Medium Diagonal of Octagon given Short Diagonal Solution

STEP 0: Pre-Calculation Summary
Formula Used
Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon
dMedium = sqrt(1+(1/(sqrt(2))))*dShort
This formula uses 1 Functions, 2 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Medium Diagonal of Octagon - (Measured in Meter) - The Medium Diagonal of Octagon is the length of medium diagonals or the line joining one vertex and any one of vertices that closest to the opposite vertex of first vertex of the Regular Octagon.
Short Diagonal of Octagon - (Measured in Meter) - The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.
STEP 1: Convert Input(s) to Base Unit
Short Diagonal of Octagon: 18 Meter --> 18 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
dMedium = sqrt(1+(1/(sqrt(2))))*dShort --> sqrt(1+(1/(sqrt(2))))*18
Evaluating ... ...
dMedium = 23.5181333677748
STEP 3: Convert Result to Output's Unit
23.5181333677748 Meter --> No Conversion Required
FINAL ANSWER
23.5181333677748 23.51813 Meter <-- Medium Diagonal of Octagon
(Calculation completed in 00.020 seconds)

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St Joseph's College (SJC), Bengaluru
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Walchand College of Engineering (WCE), Sangli
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Medium Diagonal of Octagon Calculators

Medium Diagonal of Octagon given Short Diagonal
​ LaTeX ​ Go Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon
Medium Diagonal of Octagon given Long Diagonal
​ LaTeX ​ Go Medium Diagonal of Octagon = ((sqrt(2+sqrt(2)))/2)*Long Diagonal of Octagon
Medium Diagonal of Octagon given Perimeter
​ LaTeX ​ Go Medium Diagonal of Octagon = (1+sqrt(2))*Perimeter of Octagon/8
Medium Diagonal of Octagon
​ LaTeX ​ Go Medium Diagonal of Octagon = (1+sqrt(2))*Edge Length of Octagon

Medium Diagonal of Octagon given Short Diagonal Formula

​LaTeX ​Go
Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon
dMedium = sqrt(1+(1/(sqrt(2))))*dShort

What is an Octagon?

Octagon is a polygon in geometry, which has 8 sides and 8 angles. That means the number of vertices is 8 and the number of edges is 8. All the sides are joined with each other end-to-end to form a shape. These sides are in a straight line form; they are not curved or disjoint with each other. Each interior angle of a regular octagon is 135° and each exterior angle will be 45°.

How to Calculate Medium Diagonal of Octagon given Short Diagonal?

Medium Diagonal of Octagon given Short Diagonal calculator uses Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon to calculate the Medium Diagonal of Octagon, The Medium Diagonal of Octagon given Short Diagonal formula is defined as the length of medium diagonals or the line joining one vertex and any of the vertices closest to the opposite vertex of first vertex of the Regular Octagon, and calculated using short diagonal of the Octagon. Medium Diagonal of Octagon is denoted by dMedium symbol.

How to calculate Medium Diagonal of Octagon given Short Diagonal using this online calculator? To use this online calculator for Medium Diagonal of Octagon given Short Diagonal, enter Short Diagonal of Octagon (dShort) and hit the calculate button. Here is how the Medium Diagonal of Octagon given Short Diagonal calculation can be explained with given input values -> 23.51813 = sqrt(1+(1/(sqrt(2))))*18.

FAQ

What is Medium Diagonal of Octagon given Short Diagonal?
The Medium Diagonal of Octagon given Short Diagonal formula is defined as the length of medium diagonals or the line joining one vertex and any of the vertices closest to the opposite vertex of first vertex of the Regular Octagon, and calculated using short diagonal of the Octagon and is represented as dMedium = sqrt(1+(1/(sqrt(2))))*dShort or Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon. The Short Diagonal of Octagon is the length of smallest diagonals or the line joining a vertex and any one of the vertices that coming next to the adjacent vertices of the first vertex of the Octagon.
How to calculate Medium Diagonal of Octagon given Short Diagonal?
The Medium Diagonal of Octagon given Short Diagonal formula is defined as the length of medium diagonals or the line joining one vertex and any of the vertices closest to the opposite vertex of first vertex of the Regular Octagon, and calculated using short diagonal of the Octagon is calculated using Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon. To calculate Medium Diagonal of Octagon given Short Diagonal, you need Short Diagonal of Octagon (dShort). With our tool, you need to enter the respective value for Short Diagonal of Octagon and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Medium Diagonal of Octagon?
In this formula, Medium Diagonal of Octagon uses Short Diagonal of Octagon. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Medium Diagonal of Octagon = (1+sqrt(2))*Edge Length of Octagon
  • Medium Diagonal of Octagon = ((sqrt(2+sqrt(2)))/2)*Long Diagonal of Octagon
  • Medium Diagonal of Octagon = (1+sqrt(2))*Perimeter of Octagon/8
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