Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure Calculator

Chemistry Engineering Financial Health More >>

↳

Solution and Colligative properties Analytical chemistry Atmospheric Chemistry Atomic structure More >>

⤿

Relative Lowering of Vapour Pressure Clausius Clapeyron Equation Depression in Freezing Point Elevation in Boiling Point More >>

✖The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute.ⓘ Vapour Pressure of Pure Solvent [p_o]			+10% -10%
✖The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute.ⓘ Vapour Pressure of Solvent in Solution [p]			+10% -10%
✖Number of Moles of Solvent is the total number of representative particles present in the solvent.ⓘ Number of Moles of Solvent [N]			+10% -10%

✖The number of Moles of Solute is the total number of representative particles present in the solute.ⓘ Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure [n]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Solution and Colligative properties Formula PDF PDF Image

Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure Solution

STEP 0: Pre-Calculation Summary

Formula Used

Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent
n = ((p_o-p)*N)/p_o
This formula uses 4 Variables

Variables Used

Number of Moles of Solute - (Measured in Mole) - The number of Moles of Solute is the total number of representative particles present in the solute.
Vapour Pressure of Pure Solvent - (Measured in Pascal) - The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute.
Vapour Pressure of Solvent in Solution - (Measured in Pascal) - The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute.
Number of Moles of Solvent - (Measured in Mole) - Number of Moles of Solvent is the total number of representative particles present in the solvent.

STEP 1: Convert Input(s) to Base Unit

Vapour Pressure of Pure Solvent: 2000 Pascal --> 2000 Pascal No Conversion Required
Vapour Pressure of Solvent in Solution: 1895.86 Pascal --> 1895.86 Pascal No Conversion Required
Number of Moles of Solvent: 10 Mole --> 10 Mole No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

n = ((p_o-p)*N)/p_o --> ((2000-1895.86)*10)/2000

Evaluating ... ...

n = 0.5207

STEP 3: Convert Result to Output's Unit

0.5207 Mole --> No Conversion Required

FINAL ANSWER

0.5207 Mole <-- Number of Moles of Solute

(Calculation completed in 00.021 seconds)

You are here -

Home » Chemistry » Solution and Colligative properties » Relative Lowering of Vapour Pressure » Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure

Credits

Created by Prerana Bakli

University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA

Prerana Bakli has created this Calculator and 800+ more calculators!

Verified by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has verified this Calculator and 900+ more calculators!

< Relative Lowering of Vapour Pressure Calculators

Molecular Mass of Solvent given Relative Lowering of Vapour Pressure

LaTeX Go Molecular Mass Solvent = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molality*Vapour Pressure of Pure Solvent)

Relative Lowering of Vapour Pressure

LaTeX Go Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Mole Fraction of Solute given Vapour Pressure

LaTeX Go Mole Fraction of Solute = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Mole Fraction of Solvent given Vapour Pressure

LaTeX Go Mole Fraction of Solvent = Vapour Pressure of Solvent in Solution/Vapour Pressure of Pure Solvent

Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure Formula

LaTeX Go

Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent
n = ((p_o-p)*N)/p_o

What causes the Relative Lowering Of Vapour Pressure?

This lowering in vapour pressure is due to the fact that after the solute was added to the pure liquid (solvent), the liquid surface now had molecules of both, the pure liquid and the solute. The number of solvent molecules escaping into vapour phase gets reduced and as a result the pressure exerted by the vapour phase is also reduced. This is known as relative lowering of vapour pressure. This decrease in vapour pressure depends on the amount of non-volatile solute added in the solution irrespective of its nature and hence it is one of the colligative properties.

How to Calculate Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure?

Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure calculator uses Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent to calculate the Number of Moles of Solute, The Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure is the no. of moles of solute causing the colligative property of the solution. Number of Moles of Solute is denoted by n symbol.

How to calculate Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure using this online calculator? To use this online calculator for Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure, enter Vapour Pressure of Pure Solvent (p_o), Vapour Pressure of Solvent in Solution (p) & Number of Moles of Solvent (N) and hit the calculate button. Here is how the Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure calculation can be explained with given input values -> 0.5207 = ((2000-1895.86)*10)/2000.

FAQ

What is Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure?

The Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure is the no. of moles of solute causing the colligative property of the solution and is represented as n = ((p_o-p)*N)/p_o or Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent. The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute, The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute & Number of Moles of Solvent is the total number of representative particles present in the solvent.

How to calculate Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure?

The Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure is the no. of moles of solute causing the colligative property of the solution is calculated using Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent. To calculate Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure, you need Vapour Pressure of Pure Solvent (p_o), Vapour Pressure of Solvent in Solution (p) & Number of Moles of Solvent (N). With our tool, you need to enter the respective value for Vapour Pressure of Pure Solvent, Vapour Pressure of Solvent in Solution & Number of Moles of Solvent and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search