Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Wire DC is the measurement or extent of something from end to end.ⓘ Length of Wire DC [l]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖The Area of underground dc wire is the amount of two-dimensional space taken up by an object.ⓘ Area of underground dc wire [A]			+10% -10%
✖Maximum Voltage the highest voltage rating for electrical devices.ⓘ Maximum Voltage [V_m]			+10% -10%
✖Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.ⓘ Theta [θ]			+10% -10%

✖Line Losses is defined as the losses that are produced in the line.ⓘ Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) [P_line]

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Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))
P_line = (2*ρ*l*(P^2))/(A*(V_m^2*cos(θ)^2))
This formula uses 1 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Area of underground dc wire - (Measured in Square Meter) - The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Area of underground dc wire: 0.32 Square Meter --> 0.32 Square Meter No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_line = (2*ρ*l*(P^2))/(A*(V_m^2*cos(θ)^2)) --> (2*1.7E-05*3.2*(300^2))/(0.32*(60^2*cos(0.5235987755982)^2))

Evaluating ... ...

P_line = 0.0113333333333333

STEP 3: Convert Result to Output's Unit

0.0113333333333333 Watt --> No Conversion Required

FINAL ANSWER

0.0113333333333333 ≈ 0.011333 Watt <-- Line Losses

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)

LaTeX Go Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))

Length using Area of X-Section (2-Wire Mid-Point Earthed DC US)

LaTeX Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*(Power Transmitted^2)*Resistivity)

Line Losses using Volume of Conductor Material (2-Wire Mid-Point DC US)

LaTeX Go Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor)

Length using Volume of Conductor Material (2-Wire Mid-Point DC US)

LaTeX Go Length of Wire DC = sqrt((Volume Of Conductor*Line Losses)/(4*(Current underground DC^2)*(Resistivity)))

Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) Formula

LaTeX Go

Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2))
P_line = (2*ρ*l*(P^2))/(A*(V_m^2*cos(θ)^2))

What are transmission lines losses?

Depending on voltage and distance, transmission line losses range from two to five percent. increase system losses at every level. Transmission System Conductors. Long-distance transmission lines bring power from generators to the service territory of the distribution utility.

How to Calculate Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)?

Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) calculator uses Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2)) to calculate the Line Losses, The Line Losses using Area of X-Section (2-wire Mid-point earthed DC US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_line symbol.

How to calculate Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) using this online calculator? To use this online calculator for Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US), enter Resistivity (ρ), Length of Wire DC (l), Power Transmitted (P), Area of underground dc wire (A), Maximum Voltage (V_m) & Theta (θ) and hit the calculate button. Here is how the Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US) calculation can be explained with given input values -> 0.011333 = (2*1.7E-05*3.2*(300^2))/(0.32*(60^2*cos(0.5235987755982)^2)).

FAQ

What is Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)?

The Line Losses using Area of X-Section (2-wire Mid-point earthed DC US) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as P_line = (2*ρ*l*(P^2))/(A*(V_m^2*cos(θ)^2)) or Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Wire DC is the measurement or extent of something from end to end, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, The Area of underground dc wire is the amount of two-dimensional space taken up by an object, Maximum Voltage the highest voltage rating for electrical devices & Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.

How to calculate Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US)?

The Line Losses using Area of X-Section (2-wire Mid-point earthed DC US) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = (2*Resistivity*Length of Wire DC*(Power Transmitted^2))/(Area of underground dc wire*(Maximum Voltage^2*cos(Theta)^2)). To calculate Line Losses using Area of X-Section (2-Wire Mid-Point Earthed DC US), you need Resistivity (ρ), Length of Wire DC (l), Power Transmitted (P), Area of underground dc wire (A), Maximum Voltage (V_m) & Theta (θ). With our tool, you need to enter the respective value for Resistivity, Length of Wire DC, Power Transmitted, Area of underground dc wire, Maximum Voltage & Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Line Losses?

In this formula, Line Losses uses Resistivity, Length of Wire DC, Power Transmitted, Area of underground dc wire, Maximum Voltage & Theta. We can use 1 other way(s) to calculate the same, which is/are as follows -

Line Losses = 4*Resistivity*(Power Transmitted^2*Length of Wire DC^2)/(Maximum Voltage^2*Volume Of Conductor)

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