Medium Diagonal of Octagon given Inradius Calculator

✖The Inradius of Octagon is the radius of incircle of the Regular Octagon or the circle that contained by the Octagon with all edges touch the circle.ⓘ Inradius of Octagon [r_i]

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✖The Medium Diagonal of Octagon is the length of medium diagonals or the line joining one vertex and any one of vertices that closest to the opposite vertex of first vertex of the Regular Octagon.ⓘ Medium Diagonal of Octagon given Inradius [d_Medium]

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Medium Diagonal of Octagon given Inradius Solution

STEP 0: Pre-Calculation Summary

Formula Used

Medium Diagonal of Octagon = 2*Inradius of Octagon
d_Medium = 2*r_i
This formula uses 2 Variables

Variables Used

Medium Diagonal of Octagon - (Measured in Meter) - The Medium Diagonal of Octagon is the length of medium diagonals or the line joining one vertex and any one of vertices that closest to the opposite vertex of first vertex of the Regular Octagon.
Inradius of Octagon - (Measured in Meter) - The Inradius of Octagon is the radius of incircle of the Regular Octagon or the circle that contained by the Octagon with all edges touch the circle.

STEP 1: Convert Input(s) to Base Unit

Inradius of Octagon: 12 Meter --> 12 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

d_Medium = 2*r_i --> 2*12

Evaluating ... ...

d_Medium = 24

STEP 3: Convert Result to Output's Unit

24 Meter --> No Conversion Required

FINAL ANSWER

24 Meter <-- Medium Diagonal of Octagon

(Calculation completed in 00.004 seconds)

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Created by Mona Gladys

St Joseph's College (SJC), Bengaluru

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Walchand College of Engineering (WCE), Sangli

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< Medium Diagonal of Octagon Calculators

Medium Diagonal of Octagon given Short Diagonal

LaTeX Go Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon

Medium Diagonal of Octagon given Long Diagonal

LaTeX Go Medium Diagonal of Octagon = ((sqrt(2+sqrt(2)))/2)*Long Diagonal of Octagon

Medium Diagonal of Octagon given Perimeter

LaTeX Go Medium Diagonal of Octagon = (1+sqrt(2))*Perimeter of Octagon/8

Medium Diagonal of Octagon

LaTeX Go Medium Diagonal of Octagon = (1+sqrt(2))*Edge Length of Octagon

< Diagonal of Octagon Calculators

Long Diagonal of Octagon

LaTeX Go Long Diagonal of Octagon = sqrt(4+(2*sqrt(2)))*Edge Length of Octagon

Medium Diagonal of Octagon

LaTeX Go Medium Diagonal of Octagon = (1+sqrt(2))*Edge Length of Octagon

Long Diagonal of Octagon given Circumradius

LaTeX Go Long Diagonal of Octagon = 2*Circumradius of Octagon

Medium Diagonal of Octagon given Inradius

LaTeX Go Medium Diagonal of Octagon = 2*Inradius of Octagon

Medium Diagonal of Octagon given Inradius Formula

LaTeX Go

Medium Diagonal of Octagon = 2*Inradius of Octagon
d_Medium = 2*r_i

What is an Octagon?

Octagon is a polygon in geometry, which has 8 sides and 8 angles. That means the number of vertices is 8 and the number of edges is 8. All the sides are joined with each other end-to-end to form a shape. These sides are in a straight line form; they are not curved or disjoint with each other. Each interior angle of a regular octagon is 135° and each exterior angle will be 45°.

How to Calculate Medium Diagonal of Octagon given Inradius?

Medium Diagonal of Octagon given Inradius calculator uses Medium Diagonal of Octagon = 2*Inradius of Octagon to calculate the Medium Diagonal of Octagon, The Medium Diagonal of Octagon given Inradius formula is defined as the length of medium diagonals or the line joining one vertex and any one of the vertices that is closest to the opposite vertex of first vertex of the Regular Octagon and calculated using inradius of the Octagon. Medium Diagonal of Octagon is denoted by d_Medium symbol.

How to calculate Medium Diagonal of Octagon given Inradius using this online calculator? To use this online calculator for Medium Diagonal of Octagon given Inradius, enter Inradius of Octagon (r_i) and hit the calculate button. Here is how the Medium Diagonal of Octagon given Inradius calculation can be explained with given input values -> 24 = 2*12.

FAQ

What is Medium Diagonal of Octagon given Inradius?

The Medium Diagonal of Octagon given Inradius formula is defined as the length of medium diagonals or the line joining one vertex and any one of the vertices that is closest to the opposite vertex of first vertex of the Regular Octagon and calculated using inradius of the Octagon and is represented as d_Medium = 2*r_i or Medium Diagonal of Octagon = 2*Inradius of Octagon. The Inradius of Octagon is the radius of incircle of the Regular Octagon or the circle that contained by the Octagon with all edges touch the circle.

How to calculate Medium Diagonal of Octagon given Inradius?

The Medium Diagonal of Octagon given Inradius formula is defined as the length of medium diagonals or the line joining one vertex and any one of the vertices that is closest to the opposite vertex of first vertex of the Regular Octagon and calculated using inradius of the Octagon is calculated using Medium Diagonal of Octagon = 2*Inradius of Octagon. To calculate Medium Diagonal of Octagon given Inradius, you need Inradius of Octagon (r_i). With our tool, you need to enter the respective value for Inradius of Octagon and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Medium Diagonal of Octagon?

In this formula, Medium Diagonal of Octagon uses Inradius of Octagon. We can use 3 other way(s) to calculate the same, which is/are as follows -

Medium Diagonal of Octagon = (1+sqrt(2))*Edge Length of Octagon
Medium Diagonal of Octagon = ((sqrt(2+sqrt(2)))/2)*Long Diagonal of Octagon
Medium Diagonal of Octagon = sqrt(1+(1/(sqrt(2))))*Short Diagonal of Octagon

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