HCF calculator

Molar Mass of First Gas by Graham's law Calculator

Chemistry Engineering Financial Health More >>

↳

Physical Chemistry Analytical chemistry Atmospheric Chemistry Atomic structure More >>

⤿

Gaseous state Physical spectroscopy Vapour Pressure

⤿

Graham's Law Avogadro's Law Boyle's Law Charle's Law More >>

✖The Molar Mass of Second Gas is defined as the mass of the gas per mole.ⓘ Molar Mass of Second Gas [M₂]			+10% -10%
✖The Rate of Effusion of First Gas is the special case of diffusion when the first gas is allowed to escape through the small hole.ⓘ Rate of Effusion of First Gas [r₁]			+10% -10%
✖The Rate of Effusion of Second Gas is the special case of diffusion when the second gas is allowed to escape through the small hole.ⓘ Rate of Effusion of Second Gas [r₂]			+10% -10%

✖The Molar Mass of First Gas is defined as the mass of the gas per mole.ⓘ Molar Mass of First Gas by Graham's law [M₁]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Gaseous state Formula PDF PDF Image

Molar Mass of First Gas by Graham's law Solution

STEP 0: Pre-Calculation Summary

Formula Used

Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2)
M₁ = M₂/((r₁/r₂)^2)
This formula uses 4 Variables

Variables Used

Molar Mass of First Gas - (Measured in Kilogram Per Mole) - The Molar Mass of First Gas is defined as the mass of the gas per mole.
Molar Mass of Second Gas - (Measured in Kilogram Per Mole) - The Molar Mass of Second Gas is defined as the mass of the gas per mole.
Rate of Effusion of First Gas - (Measured in Cubic Meter per Second) - The Rate of Effusion of First Gas is the special case of diffusion when the first gas is allowed to escape through the small hole.
Rate of Effusion of Second Gas - (Measured in Cubic Meter per Second) - The Rate of Effusion of Second Gas is the special case of diffusion when the second gas is allowed to escape through the small hole.

STEP 1: Convert Input(s) to Base Unit

Molar Mass of Second Gas: 20.21 Gram Per Mole --> 0.02021 Kilogram Per Mole (Check conversion here)
Rate of Effusion of First Gas: 2.12 Cubic Meter per Second --> 2.12 Cubic Meter per Second No Conversion Required
Rate of Effusion of Second Gas: 0.12 Cubic Meter per Second --> 0.12 Cubic Meter per Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

M₁ = M₂/((r₁/r₂)^2) --> 0.02021/((2.12/0.12)^2)

Evaluating ... ...

M₁ = 6.4752580989676E-05

STEP 3: Convert Result to Output's Unit

6.4752580989676E-05 Kilogram Per Mole -->0.064752580989676 Gram Per Mole (Check conversion here)

FINAL ANSWER

0.064752580989676 ≈ 0.064753 Gram Per Mole <-- Molar Mass of First Gas

(Calculation completed in 00.006 seconds)

You are here -

Home » Chemistry » Physical Chemistry » Gaseous state » Graham's Law » Molar Mass of First Gas by Graham's law

Credits

Created by Prashant Singh

K J Somaiya College of science (K J Somaiya), Mumbai

Prashant Singh has created this Calculator and 700+ more calculators!

Verified by Prerana Bakli

University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA

Prerana Bakli has verified this Calculator and 1600+ more calculators!

< Graham's Law Calculators

Rate of Effusion for Second Gas by Graham's law

LaTeX Go Rate of Effusion of Second Gas = Rate of Effusion of First Gas/(sqrt(Molar Mass of Second Gas/Molar Mass of First Gas))

Rate of Effusion for First Gas by Graham's law

LaTeX Go Rate of Effusion of First Gas = (sqrt(Molar Mass of Second Gas/Molar Mass of First Gas))*Rate of Effusion of Second Gas

Molar Mass of Second Gas by Graham's law

LaTeX Go Molar Mass of Second Gas = ((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2)*Molar Mass of First Gas

Molar Mass of First Gas by Graham's law

LaTeX Go Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2)

Molar Mass of First Gas by Graham's law Formula

LaTeX Go

Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2)
M₁ = M₂/((r₁/r₂)^2)

What is Graham's law?

Graham's law of effusion (also called Graham's law of diffusion) was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles. Graham's law is most accurate for molecular effusion which involves the movement of one gas at a time through a hole. It is only approximate for diffusion of one gas in another or in air, as these processes involve the movement of more than one gas. In the same conditions of temperature and pressure, the molar mass is proportional to the mass density. Therefore, the rates of diffusion of different gases are inversely proportional to the square roots of their mass densities.

How to Calculate Molar Mass of First Gas by Graham's law?

Molar Mass of First Gas by Graham's law calculator uses Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2) to calculate the Molar Mass of First Gas, The Molar mass of first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight. Molar Mass of First Gas is denoted by M₁ symbol.

How to calculate Molar Mass of First Gas by Graham's law using this online calculator? To use this online calculator for Molar Mass of First Gas by Graham's law, enter Molar Mass of Second Gas (M₂), Rate of Effusion of First Gas (r₁) & Rate of Effusion of Second Gas (r₂) and hit the calculate button. Here is how the Molar Mass of First Gas by Graham's law calculation can be explained with given input values -> 64.75258 = 0.02021/((2.12/0.12)^2).

FAQ

What is Molar Mass of First Gas by Graham's law?

The Molar mass of first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight and is represented as M₁ = M₂/((r₁/r₂)^2) or Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2). The Molar Mass of Second Gas is defined as the mass of the gas per mole, The Rate of Effusion of First Gas is the special case of diffusion when the first gas is allowed to escape through the small hole & The Rate of Effusion of Second Gas is the special case of diffusion when the second gas is allowed to escape through the small hole.

How to calculate Molar Mass of First Gas by Graham's law?

The Molar mass of first gas by Graham's law formula is defined as rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight is calculated using Molar Mass of First Gas = Molar Mass of Second Gas/((Rate of Effusion of First Gas/Rate of Effusion of Second Gas)^2). To calculate Molar Mass of First Gas by Graham's law, you need Molar Mass of Second Gas (M₂), Rate of Effusion of First Gas (r₁) & Rate of Effusion of Second Gas (r₂). With our tool, you need to enter the respective value for Molar Mass of Second Gas, Rate of Effusion of First Gas & Rate of Effusion of Second Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search