Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm Solution

STEP 0: Pre-Calculation Summary
Formula Used
Minor Axis of Pulley Arm = 64*Area Moment of Inertia of Arms/(pi*Major Axis of Pulley Arm^3)
a = 64*I/(pi*ba^3)
This formula uses 1 Constants, 3 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Minor Axis of Pulley Arm - (Measured in Meter) - Minor Axis of Pulley Arm is the length of the minor or the smallest axis of the elliptical cross-section of a pulley.
Area Moment of Inertia of Arms - (Measured in Meter⁴) - Area Moment of Inertia of Arms is the measure of the resistance of the arms of a part its angular acceleration about a given axis without considering its mass.
Major Axis of Pulley Arm - (Measured in Meter) - Major Axis of Pulley Arm is the length of the major or the largest axis of the elliptical cross-section of a pulley.
STEP 1: Convert Input(s) to Base Unit
Area Moment of Inertia of Arms: 17350 Millimeter⁴ --> 1.735E-08 Meter⁴ (Check conversion ​here)
Major Axis of Pulley Arm: 29.6 Millimeter --> 0.0296 Meter (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
a = 64*I/(pi*ba^3) --> 64*1.735E-08/(pi*0.0296^3)
Evaluating ... ...
a = 0.0136287004848893
STEP 3: Convert Result to Output's Unit
0.0136287004848893 Meter -->13.6287004848893 Millimeter (Check conversion ​here)
FINAL ANSWER
13.6287004848893 13.6287 Millimeter <-- Minor Axis of Pulley Arm
(Calculation completed in 00.004 seconds)

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​ LaTeX ​ Go Tangential Force at End of Each Pulley Arm = Torque Transmitted by Pulley/(Radius of Rim of Pulley*(Number of Arms in Pulley/2))
Radius of Rim of Pulley given Torque Transmitted by Pulley
​ LaTeX ​ Go Radius of Rim of Pulley = Torque Transmitted by Pulley/(Tangential Force at End of Each Pulley Arm*(Number of Arms in Pulley/2))
Number of Arms of Pulley given Torque Transmitted by Pulley
​ LaTeX ​ Go Number of Arms in Pulley = 2*Torque Transmitted by Pulley/(Tangential Force at End of Each Pulley Arm*Radius of Rim of Pulley)
Torque Transmitted by Pulley
​ LaTeX ​ Go Torque Transmitted by Pulley = Tangential Force at End of Each Pulley Arm*Radius of Rim of Pulley*(Number of Arms in Pulley/2)

Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm Formula

​Go
Minor Axis of Pulley Arm = 64*Area Moment of Inertia of Arms/(pi*Major Axis of Pulley Arm^3)
a = 64*I/(pi*ba^3)

Define Moment of Inertia?

The moment of inertia, otherwise known as the mass moment of inertia, angular mass, second moment of mass, or most accurately, rotational inertia, of a rigid body is a quantity that determines the torque needed for a desired angular acceleration about a rotational axis, akin to how mass determines the force needed for a desired acceleration.

How to Calculate Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm?

Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm calculator uses Minor Axis of Pulley Arm = 64*Area Moment of Inertia of Arms/(pi*Major Axis of Pulley Arm^3) to calculate the Minor Axis of Pulley Arm, The Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm formula is defined as shortest axis of elliptical cross-section of arm which is perpendicular to major axis. Minor Axis of Pulley Arm is denoted by a symbol.

How to calculate Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm using this online calculator? To use this online calculator for Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm, enter Area Moment of Inertia of Arms (I) & Major Axis of Pulley Arm (ba) and hit the calculate button. Here is how the Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm calculation can be explained with given input values -> 13628.7 = 64*1.735E-08/(pi*0.0296^3).

FAQ

What is Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm?
The Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm formula is defined as shortest axis of elliptical cross-section of arm which is perpendicular to major axis and is represented as a = 64*I/(pi*ba^3) or Minor Axis of Pulley Arm = 64*Area Moment of Inertia of Arms/(pi*Major Axis of Pulley Arm^3). Area Moment of Inertia of Arms is the measure of the resistance of the arms of a part its angular acceleration about a given axis without considering its mass & Major Axis of Pulley Arm is the length of the major or the largest axis of the elliptical cross-section of a pulley.
How to calculate Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm?
The Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm formula is defined as shortest axis of elliptical cross-section of arm which is perpendicular to major axis is calculated using Minor Axis of Pulley Arm = 64*Area Moment of Inertia of Arms/(pi*Major Axis of Pulley Arm^3). To calculate Minor Axis of Elliptical Cross-Section of Arm given Moment of Inertia of Arm, you need Area Moment of Inertia of Arms (I) & Major Axis of Pulley Arm (ba). With our tool, you need to enter the respective value for Area Moment of Inertia of Arms & Major Axis of Pulley Arm and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Minor Axis of Pulley Arm?
In this formula, Minor Axis of Pulley Arm uses Area Moment of Inertia of Arms & Major Axis of Pulley Arm. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Minor Axis of Pulley Arm = (8*Area Moment of Inertia of Arms/pi)^(1/4)
  • Minor Axis of Pulley Arm = 1.72*((Bending Moment in Pulley's Arm/(2*Bending stress in pulley's arm))^(1/3))
  • Minor Axis of Pulley Arm = (16*Torque Transmitted by Pulley/(pi*Number of Arms in Pulley*Bending stress in pulley's arm))^(1/3)
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