Molar Vapor Volume given rate of pressure change Solution

STEP 0: Pre-Calculation Summary
Formula Used
Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature))
Vm = v+((ΔHv*∆T)/(ΔP*Tabs))
This formula uses 6 Variables
Variables Used
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.
Molal Liquid Volume - (Measured in Cubic Meter) - Molal Liquid Volume is the volume of liquid substance.
Molal Heat of Vaporization - (Measured in Joule Per Mole) - Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.
Change in Temperature - (Measured in Kelvin) - The Change in Temperature refers to the difference between the initial and final temperature.
Change in Pressure - (Measured in Pascal) - Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.
Absolute Temperature - Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.
STEP 1: Convert Input(s) to Base Unit
Molal Liquid Volume: 5.5 Cubic Meter --> 5.5 Cubic Meter No Conversion Required
Molal Heat of Vaporization: 11 KiloJoule Per Mole --> 11000 Joule Per Mole (Check conversion ​here)
Change in Temperature: 50 Kelvin --> 50 Kelvin No Conversion Required
Change in Pressure: 100 Pascal --> 100 Pascal No Conversion Required
Absolute Temperature: 273 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = v+((ΔHv*∆T)/(ΔP*Tabs)) --> 5.5+((11000*50)/(100*273))
Evaluating ... ...
Vm = 25.6465201465201
STEP 3: Convert Result to Output's Unit
25.6465201465201 Cubic Meter per Mole --> No Conversion Required
FINAL ANSWER
25.6465201465201 25.64652 Cubic Meter per Mole <-- Molar Volume
(Calculation completed in 00.004 seconds)

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Molar Vapor Volume given rate of pressure change Formula

​LaTeX ​Go
Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature))
Vm = v+((ΔHv*∆T)/(ΔP*Tabs))

What is Clausius- Clapeyron Equation ?

The rate of increase in vapor pressure per unit increase in temperature is given by the Clausius-Clapeyron equation. More generally the Clausius-Clapeyron equation pertains to the relationship between the pressure and temperature for conditions of equilibrium between two phases. The two phases could be vapor and solid for sublimation or solid and liquid for melting.

How to Calculate Molar Vapor Volume given rate of pressure change?

Molar Vapor Volume given rate of pressure change calculator uses Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)) to calculate the Molar Volume, The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure. Molar Volume is denoted by Vm symbol.

How to calculate Molar Vapor Volume given rate of pressure change using this online calculator? To use this online calculator for Molar Vapor Volume given rate of pressure change, enter Molal Liquid Volume (v), Molal Heat of Vaporization (ΔHv), Change in Temperature (∆T), Change in Pressure (ΔP) & Absolute Temperature (Tabs) and hit the calculate button. Here is how the Molar Vapor Volume given rate of pressure change calculation can be explained with given input values -> 25.64652 = 5.5+((11000*50)/(100*273)).

FAQ

What is Molar Vapor Volume given rate of pressure change?
The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure and is represented as Vm = v+((ΔHv*∆T)/(ΔP*Tabs)) or Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)). Molal Liquid Volume is the volume of liquid substance, Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid, The Change in Temperature refers to the difference between the initial and final temperature, Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP & Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.
How to calculate Molar Vapor Volume given rate of pressure change?
The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure is calculated using Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)). To calculate Molar Vapor Volume given rate of pressure change, you need Molal Liquid Volume (v), Molal Heat of Vaporization (ΔHv), Change in Temperature (∆T), Change in Pressure (ΔP) & Absolute Temperature (Tabs). With our tool, you need to enter the respective value for Molal Liquid Volume, Molal Heat of Vaporization, Change in Temperature, Change in Pressure & Absolute Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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