Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm Solution

STEP 0: Pre-Calculation Summary
Formula Used
Major Axis of Pulley Arm = (64*Area Moment of Inertia of Arms/(pi*Minor Axis of Pulley Arm))^(1/3)
ba = (64*I/(pi*a))^(1/3)
This formula uses 1 Constants, 3 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Major Axis of Pulley Arm - (Measured in Meter) - Major Axis of Pulley Arm is the length of the major or the largest axis of the elliptical cross-section of a pulley.
Area Moment of Inertia of Arms - (Measured in Meter⁴) - Area Moment of Inertia of Arms is the measure of the resistance of the arms of a part its angular acceleration about a given axis without considering its mass.
Minor Axis of Pulley Arm - (Measured in Meter) - Minor Axis of Pulley Arm is the length of the minor or the smallest axis of the elliptical cross-section of a pulley.
STEP 1: Convert Input(s) to Base Unit
Area Moment of Inertia of Arms: 17350 Millimeter⁴ --> 1.735E-08 Meter⁴ (Check conversion ​here)
Minor Axis of Pulley Arm: 13.66 Millimeter --> 0.01366 Meter (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ba = (64*I/(pi*a))^(1/3) --> (64*1.735E-08/(pi*0.01366))^(1/3)
Evaluating ... ...
ba = 0.0295773749594664
STEP 3: Convert Result to Output's Unit
0.0295773749594664 Meter -->29.5773749594664 Millimeter (Check conversion ​here)
FINAL ANSWER
29.5773749594664 29.57737 Millimeter <-- Major Axis of Pulley Arm
(Calculation completed in 00.004 seconds)

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Tangential Force at End of Each Arm of Pulley given Torque Transmitted by Pulley
​ LaTeX ​ Go Tangential Force at End of Each Pulley Arm = Torque Transmitted by Pulley/(Radius of Rim of Pulley*(Number of Arms in Pulley/2))
Radius of Rim of Pulley given Torque Transmitted by Pulley
​ LaTeX ​ Go Radius of Rim of Pulley = Torque Transmitted by Pulley/(Tangential Force at End of Each Pulley Arm*(Number of Arms in Pulley/2))
Number of Arms of Pulley given Torque Transmitted by Pulley
​ LaTeX ​ Go Number of Arms in Pulley = 2*Torque Transmitted by Pulley/(Tangential Force at End of Each Pulley Arm*Radius of Rim of Pulley)
Torque Transmitted by Pulley
​ LaTeX ​ Go Torque Transmitted by Pulley = Tangential Force at End of Each Pulley Arm*Radius of Rim of Pulley*(Number of Arms in Pulley/2)

Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm Formula

​LaTeX ​Go
Major Axis of Pulley Arm = (64*Area Moment of Inertia of Arms/(pi*Minor Axis of Pulley Arm))^(1/3)
ba = (64*I/(pi*a))^(1/3)

What is Moment of Inertia?

The moment of inertia, otherwise known as the mass moment of inertia, angular mass, second moment of mass, or most accurately, rotational inertia, of a rigid body is a quantity that determines the torque needed for a desired angular acceleration about a rotational axis, akin to how mass determines the force needed for a desired acceleration.

How to Calculate Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm?

Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm calculator uses Major Axis of Pulley Arm = (64*Area Moment of Inertia of Arms/(pi*Minor Axis of Pulley Arm))^(1/3) to calculate the Major Axis of Pulley Arm, Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm formula is defined as a method to determine the dimensions of a pulley arm's elliptical cross-section, which influences its mechanical performance and stability in belt drive systems. Major Axis of Pulley Arm is denoted by ba symbol.

How to calculate Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm using this online calculator? To use this online calculator for Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm, enter Area Moment of Inertia of Arms (I) & Minor Axis of Pulley Arm (a) and hit the calculate button. Here is how the Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm calculation can be explained with given input values -> 29577.37 = (64*1.735E-08/(pi*0.01366))^(1/3).

FAQ

What is Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm?
Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm formula is defined as a method to determine the dimensions of a pulley arm's elliptical cross-section, which influences its mechanical performance and stability in belt drive systems and is represented as ba = (64*I/(pi*a))^(1/3) or Major Axis of Pulley Arm = (64*Area Moment of Inertia of Arms/(pi*Minor Axis of Pulley Arm))^(1/3). Area Moment of Inertia of Arms is the measure of the resistance of the arms of a part its angular acceleration about a given axis without considering its mass & Minor Axis of Pulley Arm is the length of the minor or the smallest axis of the elliptical cross-section of a pulley.
How to calculate Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm?
Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm formula is defined as a method to determine the dimensions of a pulley arm's elliptical cross-section, which influences its mechanical performance and stability in belt drive systems is calculated using Major Axis of Pulley Arm = (64*Area Moment of Inertia of Arms/(pi*Minor Axis of Pulley Arm))^(1/3). To calculate Major Axis of Elliptical Cross-Section of Pulley's Arm given Moment of Inertia of Arm, you need Area Moment of Inertia of Arms (I) & Minor Axis of Pulley Arm (a). With our tool, you need to enter the respective value for Area Moment of Inertia of Arms & Minor Axis of Pulley Arm and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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