Interchange factor for two rectangles with common side at right angles to each other Solution

STEP 0: Pre-Calculation Summary
Formula Used
Interchange Factor = Emissivity of Body 1*Emissivity of Body 2
f1-2 = ε1*ε2
This formula uses 3 Variables
Variables Used
Interchange Factor - The Interchange Factor is a measure of the efficiency of heat transfer between two surfaces through radiation, influencing thermal performance in mechanical systems.
Emissivity of Body 1 - The Emissivity of Body 1 is a measure of how effectively the surface emits thermal radiation compared to a perfect black body at the same temperature.
Emissivity of Body 2 - The Emissivity of Body 2 is a measure of how effectively the surface emits thermal radiation compared to a perfect black body at the same temperature.
STEP 1: Convert Input(s) to Base Unit
Emissivity of Body 1: 0.4 --> No Conversion Required
Emissivity of Body 2: 0.3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
f1-2 = ε12 --> 0.4*0.3
Evaluating ... ...
f1-2 = 0.12
STEP 3: Convert Result to Output's Unit
0.12 --> No Conversion Required
FINAL ANSWER
0.12 <-- Interchange Factor
(Calculation completed in 00.004 seconds)

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Shri Govindram Seksaria Institute of Technology and Science (SGSITS), Indore
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Interchange Factor between Surfaces Calculators

Interchange factor for infinitely long concentric cylinders
​ LaTeX ​ Go Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)
Interchange factor for infinitely long concentric spheres
​ LaTeX ​ Go Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)
Interchange Factor for Infinite parallel planes
​ LaTeX ​ Go Interchange Factor = ((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)^(-1)
Interchange factor for two rectangles with common side at right angles to each other
​ LaTeX ​ Go Interchange Factor = Emissivity of Body 1*Emissivity of Body 2

Interchange factor for two rectangles with common side at right angles to each other Formula

​LaTeX ​Go
Interchange Factor = Emissivity of Body 1*Emissivity of Body 2
f1-2 = ε1*ε2

What is Interchange Factor?

Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body. It is also known as the Equivalent Emissivity.

What is Emissivity?

Emissivity is defined as the ratio of the energy radiated from a material's surface to that radiated from a perfect emitter known as a blackbody, at the same temperature and wavelength and under the same viewing conditions. It is a dimensionless number between 0 (for a perfect reflector) and 1 (for a perfect emitter).

How to Calculate Interchange factor for two rectangles with common side at right angles to each other?

Interchange factor for two rectangles with common side at right angles to each other calculator uses Interchange Factor = Emissivity of Body 1*Emissivity of Body 2 to calculate the Interchange Factor, Interchange factor for two rectangles with common side at right angles to each other formula is defined as a measure of the energy exchange between two rectangular surfaces that share a common side perpendicular to each other, used to calculate the radiative heat transfer between them in radiation heat transfer analysis. Interchange Factor is denoted by f1-2 symbol.

How to calculate Interchange factor for two rectangles with common side at right angles to each other using this online calculator? To use this online calculator for Interchange factor for two rectangles with common side at right angles to each other, enter Emissivity of Body 1 1) & Emissivity of Body 2 2) and hit the calculate button. Here is how the Interchange factor for two rectangles with common side at right angles to each other calculation can be explained with given input values -> 0.12 = 0.4*0.3.

FAQ

What is Interchange factor for two rectangles with common side at right angles to each other?
Interchange factor for two rectangles with common side at right angles to each other formula is defined as a measure of the energy exchange between two rectangular surfaces that share a common side perpendicular to each other, used to calculate the radiative heat transfer between them in radiation heat transfer analysis and is represented as f1-2 = ε12 or Interchange Factor = Emissivity of Body 1*Emissivity of Body 2. The Emissivity of Body 1 is a measure of how effectively the surface emits thermal radiation compared to a perfect black body at the same temperature & The Emissivity of Body 2 is a measure of how effectively the surface emits thermal radiation compared to a perfect black body at the same temperature.
How to calculate Interchange factor for two rectangles with common side at right angles to each other?
Interchange factor for two rectangles with common side at right angles to each other formula is defined as a measure of the energy exchange between two rectangular surfaces that share a common side perpendicular to each other, used to calculate the radiative heat transfer between them in radiation heat transfer analysis is calculated using Interchange Factor = Emissivity of Body 1*Emissivity of Body 2. To calculate Interchange factor for two rectangles with common side at right angles to each other, you need Emissivity of Body 1 1) & Emissivity of Body 2 2). With our tool, you need to enter the respective value for Emissivity of Body 1 & Emissivity of Body 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Interchange Factor?
In this formula, Interchange Factor uses Emissivity of Body 1 & Emissivity of Body 2. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Interchange Factor = ((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)^(-1)
  • Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)
  • Interchange Factor = ((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))^(-1)
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