Jet velocity given temperature drop Calculator

✖Specific heat at constant pressure is the energy required to raise the temperature of the unit mass of a substance by one degree as the pressure is maintained constant.ⓘ Specific Heat at Constant Pressure [C_p]			+10% -10%
✖Temperature Drop is the difference between two temperatures.ⓘ Temperature Drop [ΔT]			+10% -10%

✖Ideal Exit Velocity is the velocity at the exit of nozzle, it does not includes losses due to external factors.ⓘ Jet velocity given temperature drop [C_ideal]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Propulsion Formula PDF PDF Image

Jet velocity given temperature drop Solution

STEP 0: Pre-Calculation Summary

Formula Used

Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop)
C_ideal = sqrt(2*C_p*ΔT)
This formula uses 1 Functions, 3 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Ideal Exit Velocity - (Measured in Meter per Second) - Ideal Exit Velocity is the velocity at the exit of nozzle, it does not includes losses due to external factors.
Specific Heat at Constant Pressure - (Measured in Joule per Kilogram per K) - Specific heat at constant pressure is the energy required to raise the temperature of the unit mass of a substance by one degree as the pressure is maintained constant.
Temperature Drop - (Measured in Kelvin) - Temperature Drop is the difference between two temperatures.

STEP 1: Convert Input(s) to Base Unit

Specific Heat at Constant Pressure: 1248 Joule per Kilogram per K --> 1248 Joule per Kilogram per K No Conversion Required
Temperature Drop: 16 Kelvin --> 16 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

C_ideal = sqrt(2*C_p*ΔT) --> sqrt(2*1248*16)

Evaluating ... ...

C_ideal = 199.839935948749

STEP 3: Convert Result to Output's Unit

199.839935948749 Meter per Second --> No Conversion Required

FINAL ANSWER

199.839935948749 ≈ 199.8399 Meter per Second <-- Ideal Exit Velocity

(Calculation completed in 00.004 seconds)

You are here -

Home » Physics » Propulsion » Components of Gas Turbine » Aerospace » Nozzle » Jet velocity given temperature drop

Credits

Created by Chilvera Bhanu Teja

Institute of Aeronautical Engineering (IARE), Hyderabad

Chilvera Bhanu Teja has created this Calculator and 300+ more calculators!

Verified by Sagar S Kulkarni

Dayananda Sagar College of Engineering (DSCE), Bengaluru

Sagar S Kulkarni has verified this Calculator and 200+ more calculators!

< Nozzle Calculators

Kinetic Energy of Exhaust Gases

LaTeX Go Kinetic Energy of Gas = 1/2*Ideal Mass Flow Rate*(1+Fuel to Air Ratio)*Ideal Exit Velocity^2

Jet velocity given temperature drop

LaTeX Go Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop)

Ideal Exhaust Velocity given Enthalpy Drop

LaTeX Go Ideal Exit Velocity = sqrt(2*Enthalpy Drop in Nozzle)

Velocity Coefficient given Nozzle Efficiency

LaTeX Go Velocity Coefficient = sqrt(Nozzle Efficiency)

Jet velocity given temperature drop Formula

LaTeX Go

Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop)
C_ideal = sqrt(2*C_p*ΔT)

What is enthalpy?

Enthalpy is a property of a thermodynamic system, defined as the sum of the system's internal energy and the product of its pressure and volume.

How to Calculate Jet velocity given temperature drop?

Jet velocity given temperature drop calculator uses Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop) to calculate the Ideal Exit Velocity, The Jet velocity given temperature drop formula is defined as the square root of 2 times the product of specific heat at constant pressure and temperature drop. Ideal Exit Velocity is denoted by C_ideal symbol.

How to calculate Jet velocity given temperature drop using this online calculator? To use this online calculator for Jet velocity given temperature drop, enter Specific Heat at Constant Pressure (C_p) & Temperature Drop (ΔT) and hit the calculate button. Here is how the Jet velocity given temperature drop calculation can be explained with given input values -> 193.4942 = sqrt(2*1248*16).

FAQ

What is Jet velocity given temperature drop?

The Jet velocity given temperature drop formula is defined as the square root of 2 times the product of specific heat at constant pressure and temperature drop and is represented as C_ideal = sqrt(2*C_p*ΔT) or Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop). Specific heat at constant pressure is the energy required to raise the temperature of the unit mass of a substance by one degree as the pressure is maintained constant & Temperature Drop is the difference between two temperatures.

How to calculate Jet velocity given temperature drop?

The Jet velocity given temperature drop formula is defined as the square root of 2 times the product of specific heat at constant pressure and temperature drop is calculated using Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Temperature Drop). To calculate Jet velocity given temperature drop, you need Specific Heat at Constant Pressure (C_p) & Temperature Drop (ΔT). With our tool, you need to enter the respective value for Specific Heat at Constant Pressure & Temperature Drop and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Ideal Exit Velocity?

In this formula, Ideal Exit Velocity uses Specific Heat at Constant Pressure & Temperature Drop. We can use 2 other way(s) to calculate the same, which is/are as follows -

Ideal Exit Velocity = sqrt(2*Enthalpy Drop in Nozzle)
Ideal Exit Velocity = sqrt(2*Specific Heat at Constant Pressure*Nozzle Temperature*(1-(Pressure Ratio)^((Specific Heat Ratio-1)/(Specific Heat Ratio))))

Home

FREE PDFs

🔍 Search