vapour Pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in pure solvent by osmosis is calculated using Osmotic Pressure = (Relative Lowering of Vapour Pressure*[R]*Temperature)/Molar Volume. To calculate Osmotic Pressure given Relative Lowering of Vapour Pressure, you need Relative Lowering of Vapour Pressure (Δp), Temperature (T) & Molar Volume (V_m). With our tool, you need to enter the respective value for Relative Lowering of Vapour Pressure, Temperature & Molar Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Osmotic Pressure?

In this formula, Osmotic Pressure uses Relative Lowering of Vapour Pressure, Temperature & Molar Volume. We can use 3 other way(s) to calculate the same, which is/are as follows -

Osmotic Pressure = ((Osmotic Pressure of Particle 1*Volume of Particle 1)+(Osmotic Pressure of Particle 2*Volume of Particle 2))/([R]*Temperature)
Osmotic Pressure = (Number of Moles of Solute*[R]*Temperature)/Volume of Solution
Osmotic Pressure = (((Concentration of Particle 1*Volume of Particle 1)+(Concentration of Particle 2*Volume of Particle 2))*([R]*Temperature))/(Volume of Particle 1+Volume of Particle 2)

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