Head1 given Time Required to Lower Liquid for Triangular Notch Calculator

✖Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head on Downstream of Weir [h₂]			+10% -10%
✖Time interval is the time duration between two events/entities of interest.ⓘ Time Interval [Δt]			+10% -10%
✖The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.ⓘ Coefficient of Discharge [C_d]			+10% -10%
✖The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.ⓘ Acceleration due to Gravity [g]			+10% -10%
✖Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.ⓘ Theta [θ]			+10% -10%
✖Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.ⓘ Cross-Sectional Area of Reservoir [A_R]			+10% -10%

✖Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head1 given Time Required to Lower Liquid for Triangular Notch [H_Upstream]

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Head1 given Time Required to Lower Liquid for Triangular Notch Solution

STEP 0: Pre-Calculation Summary

Formula Used

Head on Upstream of Weir = (1/((1/Head on Downstream of Weir^(3/2))-((Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*Cross-Sectional Area of Reservoir))))^(2/3)
H_Upstream = (1/((1/h₂^(3/2))-((Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*A_R))))^(2/3)
This formula uses 2 Functions, 7 Variables

Functions Used

tan - The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle., tan(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Head on Upstream of Weir - (Measured in Meter) - Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
Head on Downstream of Weir - (Measured in Meter) - Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
Time Interval - (Measured in Second) - Time interval is the time duration between two events/entities of interest.
Coefficient of Discharge - The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.
Acceleration due to Gravity - (Measured in Meter per Square Second) - The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
Cross-Sectional Area of Reservoir - (Measured in Square Meter) - Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.

STEP 1: Convert Input(s) to Base Unit

Head on Downstream of Weir: 5.1 Meter --> 5.1 Meter No Conversion Required
Time Interval: 1.25 Second --> 1.25 Second No Conversion Required
Coefficient of Discharge: 0.66 --> No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Cross-Sectional Area of Reservoir: 13 Square Meter --> 13 Square Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

H_Upstream = (1/((1/h₂^(3/2))-((Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*A_R))))^(2/3) --> (1/((1/5.1^(3/2))-((1.25*(8/15)*0.66*sqrt(2*9.8)*tan(0.5235987755982/2))/((2/3)*13))))^(2/3)

Evaluating ... ...

H_Upstream = 11.2223927927199

STEP 3: Convert Result to Output's Unit

11.2223927927199 Meter --> No Conversion Required

FINAL ANSWER

11.2223927927199 ≈ 11.22239 Meter <-- Head on Upstream of Weir

(Calculation completed in 00.004 seconds)

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< Time Required to Empty a Reservoir with Rectangular Weir Calculators

Coefficient of Discharge for Time Required to Lower Liquid Surface

LaTeX Go Coefficient of Discharge = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Length of Crest for time required to Lower Liquid Surface

LaTeX Go Length of Weir Crest = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Time Interval))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Time Required to Lower Liquid Surface

LaTeX Go Time Interval = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Cross Sectional Area given Time required to Lower Liquid Surface

LaTeX Go Cross-Sectional Area of Reservoir = (Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))

Head1 given Time Required to Lower Liquid for Triangular Notch Formula

LaTeX Go

What is meant by Coefficient of Discharge?

Coefficient of Discharge is the ratio of the actual discharge to the theoretical discharge, i.e., the ratio of the mass flow rate at the discharge end.

How to Calculate Head1 given Time Required to Lower Liquid for Triangular Notch?

Head1 given Time Required to Lower Liquid for Triangular Notch calculator uses Head on Upstream of Weir = (1/((1/Head on Downstream of Weir^(3/2))-((Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*Cross-Sectional Area of Reservoir))))^(2/3) to calculate the Head on Upstream of Weir, Head1 given Time Required to Lower Liquid for Triangular Notch in fluid dynamics, head is concept that relates energy in incompressible fluid to height of equivalent static column. Head on Upstream of Weir is denoted by H_Upstream symbol.

How to calculate Head1 given Time Required to Lower Liquid for Triangular Notch using this online calculator? To use this online calculator for Head1 given Time Required to Lower Liquid for Triangular Notch, enter Head on Downstream of Weir (h₂), Time Interval (Δt), Coefficient of Discharge (C_d), Acceleration due to Gravity (g), Theta (θ) & Cross-Sectional Area of Reservoir (A_R) and hit the calculate button. Here is how the Head1 given Time Required to Lower Liquid for Triangular Notch calculation can be explained with given input values -> 11.22239 = (1/((1/5.1^(3/2))-((1.25*(8/15)*0.66*sqrt(2*9.8)*tan(0.5235987755982/2))/((2/3)*13))))^(2/3).

FAQ

What is Head1 given Time Required to Lower Liquid for Triangular Notch?

Head1 given Time Required to Lower Liquid for Triangular Notch in fluid dynamics, head is concept that relates energy in incompressible fluid to height of equivalent static column and is represented as H_Upstream = (1/((1/h₂^(3/2))-((Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*A_R))))^(2/3) or Head on Upstream of Weir = (1/((1/Head on Downstream of Weir^(3/2))-((Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*Cross-Sectional Area of Reservoir))))^(2/3). Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures, Time interval is the time duration between two events/entities of interest, The Coefficient of Discharge is ratio of actual discharge to theoretical discharge, The Acceleration due to Gravity is acceleration gained by an object because of gravitational force, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint & Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.

How to calculate Head1 given Time Required to Lower Liquid for Triangular Notch?

Head1 given Time Required to Lower Liquid for Triangular Notch in fluid dynamics, head is concept that relates energy in incompressible fluid to height of equivalent static column is calculated using Head on Upstream of Weir = (1/((1/Head on Downstream of Weir^(3/2))-((Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*Cross-Sectional Area of Reservoir))))^(2/3). To calculate Head1 given Time Required to Lower Liquid for Triangular Notch, you need Head on Downstream of Weir (h₂), Time Interval (Δt), Coefficient of Discharge (C_d), Acceleration due to Gravity (g), Theta (θ) & Cross-Sectional Area of Reservoir (A_R). With our tool, you need to enter the respective value for Head on Downstream of Weir, Time Interval, Coefficient of Discharge, Acceleration due to Gravity, Theta & Cross-Sectional Area of Reservoir and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Head on Upstream of Weir?

In this formula, Head on Upstream of Weir uses Head on Downstream of Weir, Time Interval, Coefficient of Discharge, Acceleration due to Gravity, Theta & Cross-Sectional Area of Reservoir. We can use 2 other way(s) to calculate the same, which is/are as follows -

Head on Upstream of Weir = ((1/((1/sqrt(Head on Downstream of Weir))-(Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*Cross-Sectional Area of Reservoir)))^2)
Head on Upstream of Weir = ((1/((Time Interval*Bazins Coefficient*sqrt(2*Acceleration due to Gravity))/(2*Cross-Sectional Area of Reservoir)-(1/sqrt(Head on Downstream of Weir))))^2)

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