Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces Solution

STEP 0: Pre-Calculation Summary
Formula Used
Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)
q = (A*[Stefan-BoltZ]*((T1^4)-(T2^4)))/((1/ε1)+(1/ε2)-1)
This formula uses 1 Constants, 6 Variables
Constants Used
[Stefan-BoltZ] - Stefan-Boltzmann Constant Value Taken As 5.670367E-8
Variables Used
Heat Transfer - (Measured in Watt) - Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second).
Area - (Measured in Square Meter) - The area is the amount of two-dimensional space taken up by an object.
Temperature of Surface 1 - (Measured in Kelvin) - Temperature of Surface 1 is the temperature of the 1st surface.
Temperature of Surface 2 - (Measured in Kelvin) - Temperature of Surface 2 is the temperature of the 2nd surface.
Emissivity of Body 1 - The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Emissivity of Body 2 - The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
STEP 1: Convert Input(s) to Base Unit
Area: 50.3 Square Meter --> 50.3 Square Meter No Conversion Required
Temperature of Surface 1: 202 Kelvin --> 202 Kelvin No Conversion Required
Temperature of Surface 2: 151 Kelvin --> 151 Kelvin No Conversion Required
Emissivity of Body 1: 0.4 --> No Conversion Required
Emissivity of Body 2: 0.3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
q = (A*[Stefan-BoltZ]*((T1^4)-(T2^4)))/((1/ε1)+(1/ε2)-1) --> (50.3*[Stefan-BoltZ]*((202^4)-(151^4)))/((1/0.4)+(1/0.3)-1)
Evaluating ... ...
q = 675.722755500347
STEP 3: Convert Result to Output's Unit
675.722755500347 Watt --> No Conversion Required
FINAL ANSWER
675.722755500347 675.7228 Watt <-- Heat Transfer
(Calculation completed in 00.004 seconds)

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Radiation Heat Transfer Calculators

Net Heat Exchange given Area 1 and Shape Factor 12
​ LaTeX ​ Go Net Heat Transfer = Surface Area of Body 1*Radiation Shape Factor 12*(Emissive Power of 1st Blackbody-Emissive Power of 2nd Blackbody)
Net Heat Exchange given Area 2 and Shape Factor 21
​ LaTeX ​ Go Net Heat Transfer = Surface Area of Body 2*Radiation Shape Factor 21*(Emissive Power of 1st Blackbody-Emissive Power of 2nd Blackbody)
Net Heat Exchange between Two Surfaces given Radiosity for Both Surface
​ LaTeX ​ Go Radiation Heat Transfer = (Radiosity of 1st Body-Radiosity of 2nd Body)/(1/(Surface Area of Body 1*Radiation Shape Factor 12))
Net Heat Transfer from Surface given Emissivity, Radiosity and Emissive Power
​ LaTeX ​ Go Heat Transfer = (((Emissivity*Area)*(Emissive Power of Blackbody-Radiosity))/(1-Emissivity))

Important Formulas in Radiation Heat Transfer Calculators

Area of Surface 1 given Area 2 and Radiation Shape Factor for Both Surfaces
​ LaTeX ​ Go Surface Area of Body 1 = Surface Area of Body 2*(Radiation Shape Factor 21/Radiation Shape Factor 12)
Area of Surface 2 given Area 1 and Radiation Shape Factor for Both Surfaces
​ LaTeX ​ Go Surface Area of Body 2 = Surface Area of Body 1*(Radiation Shape Factor 12/Radiation Shape Factor 21)
Emissive Power of Blackbody
​ LaTeX ​ Go Emissive Power of Blackbody = [Stefan-BoltZ]*(Temperature of Blackbody^4)
Absorptivity given Reflectivity and Transmissivity
​ LaTeX ​ Go Absorptivity = 1-Reflectivity-Transmissivity

Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces Formula

​LaTeX ​Go
Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1)
q = (A*[Stefan-BoltZ]*((T1^4)-(T2^4)))/((1/ε1)+(1/ε2)-1)

What is Radiation?

Radiation is energy that comes from a source and travels through space at the speed of light. This energy has an electric field and a magnetic field associated with it, and has wave-like properties. You could also call radiation “electromagnetic waves”.

What is Emissivity?

Emissivity is defined as the ratio of the energy radiated from a material's surface to that radiated from a perfect emitter, known as a blackbody, at the same temperature and wavelength and under the same viewing conditions. It is a dimensionless number between 0 (for a perfect reflector) and 1 (for a perfect emitter).

How to Calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?

Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces calculator uses Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1) to calculate the Heat Transfer, The Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces formula is defined as the function of area of heat transfer, temperature of both the bodies, emissivity of both the bodies. Heat Transfer is denoted by q symbol.

How to calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces using this online calculator? To use this online calculator for Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces, enter Area (A), Temperature of Surface 1 (T1), Temperature of Surface 2 (T2), Emissivity of Body 1 1) & Emissivity of Body 2 2) and hit the calculate button. Here is how the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces calculation can be explained with given input values -> 675.7228 = (50.3*[Stefan-BoltZ]*((202^4)-(151^4)))/((1/0.4)+(1/0.3)-1).

FAQ

What is Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?
The Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces formula is defined as the function of area of heat transfer, temperature of both the bodies, emissivity of both the bodies and is represented as q = (A*[Stefan-BoltZ]*((T1^4)-(T2^4)))/((1/ε1)+(1/ε2)-1) or Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1). The area is the amount of two-dimensional space taken up by an object, Temperature of Surface 1 is the temperature of the 1st surface, Temperature of Surface 2 is the temperature of the 2nd surface, The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter & The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
How to calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?
The Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces formula is defined as the function of area of heat transfer, temperature of both the bodies, emissivity of both the bodies is calculated using Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1). To calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces, you need Area (A), Temperature of Surface 1 (T1), Temperature of Surface 2 (T2), Emissivity of Body 1 1) & Emissivity of Body 2 2). With our tool, you need to enter the respective value for Area, Temperature of Surface 1, Temperature of Surface 2, Emissivity of Body 1 & Emissivity of Body 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Heat Transfer?
In this formula, Heat Transfer uses Area, Temperature of Surface 1, Temperature of Surface 2, Emissivity of Body 1 & Emissivity of Body 2. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Heat Transfer = (((Emissivity*Area)*(Emissive Power of Blackbody-Radiosity))/(1-Emissivity))
  • Heat Transfer = (([Stefan-BoltZ]*Surface Area of Body 1*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))))/((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1)))
  • Heat Transfer = Surface Area of Body 1*Emissivity of Body 1*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))
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