Minimum Periodic Time of SHM for Compound Pendulum Solution

STEP 0: Pre-Calculation Summary
Formula Used
Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity)
tp = 2*pi*sqrt(2*kG/g)
This formula uses 1 Constants, 1 Functions, 3 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Time Period SHM - (Measured in Second) - Time Period SHM is time required for the periodic motion.
Radius of Gyration - (Measured in Meter) - The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass.
Acceleration Due to Gravity - (Measured in Meter per Square Second) - Acceleration Due to Gravity is acceleration gained by an object because of gravitational force.
STEP 1: Convert Input(s) to Base Unit
Radius of Gyration: 3103 Millimeter --> 3.103 Meter (Check conversion ​here)
Acceleration Due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
tp = 2*pi*sqrt(2*kG/g) --> 2*pi*sqrt(2*3.103/9.8)
Evaluating ... ...
tp = 5.00003122084785
STEP 3: Convert Result to Output's Unit
5.00003122084785 Second --> No Conversion Required
FINAL ANSWER
5.00003122084785 5.000031 Second <-- Time Period SHM
(Calculation completed in 00.020 seconds)

Credits

Creator Image
Created by Anshika Arya
National Institute Of Technology (NIT), Hamirpur
Anshika Arya has created this Calculator and 2000+ more calculators!
Verifier Image
Verified by Team Softusvista
Softusvista Office (Pune), India
Team Softusvista has verified this Calculator and 1100+ more calculators!

Compound Pendulum Calculators

Periodic Time of SHM for Compound Pendulum given Radius of Gyration
​ LaTeX ​ Go Periodic Time for Compound Pendulum = 2*pi*sqrt((Radius of Gyration^2+Distance of PT of Suspension of Pendulum From CG^2)/(Acceleration Due to Gravity*Distance of PT of Suspension of Pendulum From CG))
Minimum Periodic Time of SHM for Compound Pendulum
​ LaTeX ​ Go Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity)
Frequency of Compound Pendulum in SHM
​ LaTeX ​ Go Frequency = 1/Periodic Time for Compound Pendulum

Minimum Periodic Time of SHM for Compound Pendulum Formula

​LaTeX ​Go
Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity)
tp = 2*pi*sqrt(2*kG/g)

What is the meaning of time period or periodic time?

The time period is the time taken by a complete cycle of the wave to pass a point, Frequency is the number of the complete cycles of waves passing a point in unit time. Angular frequency is the angular displacement of any element of the wave per unit time.

How to Calculate Minimum Periodic Time of SHM for Compound Pendulum?

Minimum Periodic Time of SHM for Compound Pendulum calculator uses Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity) to calculate the Time Period SHM, Minimum Periodic Time of SHM for Compound Pendulum formula is defined as the time required for one complete oscillation of a compound pendulum in simple harmonic motion, which depends on the gravitational acceleration and the radius of gyration of the pendulum. Time Period SHM is denoted by tp symbol.

How to calculate Minimum Periodic Time of SHM for Compound Pendulum using this online calculator? To use this online calculator for Minimum Periodic Time of SHM for Compound Pendulum, enter Radius of Gyration (kG) & Acceleration Due to Gravity (g) and hit the calculate button. Here is how the Minimum Periodic Time of SHM for Compound Pendulum calculation can be explained with given input values -> 0.500003 = 2*pi*sqrt(2*3.103/9.8).

FAQ

What is Minimum Periodic Time of SHM for Compound Pendulum?
Minimum Periodic Time of SHM for Compound Pendulum formula is defined as the time required for one complete oscillation of a compound pendulum in simple harmonic motion, which depends on the gravitational acceleration and the radius of gyration of the pendulum and is represented as tp = 2*pi*sqrt(2*kG/g) or Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity). The Radius of Gyration or gyradius is defined as the radial distance to a point that would have a moment of inertia the same as the body's actual distribution of mass & Acceleration Due to Gravity is acceleration gained by an object because of gravitational force.
How to calculate Minimum Periodic Time of SHM for Compound Pendulum?
Minimum Periodic Time of SHM for Compound Pendulum formula is defined as the time required for one complete oscillation of a compound pendulum in simple harmonic motion, which depends on the gravitational acceleration and the radius of gyration of the pendulum is calculated using Time Period SHM = 2*pi*sqrt(2*Radius of Gyration/Acceleration Due to Gravity). To calculate Minimum Periodic Time of SHM for Compound Pendulum, you need Radius of Gyration (kG) & Acceleration Due to Gravity (g). With our tool, you need to enter the respective value for Radius of Gyration & Acceleration Due to Gravity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!