LCM of two numbers

Molal Liquid Volume given rate of pressure change Calculator

Chemistry Engineering Financial Health More >>

↳

Solution and Colligative properties Analytical chemistry Atmospheric Chemistry Atomic structure More >>

⤿

Gibb's Phase Rule Clausius Clapeyron Equation Depression in Freezing Point Elevation in Boiling Point More >>

⤿

Multi Component System

✖Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.ⓘ Molar Volume [V_m]			+10% -10%
✖The Change in Temperature refers to the difference between the initial and final temperature.ⓘ Change in Temperature [∆T]			+10% -10%
✖Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.ⓘ Molal Heat of Vaporization [ΔH_v]			+10% -10%
✖Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.ⓘ Change in Pressure [ΔP]			+10% -10%
✖Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.ⓘ Absolute Temperature [T_abs]			+10% -10%

✖Molal Liquid Volume is the volume of liquid substance.ⓘ Molal Liquid Volume given rate of pressure change [v]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Solution and Colligative properties Formula PDF PDF Image

Molal Liquid Volume given rate of pressure change Solution

STEP 0: Pre-Calculation Summary

Formula Used

Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature))
v = V_m-((∆T*ΔH_v)/(ΔP*T_abs))
This formula uses 6 Variables

Variables Used

Molal Liquid Volume - (Measured in Cubic Meter) - Molal Liquid Volume is the volume of liquid substance.
Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.
Change in Temperature - (Measured in Kelvin) - The Change in Temperature refers to the difference between the initial and final temperature.
Molal Heat of Vaporization - (Measured in Joule Per Mole) - Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.
Change in Pressure - (Measured in Pascal) - Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.
Absolute Temperature - Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.

STEP 1: Convert Input(s) to Base Unit

Molar Volume: 32 Cubic Meter per Mole --> 32 Cubic Meter per Mole No Conversion Required
Change in Temperature: 50 Kelvin --> 50 Kelvin No Conversion Required
Molal Heat of Vaporization: 11 KiloJoule Per Mole --> 11000 Joule Per Mole (Check conversion here)
Change in Pressure: 100 Pascal --> 100 Pascal No Conversion Required
Absolute Temperature: 273 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

v = V_m-((∆T*ΔH_v)/(ΔP*T_abs)) --> 32-((50*11000)/(100*273))

Evaluating ... ...

v = 11.8534798534799

STEP 3: Convert Result to Output's Unit

11.8534798534799 Cubic Meter --> No Conversion Required

FINAL ANSWER

11.8534798534799 ≈ 11.85348 Cubic Meter <-- Molal Liquid Volume

(Calculation completed in 00.004 seconds)

You are here -

Home » Chemistry » Solution and Colligative properties » Gibb's Phase Rule » Molal Liquid Volume given rate of pressure change

Credits

Created by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has created this Calculator and 500+ more calculators!

Verified by Pragati Jaju

College Of Engineering (COEP), Pune

Pragati Jaju has verified this Calculator and 300+ more calculators!

< Gibb's Phase Rule Calculators

Molal Liquid Volume given rate of pressure change

LaTeX Go Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature))

Mole Fraction of A in Liquid in Raoult's Law

LaTeX Go Mole Fraction of Component A in Liquid Phase = Partial Pressure/Vapor Pressure of Pure Component A

Number of Phases in Equilibrium for Non-Reactive Systems

LaTeX Go Number of Phases = Number of Components-Degree of Freedom+2

Molal Liquid Volume given rate of pressure change Formula

LaTeX Go

Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature))
v = V_m-((∆T*ΔH_v)/(ΔP*T_abs))

What is Clausius- Clapeyron Equation ?

The rate of increase in vapor pressure per unit increase in temperature is given by the Clausius-Clapeyron equation. More generally the Clausius-Clapeyron equation pertains to the relationship between the pressure and temperature for conditions of equilibrium between two phases. The two phases could be vapor and solid for sublimation or solid and liquid for melting.

How to Calculate Molal Liquid Volume given rate of pressure change?

Molal Liquid Volume given rate of pressure change calculator uses Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature)) to calculate the Molal Liquid Volume, The Molal Liquid Volume given rate of pressure change formula is defined as the volume of liquid of one mole of substance. Molal Liquid Volume is denoted by v symbol.

How to calculate Molal Liquid Volume given rate of pressure change using this online calculator? To use this online calculator for Molal Liquid Volume given rate of pressure change, enter Molar Volume (V_m), Change in Temperature (∆T), Molal Heat of Vaporization (ΔH_v), Change in Pressure (ΔP) & Absolute Temperature (T_abs) and hit the calculate button. Here is how the Molal Liquid Volume given rate of pressure change calculation can be explained with given input values -> 11.85348 = 32-((50*11000)/(100*273)).

FAQ

What is Molal Liquid Volume given rate of pressure change?

The Molal Liquid Volume given rate of pressure change formula is defined as the volume of liquid of one mole of substance and is represented as v = V_m-((∆T*ΔH_v)/(ΔP*T_abs)) or Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature)). Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure, The Change in Temperature refers to the difference between the initial and final temperature, Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid, Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP & Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.

How to calculate Molal Liquid Volume given rate of pressure change?

The Molal Liquid Volume given rate of pressure change formula is defined as the volume of liquid of one mole of substance is calculated using Molal Liquid Volume = Molar Volume-((Change in Temperature*Molal Heat of Vaporization)/(Change in Pressure*Absolute Temperature)). To calculate Molal Liquid Volume given rate of pressure change, you need Molar Volume (V_m), Change in Temperature (∆T), Molal Heat of Vaporization (ΔH_v), Change in Pressure (ΔP) & Absolute Temperature (T_abs). With our tool, you need to enter the respective value for Molar Volume, Change in Temperature, Molal Heat of Vaporization, Change in Pressure & Absolute Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search