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Moles of Electron given Potentials Calculator

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✖Anodic Potential is defined as electrode potential were the metal ions will be pulled away the electrode.ⓘ Anodic Potential [E_pa]			+10% -10%
✖Cathodic Potential is defined as electrode potential were the metal ions will be pulled towards the electrode.ⓘ Cathodic Potential [E_pc]			+10% -10%

✖Moles of Electron is a unit of measurement that is the amount of a pure substance containing the same number of chemical units in carbon.ⓘ Moles of Electron given Potentials [m_e]

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Moles of Electron given Potentials

Formula

`"m"_{"e"} = 57/("E"_{"pa"}-"E"_{"pc"})`

Example

`"57"=57/("4.5"-"3.5V/m")`

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Moles of Electron given Potentials Solution

STEP 0: Pre-Calculation Summary

Formula Used

Moles of Electron = 57/(Anodic Potential-Cathodic Potential)
m_e = 57/(E_pa-E_pc)
This formula uses 3 Variables

Variables Used

Moles of Electron - Moles of Electron is a unit of measurement that is the amount of a pure substance containing the same number of chemical units in carbon.
Anodic Potential - Anodic Potential is defined as electrode potential were the metal ions will be pulled away the electrode.
Cathodic Potential - (Measured in Volt per Meter) - Cathodic Potential is defined as electrode potential were the metal ions will be pulled towards the electrode.

STEP 1: Convert Input(s) to Base Unit

Anodic Potential: 4.5 --> No Conversion Required
Cathodic Potential: 3.5 Volt per Meter --> 3.5 Volt per Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

m_e = 57/(E_pa-E_pc) --> 57/(4.5-3.5)

Evaluating ... ...

m_e = 57

STEP 3: Convert Result to Output's Unit

57 --> No Conversion Required

FINAL ANSWER

57 <-- Moles of Electron

(Calculation completed in 00.004 seconds)

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< 23 Potentiometry and Voltametry Calculators

Number of Electron given CI

Go Number of electrons given CI = (Cathodic Current/(2.69*(10^8)*Area of Electrode*Concentration given CI*(Diffusion Constant^0.5)*(Sweep Rate^0.5)))^(2/3)

Maximum Diffusion Current

Go Maximum Diffusion Current = 708*Moles of Analyte*(Diffusion Constant^(1/2))*(Rate of Flow of Mercury^(2/3))*(Drop Time^(1/6))*Concentration at given time

Area of Electrode

Go Area of Electrode = (Cathodic Current/(2.69*(10^8)*Number of electrons given CI*Concentration given CI*(Diffusion Constant^0.5)*(Sweep Rate^0.5)))^(2/3)

Concentration given CI

Go Concentration given CI = Cathodic Current/(2.69*(10^8)*(Number of electrons given CI^1.5)*Area of Electrode*(Diffusion Constant^0.5)*(Sweep Rate^0.5))

Cathodic Current

Go Cathodic Current = 2.69*(10^8)*(Number of electrons given CI^1.5)*Area of Electrode*Concentration given CI*(Diffusion Constant^0.5)*(Sweep Rate^0.5)

Diffusion Constant given Current

Go Diffusion Constant = (Cathodic Current/(2.69*(10^8)*Number of electrons given CI*Concentration given CI*(Sweep Rate^0.5)*Area of Electrode))^(4/3)

Sweep Rate

Go Sweep Rate = (Cathodic Current/(2.69*(10^8)*Number of electrons given CI*Concentration given CI*(Diffusion Constant^0.5)*Area of Electrode))^(4/3)

Current in Potentiometry

Go Current in Potentiometry = (Cell Potential in Potentiometry-Applied Potential in Potentiometry)/Resistance in Potentiometry

Applied Potential

Go Applied Potential in Potentiometry = Cell Potential in Potentiometry+(Current in Potentiometry*Resistance in Potentiometry)

