Maximum Height Attained by Object Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)
vmax = ((u*sin(θpr))^2)/(2*g)
This formula uses 1 Functions, 4 Variables
Functions Used
sin - Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse., sin(Angle)
Variables Used
Maximum Height of Crack - (Measured in Meter) - Maximum Height of Crack is the highest point reached by an object under the influence of gravity, friction, and other external forces during its motion.
Initial Velocity - (Measured in Meter per Second) - Initial Velocity is the velocity of an object at the start of a motion, describing the object's initial state of motion.
Angle of Projection - (Measured in Radian) - Angle of Projection is the angle at which an object is projected from the ground, influencing its trajectory and range of motion.
Acceleration due to Gravity - (Measured in Meter per Square Second) - Acceleration due to Gravity is the rate of change of velocity of an object under the influence of gravitational force, typically measured in meters per second squared.
STEP 1: Convert Input(s) to Base Unit
Initial Velocity: 35 Meter per Second --> 35 Meter per Second No Conversion Required
Angle of Projection: 0.4 Radian --> 0.4 Radian No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
vmax = ((u*sin(θpr))^2)/(2*g) --> ((35*sin(0.4))^2)/(2*9.8)
Evaluating ... ...
vmax = 9.47791533290108
STEP 3: Convert Result to Output's Unit
9.47791533290108 Meter --> No Conversion Required
FINAL ANSWER
9.47791533290108 9.477915 Meter <-- Maximum Height of Crack
(Calculation completed in 00.004 seconds)

Credits

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Created by Mayank Tayal
National Institute of Technology (NIT), Durgapur
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Verified by Anshika Arya
National Institute Of Technology (NIT), Hamirpur
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Projectile Motion Calculators

Maximum Height Attained for Inclined Projectile
​ LaTeX ​ Go Maximum Height = ((Initial Velocity*sin(Angle of Inclination))^2)/(2*Acceleration due to Gravity*cos(Angle of Plane))
Maximum Range of Flight for Inclined Projectile
​ LaTeX ​ Go Range of Motion = (Initial Velocity^2*(1-sin(Angle of Plane)))/(Acceleration due to Gravity*(cos(Angle of Plane))^2)
Time of Flight for Inclined Projectile
​ LaTeX ​ Go Time of Flight = (2*Initial Velocity*sin(Angle of Inclination))/(Acceleration due to Gravity*cos(Angle of Plane))
Maximum Height Attained by Object
​ LaTeX ​ Go Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)

Maximum Height Attained by Object Formula

​LaTeX ​Go
Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity)
vmax = ((u*sin(θpr))^2)/(2*g)

What is Projectile Motion ?

Projectile motion is a type of two-dimensional motion or motion in a plane. It is assumed that the only force acting on a projectile (the object experiencing projectile motion) is the force due to gravity.

How to Calculate Maximum Height Attained by Object?

Maximum Height Attained by Object calculator uses Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity) to calculate the Maximum Height of Crack, Maximum Height Attained by Object formula is defined as the highest point reached by an object under the sole influence of gravity, characterizing the maximum altitude achieved during its projectile motion. Maximum Height of Crack is denoted by vmax symbol.

How to calculate Maximum Height Attained by Object using this online calculator? To use this online calculator for Maximum Height Attained by Object, enter Initial Velocity (u), Angle of Projection pr) & Acceleration due to Gravity (g) and hit the calculate button. Here is how the Maximum Height Attained by Object calculation can be explained with given input values -> 9.477915 = ((35*sin(0.4))^2)/(2*9.8).

FAQ

What is Maximum Height Attained by Object?
Maximum Height Attained by Object formula is defined as the highest point reached by an object under the sole influence of gravity, characterizing the maximum altitude achieved during its projectile motion and is represented as vmax = ((u*sin(θpr))^2)/(2*g) or Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). Initial Velocity is the velocity of an object at the start of a motion, describing the object's initial state of motion, Angle of Projection is the angle at which an object is projected from the ground, influencing its trajectory and range of motion & Acceleration due to Gravity is the rate of change of velocity of an object under the influence of gravitational force, typically measured in meters per second squared.
How to calculate Maximum Height Attained by Object?
Maximum Height Attained by Object formula is defined as the highest point reached by an object under the sole influence of gravity, characterizing the maximum altitude achieved during its projectile motion is calculated using Maximum Height of Crack = ((Initial Velocity*sin(Angle of Projection))^2)/(2*Acceleration due to Gravity). To calculate Maximum Height Attained by Object, you need Initial Velocity (u), Angle of Projection pr) & Acceleration due to Gravity (g). With our tool, you need to enter the respective value for Initial Velocity, Angle of Projection & Acceleration due to Gravity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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