Moment of inertia of hollow circle about diametrical axis Calculator

✖Outer Diameter of Hollow Circular Section is the measure of largest diameter of 2D concentric circular cross section.ⓘ Outer Diameter of Hollow Circular Section [d_c]			+10% -10%
✖Inner Diameter of Hollow Circular Section is the measure of smallest diameter of a 2D concentric circular cross-section.ⓘ Inner Diameter of Hollow Circular Section [d_i]			+10% -10%

✖Moment of Inertia for Solids depends on their shapes and distributions of mass around their axis of rotation.ⓘ Moment of inertia of hollow circle about diametrical axis [I_s]

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Moment of inertia of hollow circle about diametrical axis Solution

STEP 0: Pre-Calculation Summary

Formula Used

Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4)
I_s = (pi/64)*(d_c^4-d_i^4)
This formula uses 1 Constants, 3 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Moment of Inertia for Solids - (Measured in Meter⁴) - Moment of Inertia for Solids depends on their shapes and distributions of mass around their axis of rotation.
Outer Diameter of Hollow Circular Section - (Measured in Meter) - Outer Diameter of Hollow Circular Section is the measure of largest diameter of 2D concentric circular cross section.
Inner Diameter of Hollow Circular Section - (Measured in Meter) - Inner Diameter of Hollow Circular Section is the measure of smallest diameter of a 2D concentric circular cross-section.

STEP 1: Convert Input(s) to Base Unit

Outer Diameter of Hollow Circular Section: 3.999 Meter --> 3.999 Meter No Conversion Required
Inner Diameter of Hollow Circular Section: 2.8 Meter --> 2.8 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

I_s = (pi/64)*(d_c^4-d_i^4) --> (pi/64)*(3.999^4-2.8^4)

Evaluating ... ...

I_s = 9.53662337084081

STEP 3: Convert Result to Output's Unit

9.53662337084081 Meter⁴ --> No Conversion Required

FINAL ANSWER

9.53662337084081 ≈ 9.536623 Meter⁴ <-- Moment of Inertia for Solids

(Calculation completed in 00.004 seconds)

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< Moment of Inertia in Solids Calculators

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Moment of inertia of rectangle about centroidal axis along y-y parallel to length

LaTeX Go Moment of Inertia about y-y axis = Length of Rectangular Section*(Breadth of Rectangular Section^3)/12

Moment of inertia of triangle about centroidal axis x-x parallel to base

LaTeX Go Moment of Inertia about x-x axis = (Base of Triangle*Height of Triangle^3)/36

Moment of inertia of hollow circle about diametrical axis Formula

LaTeX Go

Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4)
I_s = (pi/64)*(d_c^4-d_i^4)

What is moment of inertia?

Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

How to Calculate Moment of inertia of hollow circle about diametrical axis?

Moment of inertia of hollow circle about diametrical axis calculator uses Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4) to calculate the Moment of Inertia for Solids, Moment of inertia of hollow circle about diametrical axis formula is defined as the 1/64 times of product of Archimedes' constant (pi) and the difference of outer diameter power raised to 4, inner diameter power raised to 4. Moment of Inertia for Solids is denoted by I_s symbol.

How to calculate Moment of inertia of hollow circle about diametrical axis using this online calculator? To use this online calculator for Moment of inertia of hollow circle about diametrical axis, enter Outer Diameter of Hollow Circular Section (d_c) & Inner Diameter of Hollow Circular Section (d_i) and hit the calculate button. Here is how the Moment of inertia of hollow circle about diametrical axis calculation can be explained with given input values -> 9.549185 = (pi/64)*(3.999^4-2.8^4).

FAQ

What is Moment of inertia of hollow circle about diametrical axis?

Moment of inertia of hollow circle about diametrical axis formula is defined as the 1/64 times of product of Archimedes' constant (pi) and the difference of outer diameter power raised to 4, inner diameter power raised to 4 and is represented as I_s = (pi/64)*(d_c^4-d_i^4) or Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4). Outer Diameter of Hollow Circular Section is the measure of largest diameter of 2D concentric circular cross section & Inner Diameter of Hollow Circular Section is the measure of smallest diameter of a 2D concentric circular cross-section.

How to calculate Moment of inertia of hollow circle about diametrical axis?

Moment of inertia of hollow circle about diametrical axis formula is defined as the 1/64 times of product of Archimedes' constant (pi) and the difference of outer diameter power raised to 4, inner diameter power raised to 4 is calculated using Moment of Inertia for Solids = (pi/64)*(Outer Diameter of Hollow Circular Section^4-Inner Diameter of Hollow Circular Section^4). To calculate Moment of inertia of hollow circle about diametrical axis, you need Outer Diameter of Hollow Circular Section (d_c) & Inner Diameter of Hollow Circular Section (d_i). With our tool, you need to enter the respective value for Outer Diameter of Hollow Circular Section & Inner Diameter of Hollow Circular Section and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Moment of Inertia for Solids?

In this formula, Moment of Inertia for Solids uses Outer Diameter of Hollow Circular Section & Inner Diameter of Hollow Circular Section. We can use 2 other way(s) to calculate the same, which is/are as follows -

Moment of Inertia for Solids = 0.393*Radius of semi circle^4
Moment of Inertia for Solids = 0.11*Radius of semi circle^4

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