EMF at Cell Junction

Go Junction EMF = Cell Potential in Potentiometry-Indicator EMF+Reference EMF

Cell Potential

Go Cell Potential in Potentiometry = Indicator EMF-Reference EMF+Junction EMF

Indicator EMF

Go Indicator EMF = Reference EMF-Junction EMF+Cell Potential in Potentiometry

Reference EMF

Go Reference EMF = Indicator EMF+Junction EMF-Cell Potential in Potentiometry

Number of Moles of Electron

Go Moles of Electron = Charge given Moles/(Moles of Analyte*[Faraday])

Moles of Analyte

Go Moles of Analyte = Charge given Moles/(Moles of Electron*[Faraday])

Charge given Moles

Go Charge given Moles = Moles of Electron*Moles of Analyte*[Faraday]

Potentiometric Current

Go Potentiometric Current = Potentiometric Constant*Concentration at given time

Moles of Electron given Potentials

Go Moles of Electron = 57/(Anodic Potential-Cathodic Potential)

Cathodic Potential

Go Cathodic Potential = Anodic Potential-(57/Moles of Electron)

Anodic Potential

Go Anodic Potential = Cathodic Potential+(57/Moles of Electron)

Cathodic Potential given half potential

Go Cathodic Potential = (Half Potential/0.5)-Anodic Potential

Anodic Potential given half potential

Go Anodic Potential = (Half Potential/0.5)-Cathodic Potential

Half Potential

Go Half Potential = 0.5*(Anodic Potential+Cathodic Potential)

Moles of Electron given Potentials Formula

Moles of Electron = 57/(Anodic Potential-Cathodic Potential)
m_e = 57/(E_pa-E_pc)

What is the principle of voltammetry?

Voltammetry is the study of the current response of a chemical under an applied potential difference. Voltammetry encompasses a number of different methods, each of which can tell us about the kinetics and thermodynamics of electron addition (reduction) and electron loss (oxidation).

How to Calculate Moles of Electron given Potentials?

Moles of Electron given Potentials calculator uses Moles of Electron = 57/(Anodic Potential-Cathodic Potential) to calculate the Moles of Electron, The Moles of Electron given Potentials formula is defined as the amount of a pure substance containing the same number of chemical units (atoms, molecules etc.) as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.022 X 1023). Moles of Electron is denoted by m_e symbol.

How to calculate Moles of Electron given Potentials using this online calculator? To use this online calculator for Moles of Electron given Potentials, enter Anodic Potential (E_pa) & Cathodic Potential (E_pc) and hit the calculate button. Here is how the Moles of Electron given Potentials calculation can be explained with given input values -> -28.5 = 57/(4.5-3.5).

FAQ

What is Moles of Electron given Potentials?

The Moles of Electron given Potentials formula is defined as the amount of a pure substance containing the same number of chemical units (atoms, molecules etc.) as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.022 X 1023) and is represented as m_e = 57/(E_pa-E_pc) or Moles of Electron = 57/(Anodic Potential-Cathodic Potential). Anodic Potential is defined as electrode potential were the metal ions will be pulled away the electrode & Cathodic Potential is defined as electrode potential were the metal ions will be pulled towards the electrode.

How to calculate Moles of Electron given Potentials?

The Moles of Electron given Potentials formula is defined as the amount of a pure substance containing the same number of chemical units (atoms, molecules etc.) as there are atoms in exactly 12 grams of carbon-12 (i.e., 6.022 X 1023) is calculated using Moles of Electron = 57/(Anodic Potential-Cathodic Potential). To calculate Moles of Electron given Potentials, you need Anodic Potential (E_pa) & Cathodic Potential (E_pc). With our tool, you need to enter the respective value for Anodic Potential & Cathodic Potential and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Moles of Electron?

In this formula, Moles of Electron uses Anodic Potential & Cathodic Potential. We can use 1 other way(s) to calculate the same, which is/are as follows -

Moles of Electron = Charge given Moles/(Moles of Analyte*[Faraday])

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