Length using Load Current (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)
L = (Ploss*A)/(2*(I)^2*ρ)
This formula uses 5 Variables
Variables Used
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
STEP 1: Convert Input(s) to Base Unit
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
L = (Ploss*A)/(2*(I)^2*ρ) --> (2.67*1.28)/(2*(9)^2*1.7E-05)
Evaluating ... ...
L = 1240.95860566449
STEP 3: Convert Result to Output's Unit
1240.95860566449 Meter --> No Conversion Required
FINAL ANSWER
1240.95860566449 1240.959 Meter <-- Length of Underground AC Wire
(Calculation completed in 00.020 seconds)

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Wire Parameters Calculators

Area of X-Section (1-Phase 2-Wire US)
​ LaTeX ​ Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Constant (1-Phase 2-Wire US)
​ LaTeX ​ Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)
Voltage of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)
​ LaTeX ​ Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Length using Load Current (1-Phase 2-Wire US) Formula

​LaTeX ​Go
Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)
L = (Ploss*A)/(2*(I)^2*ρ)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Length using Load Current (1-Phase 2-Wire US)?

Length using Load Current (1-Phase 2-Wire US) calculator uses Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity) to calculate the Length of Underground AC Wire, The Length using Load Current (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system. Length of Underground AC Wire is denoted by L symbol.

How to calculate Length using Load Current (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Length using Load Current (1-Phase 2-Wire US), enter Line Losses (Ploss), Area of Underground AC Wire (A), Current Underground AC (I) & Resistivity (ρ) and hit the calculate button. Here is how the Length using Load Current (1-Phase 2-Wire US) calculation can be explained with given input values -> 1240.959 = (2.67*1.28)/(2*(9)^2*1.7E-05).

FAQ

What is Length using Load Current (1-Phase 2-Wire US)?
The Length using Load Current (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system and is represented as L = (Ploss*A)/(2*(I)^2*ρ) or Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity). Line Losses is defined as the total losses occurring in an Underground AC line when in use, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Current Underground AC is defined as the current flowing through the overhead ac supply wire & Resistivity is the measure of how strongly a material opposes the flow of current through them.
How to calculate Length using Load Current (1-Phase 2-Wire US)?
The Length using Load Current (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system is calculated using Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity). To calculate Length using Load Current (1-Phase 2-Wire US), you need Line Losses (Ploss), Area of Underground AC Wire (A), Current Underground AC (I) & Resistivity (ρ). With our tool, you need to enter the respective value for Line Losses, Area of Underground AC Wire, Current Underground AC & Resistivity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Length of Underground AC Wire?
In this formula, Length of Underground AC Wire uses Line Losses, Area of Underground AC Wire, Current Underground AC & Resistivity. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
  • Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
  • Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
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