Maximum velocity to avoid overturning of vehicle along level circular path Calculator

✖Radius of Circular Path is the distance from the center of a circular path to any point on the circle in general dynamics principles.ⓘ Radius of Circular Path [r]			+10% -10%
✖Distance between Center Lines of two Wheels is the length between the center points of two wheels, considering general dynamics principles in motion.ⓘ Distance between Center Lines of two Wheels [d_w]			+10% -10%
✖Gauge of Track is the measure of the distance between the inner edges of the rail in a railway track, crucial in general dynamics principles.ⓘ Gauge of Track [G]			+10% -10%

✖Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.ⓘ Maximum velocity to avoid overturning of vehicle along level circular path [v]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download General Principal to Dynamics Formulas PDF PDF Image

Maximum velocity to avoid overturning of vehicle along level circular path Solution

STEP 0: Pre-Calculation Summary

Formula Used

Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))
v = sqrt(([g]*r*d_w)/(2*G))
This formula uses 1 Constants, 1 Functions, 4 Variables

Constants Used

[g] - Gravitational acceleration on Earth Value Taken As 9.80665

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Velocity - (Measured in Meter per Second) - Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.
Radius of Circular Path - (Measured in Meter) - Radius of Circular Path is the distance from the center of a circular path to any point on the circle in general dynamics principles.
Distance between Center Lines of two Wheels - (Measured in Meter) - Distance between Center Lines of two Wheels is the length between the center points of two wheels, considering general dynamics principles in motion.
Gauge of Track - (Measured in Meter) - Gauge of Track is the measure of the distance between the inner edges of the rail in a railway track, crucial in general dynamics principles.

STEP 1: Convert Input(s) to Base Unit

Radius of Circular Path: 100 Meter --> 100 Meter No Conversion Required
Distance between Center Lines of two Wheels: 1.5 Meter --> 1.5 Meter No Conversion Required
Gauge of Track: 0.2 Meter --> 0.2 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

v = sqrt(([g]*r*d_w)/(2*G)) --> sqrt(([g]*100*1.5)/(2*0.2))

Evaluating ... ...

v = 60.6423428802021

STEP 3: Convert Result to Output's Unit

60.6423428802021 Meter per Second --> No Conversion Required

FINAL ANSWER

60.6423428802021 ≈ 60.64234 Meter per Second <-- Velocity

(Calculation completed in 00.004 seconds)

You are here -

Home » Physics » Mechanics » General Principal to Dynamics » Mechanical » Principal Parameters » Maximum velocity to avoid overturning of vehicle along level circular path

Credits

Created by Chilvera Bhanu Teja

Institute of Aeronautical Engineering (IARE), Hyderabad

Chilvera Bhanu Teja has created this Calculator and 300+ more calculators!

Verified by Rajat Vishwakarma

University Institute of Technology RGPV (UIT - RGPV), Bhopal

Rajat Vishwakarma has verified this Calculator and 400+ more calculators!

< Principal Parameters Calculators

Maximum velocity to avoid overturning of vehicle along level circular path

LaTeX Go Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))

Force of attraction between two masses separated by distance

LaTeX Go Gravitational Force of Attraction = ([G.]*Mass of First Particle*Mass of Second Particle)/(Distance between two Masses^2)

Superelevation in railways

LaTeX Go Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path)

Angle of banking

LaTeX Go Angle of Banking = atan((Velocity^2)/([g]*Radius of Circular Path))

Maximum velocity to avoid overturning of vehicle along level circular path Formula

LaTeX Go

Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))
v = sqrt(([g]*r*d_w)/(2*G))

What is Overturning of a Vehicle?

Overturning occurs on the roads when the trucks try to change directions, take sharp turns. Overturning occurs, more after, in case of vehicles which have greater height or whose center of gravity are much high up from the surface of roads.

How to Calculate Maximum velocity to avoid overturning of vehicle along level circular path?

Maximum velocity to avoid overturning of vehicle along level circular path calculator uses Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)) to calculate the Velocity, Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the speed at which a vehicle can travel around a circular path without overturning, taking into account the gravitational force, radius of the path, and weight distribution of the vehicle. Velocity is denoted by v symbol.

How to calculate Maximum velocity to avoid overturning of vehicle along level circular path using this online calculator? To use this online calculator for Maximum velocity to avoid overturning of vehicle along level circular path, enter Radius of Circular Path (r), Distance between Center Lines of two Wheels (d_w) & Gauge of Track (G) and hit the calculate button. Here is how the Maximum velocity to avoid overturning of vehicle along level circular path calculation can be explained with given input values -> 12.78453 = sqrt(([g]*100*1.5)/(2*0.2)).

FAQ

What is Maximum velocity to avoid overturning of vehicle along level circular path?

Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the speed at which a vehicle can travel around a circular path without overturning, taking into account the gravitational force, radius of the path, and weight distribution of the vehicle and is represented as v = sqrt(([g]*r*d_w)/(2*G)) or Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)). Radius of Circular Path is the distance from the center of a circular path to any point on the circle in general dynamics principles, Distance between Center Lines of two Wheels is the length between the center points of two wheels, considering general dynamics principles in motion & Gauge of Track is the measure of the distance between the inner edges of the rail in a railway track, crucial in general dynamics principles.

How to calculate Maximum velocity to avoid overturning of vehicle along level circular path?

Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the speed at which a vehicle can travel around a circular path without overturning, taking into account the gravitational force, radius of the path, and weight distribution of the vehicle is calculated using Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)). To calculate Maximum velocity to avoid overturning of vehicle along level circular path, you need Radius of Circular Path (r), Distance between Center Lines of two Wheels (d_w) & Gauge of Track (G). With our tool, you need to enter the respective value for Radius of Circular Path, Distance between Center Lines of two Wheels & Gauge of Track and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Velocity?

In this formula, Velocity uses Radius of Circular Path, Distance between Center Lines of two Wheels & Gauge of Track. We can use 1 other way(s) to calculate the same, which is/are as follows -

Velocity = sqrt(Coefficient of Friction between Wheels and Ground*[g]*Radius of Circular Path)

Home

FREE PDFs

🔍 Search