Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))
Vm = ((2*P)/cos(Φ))*sqrt(ρ*L/(A*Ploss))
This formula uses 2 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion ​here)
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = ((2*P)/cos(Φ))*sqrt(ρ*L/(A*Ploss)) --> ((2*300)/cos(0.5235987755982))*sqrt(1.7E-05*24/(1.28*2.67))
Evaluating ... ...
Vm = 7.56989899447257
STEP 3: Convert Result to Output's Unit
7.56989899447257 Volt --> No Conversion Required
FINAL ANSWER
7.56989899447257 7.569899 Volt <-- Maximum Voltage Underground AC
(Calculation completed in 00.004 seconds)

Credits

Creator Image
Created by Urvi Rathod
Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1500+ more calculators!
Verifier Image
Verified by Kethavath Srinath
Osmania University (OU), Hyderabad
Kethavath Srinath has verified this Calculator and 1200+ more calculators!

Current and Voltage Calculators

Maximum Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed)
​ LaTeX ​ Go Maximum Voltage Underground AC = (sqrt(2)*Power Transmitted)/(Current Underground AC*cos(Phase Difference))
Load Current (1-Phase 2-Wire Mid-Point Earthed)
​ LaTeX ​ Go Current Underground AC = (sqrt(2)*Power Transmitted)/(Maximum Voltage Underground AC*cos(Phase Difference))
RMS Voltage using Load Current (1-Phase 2-Wire Mid-Point Earthed)
​ LaTeX ​ Go Root Mean Square Voltage = Power Transmitted/(Current Underground AC*cos(Phase Difference))
Load Current using Line Losses (1-Phase 2-Wire Mid-Point Earthed)
​ LaTeX ​ Go Current Underground AC = sqrt(Line Losses/(2*Resistance Underground AC))

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

​LaTeX ​Go
Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))
Vm = ((2*P)/cos(Φ))*sqrt(ρ*L/(A*Ploss))

What is the value of volume of conductor material in this US?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculator uses Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)) to calculate the Maximum Voltage Underground AC, The Maximum Voltage using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by Vm symbol.

How to calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), enter Power Transmitted (P), Phase Difference (Φ), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A) & Line Losses (Ploss) and hit the calculate button. Here is how the Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 7.569899 = ((2*300)/cos(0.5235987755982))*sqrt(1.7E-05*24/(1.28*2.67)).

FAQ

What is Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?
The Maximum Voltage using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition and is represented as Vm = ((2*P)/cos(Φ))*sqrt(ρ*L/(A*Ploss)) or Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system & Line Losses is defined as the total losses occurring in an Underground AC line when in use.
How to calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?
The Maximum Voltage using Area of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition is calculated using Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses)). To calculate Maximum Voltage using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), you need Power Transmitted (P), Phase Difference (Φ), Resistivity (ρ), Length of Underground AC Wire (L), Area of Underground AC Wire (A) & Line Losses (Ploss). With our tool, you need to enter the respective value for Power Transmitted, Phase Difference, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Voltage Underground AC?
In this formula, Maximum Voltage Underground AC uses Power Transmitted, Phase Difference, Resistivity, Length of Underground AC Wire, Area of Underground AC Wire & Line Losses. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Maximum Voltage Underground AC = (sqrt(2)*Power Transmitted)/(Current Underground AC*cos(Phase Difference))
  • Maximum Voltage Underground AC = ((2*Power Transmitted)/cos(Phase Difference))*sqrt(Resistance Underground AC/Line Losses)
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!