Molality using Relative Lowering of Vapour Pressure Solution

STEP 0: Pre-Calculation Summary
Formula Used
Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent)
m = ((po-p)*1000)/(M*po)
This formula uses 4 Variables
Variables Used
Molality - (Measured in Mole per Kilogram) - Molality is defined as the total number of moles of solute per kilograms of solvent present in the solution.
Vapour Pressure of Pure Solvent - (Measured in Pascal) - The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute.
Vapour Pressure of Solvent in Solution - (Measured in Pascal) - The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute.
Molecular Mass Solvent - (Measured in Kilogram) - The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.
STEP 1: Convert Input(s) to Base Unit
Vapour Pressure of Pure Solvent: 2000 Pascal --> 2000 Pascal No Conversion Required
Vapour Pressure of Solvent in Solution: 1895.86 Pascal --> 1895.86 Pascal No Conversion Required
Molecular Mass Solvent: 18 Gram --> 0.018 Kilogram (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
m = ((po-p)*1000)/(M*po) --> ((2000-1895.86)*1000)/(0.018*2000)
Evaluating ... ...
m = 2892.77777777778
STEP 3: Convert Result to Output's Unit
2892.77777777778 Mole per Kilogram --> No Conversion Required
FINAL ANSWER
2892.77777777778 2892.778 Mole per Kilogram <-- Molality
(Calculation completed in 00.004 seconds)

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Created by Prerana Bakli
University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
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National Institute of Information Technology (NIIT), Neemrana
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Relative Lowering of Vapour Pressure Calculators

Molecular Mass of Solvent given Relative Lowering of Vapour Pressure
​ LaTeX ​ Go Molecular Mass Solvent = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molality*Vapour Pressure of Pure Solvent)
Relative Lowering of Vapour Pressure
​ LaTeX ​ Go Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Mole Fraction of Solute given Vapour Pressure
​ LaTeX ​ Go Mole Fraction of Solute = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent
Mole Fraction of Solvent given Vapour Pressure
​ LaTeX ​ Go Mole Fraction of Solvent = Vapour Pressure of Solvent in Solution/Vapour Pressure of Pure Solvent

Molality using Relative Lowering of Vapour Pressure Formula

​LaTeX ​Go
Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent)
m = ((po-p)*1000)/(M*po)

What causes the Relative Lowering Of Vapour Pressure?

This lowering in vapour pressure is due to the fact that after the solute was added to the pure liquid (solvent), the liquid surface now had molecules of both, the pure liquid and the solute. The number of solvent molecules escaping into vapour phase gets reduced and as a result the pressure exerted by the vapour phase is also reduced. This is known as relative lowering of vapour pressure. This decrease in vapour pressure depends on the amount of non-volatile solute added in the solution irrespective of its nature and hence it is one of the colligative properties.

How to Calculate Molality using Relative Lowering of Vapour Pressure?

Molality using Relative Lowering of Vapour Pressure calculator uses Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent) to calculate the Molality, The Molality using Relative Lowering of Vapour Pressure is a property of a solution and is defined as the number of moles of solute per kilogram of solvent. Molality is denoted by m symbol.

How to calculate Molality using Relative Lowering of Vapour Pressure using this online calculator? To use this online calculator for Molality using Relative Lowering of Vapour Pressure, enter Vapour Pressure of Pure Solvent (po), Vapour Pressure of Solvent in Solution (p) & Molecular Mass Solvent (M) and hit the calculate button. Here is how the Molality using Relative Lowering of Vapour Pressure calculation can be explained with given input values -> 2892.778 = ((2000-1895.86)*1000)/(0.018*2000).

FAQ

What is Molality using Relative Lowering of Vapour Pressure?
The Molality using Relative Lowering of Vapour Pressure is a property of a solution and is defined as the number of moles of solute per kilogram of solvent and is represented as m = ((po-p)*1000)/(M*po) or Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent). The Vapour Pressure of Pure Solvent is the vapour pressure of solvent prior to addition of solute, The Vapour Pressure of Solvent in Solution is the vapour pressure of solvent post addition of solute & The Molecular Mass Solvent is sum of the atomic masses of all atoms in a molecule, based on a scale in which the atomic masses.
How to calculate Molality using Relative Lowering of Vapour Pressure?
The Molality using Relative Lowering of Vapour Pressure is a property of a solution and is defined as the number of moles of solute per kilogram of solvent is calculated using Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent). To calculate Molality using Relative Lowering of Vapour Pressure, you need Vapour Pressure of Pure Solvent (po), Vapour Pressure of Solvent in Solution (p) & Molecular Mass Solvent (M). With our tool, you need to enter the respective value for Vapour Pressure of Pure Solvent, Vapour Pressure of Solvent in Solution & Molecular Mass Solvent and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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