Line Losses using Area of X-Section (1-Phase 2-Wire US) Calculator

✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%

✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses using Area of X-Section (1-Phase 2-Wire US) [P_loss]

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Line Losses using Area of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2))
P_loss = (4*L*ρ*(P^2))/(A*(V_m^2)*((cos(Φ))^2))
This formula uses 1 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

STEP 1: Convert Input(s) to Base Unit

Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

P_loss = (4*L*ρ*(P^2))/(A*(V_m^2)*((cos(Φ))^2)) --> (4*24*1.7E-05*(300^2))/(1.28*(230^2)*((cos(0.5235987755982))^2))

Evaluating ... ...

P_loss = 0.00289224952741021

STEP 3: Convert Result to Output's Unit

0.00289224952741021 Watt --> No Conversion Required

FINAL ANSWER

0.00289224952741021 ≈ 0.002892 Watt <-- Line Losses

(Calculation completed in 00.020 seconds)

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< Line Parameters Calculators

Line Losses using Area of X-Section (1-Phase 2-Wire US)

LaTeX Go Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2))

Line Losses using Volume of Conductor Material (1-Phase 2-Wire US)

LaTeX Go Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Line Losses using Load Current (1-Phase 2-Wire US)

LaTeX Go Line Losses = 2*Resistance Underground AC*(Current Underground AC)^2

Line Losses (1-Phase 2-Wire US)

LaTeX Go Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC

Line Losses using Area of X-Section (1-Phase 2-Wire US) Formula

LaTeX Go

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Line Losses using Area of X-Section (1-Phase 2-Wire US)?

Line Losses using Area of X-Section (1-Phase 2-Wire US) calculator uses Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2)) to calculate the Line Losses, The Line Losses using Area of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by P_loss symbol.

How to calculate Line Losses using Area of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Line Losses using Area of X-Section (1-Phase 2-Wire US), enter Length of Underground AC Wire (L), Resistivity (ρ), Power Transmitted (P), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button. Here is how the Line Losses using Area of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.002892 = (4*24*1.7E-05*(300^2))/(1.28*(230^2)*((cos(0.5235987755982))^2)).

FAQ

What is Line Losses using Area of X-Section (1-Phase 2-Wire US)?

The Line Losses using Area of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as P_loss = (4*L*ρ*(P^2))/(A*(V_m^2)*((cos(Φ))^2)) or Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2)). Length of Underground AC Wire is the total length of the wire from one end to other end, Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

How to calculate Line Losses using Area of X-Section (1-Phase 2-Wire US)?

The Line Losses using Area of X-Section (1-Phase 2-Wire US) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = (4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*((cos(Phase Difference))^2)). To calculate Line Losses using Area of X-Section (1-Phase 2-Wire US), you need Length of Underground AC Wire (L), Resistivity (ρ), Power Transmitted (P), Area of Underground AC Wire (A), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ). With our tool, you need to enter the respective value for Length of Underground AC Wire, Resistivity, Power Transmitted, Area of Underground AC Wire, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Line Losses?

In this formula, Line Losses uses Length of Underground AC Wire, Resistivity, Power Transmitted, Area of Underground AC Wire, Maximum Voltage Underground AC & Phase Difference. We can use 3 other way(s) to calculate the same, which is/are as follows -

Line Losses = 2*(Current Underground AC^2)*Resistance Underground AC
Line Losses = 8*(Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)
Line Losses = 2*Resistance Underground AC*(Current Underground AC)^2

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