Maximum Voltage using Line Losses (2-Phase 3-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference)
Vm = (P*sqrt((2+sqrt(2))*ρ*L/(A*Ploss)))/cos(Φ)
This formula uses 2 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = (P*sqrt((2+sqrt(2))*ρ*L/(A*Ploss)))/cos(Φ) --> (300*sqrt((2+sqrt(2))*1.7E-05*24/(1.28*2.67)))/cos(0.5235987755982)
Evaluating ... ...
Vm = 6.99367474417098
STEP 3: Convert Result to Output's Unit
6.99367474417098 Volt --> No Conversion Required
FINAL ANSWER
6.99367474417098 6.993675 Volt <-- Maximum Voltage Underground AC
(Calculation completed in 00.004 seconds)

Credits

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Created by Urvi Rathod
Vishwakarma Government Engineering College (VGEC), Ahmedabad
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Current and Voltage Calculators

Maximum Voltage using Line Losses (2-Phase 3-Wire US)
​ LaTeX ​ Go Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference)
Maximum Voltage using Volume of Conductor Material (2-phase 3-wire US)
​ LaTeX ​ Go Maximum Voltage Underground AC = (2+sqrt(2))*sqrt(Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
RMS Voltage using Line Losses (2-Phase 3-Wire US)
​ LaTeX ​ Go Root Mean Square Voltage = Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
Maximum Phase Voltage between Outer and Neutral Wire (2-Phase 3-Wire US)
​ LaTeX ​ Go Peak Phase Voltage = Maximum Voltage Underground AC/(sqrt(2))

Maximum Voltage using Line Losses (2-Phase 3-Wire US) Formula

​LaTeX ​Go
Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference)
Vm = (P*sqrt((2+sqrt(2))*ρ*L/(A*Ploss)))/cos(Φ)

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 2.914/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm/√2 so that r.m.s. value of voltage between them is vm/2.

How to Calculate Maximum Voltage using Line Losses (2-Phase 3-Wire US)?

Maximum Voltage using Line Losses (2-Phase 3-Wire US) calculator uses Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference) to calculate the Maximum Voltage Underground AC, The Maximum Voltage using Line Losses (2-Phase 3-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by Vm symbol.

How to calculate Maximum Voltage using Line Losses (2-Phase 3-Wire US) using this online calculator? To use this online calculator for Maximum Voltage using Line Losses (2-Phase 3-Wire US), enter Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (Ploss) & Phase Difference (Φ) and hit the calculate button. Here is how the Maximum Voltage using Line Losses (2-Phase 3-Wire US) calculation can be explained with given input values -> 6.993675 = (300*sqrt((2+sqrt(2))*1.7E-05*24/(1.28*2.67)))/cos(0.5235987755982).

FAQ

What is Maximum Voltage using Line Losses (2-Phase 3-Wire US)?
The Maximum Voltage using Line Losses (2-Phase 3-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition and is represented as Vm = (P*sqrt((2+sqrt(2))*ρ*L/(A*Ploss)))/cos(Φ) or Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Line Losses is defined as the total losses occurring in an Underground AC line when in use & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Maximum Voltage using Line Losses (2-Phase 3-Wire US)?
The Maximum Voltage using Line Losses (2-Phase 3-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition is calculated using Maximum Voltage Underground AC = (Power Transmitted*sqrt((2+sqrt(2))*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)))/cos(Phase Difference). To calculate Maximum Voltage using Line Losses (2-Phase 3-Wire US), you need Power Transmitted (P), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A), Line Losses (Ploss) & Phase Difference (Φ). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire, Line Losses & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Voltage Underground AC?
In this formula, Maximum Voltage Underground AC uses Power Transmitted, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire, Line Losses & Phase Difference. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Maximum Voltage Underground AC = (2+sqrt(2))*sqrt(Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
  • Maximum Voltage Underground AC = 2*Root Mean Square Voltage
  • Maximum Voltage Underground AC = Power Transmitted/(cos(Phase Difference)*Current Underground AC)
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