Line Losses using Area of X-Section(Single-Phase Two-Wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Line Losses = (4*Length of Overhead AC Wire*Resistivity*(Power Transmitted^2))/(Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2))
Ploss = (4*L*ρ*(P^2))/(A*(Vm^2)*((cos(Φ))^2))
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end.
Area of Overhead AC Wire - (Measured in Square Meter) - Area of Overhead AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Overhead AC - (Measured in Volt) - Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 890 Watt --> 890 Watt No Conversion Required
Area of Overhead AC Wire: 0.79 Square Meter --> 0.79 Square Meter No Conversion Required
Maximum Voltage Overhead AC: 62 Volt --> 62 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion ​here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ploss = (4*L*ρ*(P^2))/(A*(Vm^2)*((cos(Φ))^2)) --> (4*10.63*1.7E-05*(890^2))/(0.79*(62^2)*((cos(0.5235987755982))^2))
Evaluating ... ...
Ploss = 0.2513914233152
STEP 3: Convert Result to Output's Unit
0.2513914233152 Watt --> No Conversion Required
FINAL ANSWER
0.2513914233152 0.251391 Watt <-- Line Losses
(Calculation completed in 00.004 seconds)

Credits

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Created by Urvi Rathod
Vishwakarma Government Engineering College (VGEC), Ahmedabad
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Wire Parameters Calculators

Area of X-Section(Single-Phase Two-Wire OS)
​ LaTeX ​ Go Area of Overhead AC Wire = (4*(Power Transmitted^2)*Resistivity*Length of Overhead AC Wire)/(((cos(Phase Difference))^2)*Line Losses*(Voltage Overhead AC^2))
Constant(Single-Phase Two-Wire OS)
​ LaTeX ​ Go Constant Overhead AC = (4*(Power Transmitted^2)*Resistivity*Length of Overhead AC Wire)/(Line Losses*(Voltage Overhead AC^2))
Volume of Conductor Material(Single-Phase Two-Wire OS)
​ LaTeX ​ Go Volume of Conductor = 2*Area of Overhead AC Wire*Length of Overhead AC Wire
Line Losses(Single-Phase Two-Wire OS)
​ LaTeX ​ Go Line Losses = (2)*((Current Overhead AC)^2)*Resistance Overhead AC

Line Losses using Area of X-Section(Single-Phase Two-Wire OS) Formula

​LaTeX ​Go
Line Losses = (4*Length of Overhead AC Wire*Resistivity*(Power Transmitted^2))/(Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2))
Ploss = (4*L*ρ*(P^2))/(A*(Vm^2)*((cos(Φ))^2))

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Line Losses using Area of X-Section(Single-Phase Two-Wire OS)?

Line Losses using Area of X-Section(Single-Phase Two-Wire OS) calculator uses Line Losses = (4*Length of Overhead AC Wire*Resistivity*(Power Transmitted^2))/(Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2)) to calculate the Line Losses, The Line Losses using Area of X-section(single-phase two-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by Ploss symbol.

How to calculate Line Losses using Area of X-Section(Single-Phase Two-Wire OS) using this online calculator? To use this online calculator for Line Losses using Area of X-Section(Single-Phase Two-Wire OS), enter Length of Overhead AC Wire (L), Resistivity (ρ), Power Transmitted (P), Area of Overhead AC Wire (A), Maximum Voltage Overhead AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Line Losses using Area of X-Section(Single-Phase Two-Wire OS) calculation can be explained with given input values -> 0.251391 = (4*10.63*1.7E-05*(890^2))/(0.79*(62^2)*((cos(0.5235987755982))^2)).

FAQ

What is Line Losses using Area of X-Section(Single-Phase Two-Wire OS)?
The Line Losses using Area of X-section(single-phase two-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as Ploss = (4*L*ρ*(P^2))/(A*(Vm^2)*((cos(Φ))^2)) or Line Losses = (4*Length of Overhead AC Wire*Resistivity*(Power Transmitted^2))/(Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2)). Length of Overhead AC Wire is the total length of the wire from one end to other end, Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end, Area of Overhead AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Line Losses using Area of X-Section(Single-Phase Two-Wire OS)?
The Line Losses using Area of X-section(single-phase two-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = (4*Length of Overhead AC Wire*Resistivity*(Power Transmitted^2))/(Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2)). To calculate Line Losses using Area of X-Section(Single-Phase Two-Wire OS), you need Length of Overhead AC Wire (L), Resistivity (ρ), Power Transmitted (P), Area of Overhead AC Wire (A), Maximum Voltage Overhead AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Length of Overhead AC Wire, Resistivity, Power Transmitted, Area of Overhead AC Wire, Maximum Voltage Overhead AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Line Losses?
In this formula, Line Losses uses Length of Overhead AC Wire, Resistivity, Power Transmitted, Area of Overhead AC Wire, Maximum Voltage Overhead AC & Phase Difference. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Line Losses = (2)*((Current Overhead AC)^2)*Resistance Overhead AC
  • Line Losses = 2*Resistance Overhead AC*(Current Overhead AC)^2
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