What is Liquid-Liquid Extraction?
Liquid–liquid extraction (LLE), also known as solvent extraction, is a method to separate compounds or metal complexes, based on their relative solubilities in two different immiscible liquids, usually water (polar) and an organic solvent (non-polar). There is a net transfer of one or more species from one liquid into another liquid phase, generally from aqueous to organic. The transfer is driven by chemical potential, i.e. once the transfer is complete, the overall system of chemical components that make up the solutes and the solvents are in a more stable configuration (lower free energy). The solvent that is enriched in solute(s) is called extract. The feed solution that is depleted in solute(s) is called the raffinate.
How to Calculate Feed Solute Concentration for Single Ideal Stage Extraction?
Feed Solute Concentration for Single Ideal Stage Extraction calculator uses Mass Fraction of Solute in the Feed = Single Stage Mass Fraction of Solute in Raffinate/(Solute Free Feed Flowrate in Extraction/(Solute Free Feed Flowrate in Extraction+(Solute Free Extract Phase Flowrate in LLE*Distribution Coefficient of Solute))) to calculate the Mass Fraction of Solute in the Feed, The Feed Solute Concentration for Single Ideal Stage Extraction formula is defined as the mass fraction of solute in feed as the function of the raffinate mass fraction of solute coming out of a Single Equilibrium Stage Extraction Process. Mass Fraction of Solute in the Feed is denoted by zC symbol.
How to calculate Feed Solute Concentration for Single Ideal Stage Extraction using this online calculator? To use this online calculator for Feed Solute Concentration for Single Ideal Stage Extraction, enter Single Stage Mass Fraction of Solute in Raffinate (X1), Solute Free Feed Flowrate in Extraction (F'), Solute Free Extract Phase Flowrate in LLE (E') & Distribution Coefficient of Solute (KSolute) and hit the calculate button. Here is how the Feed Solute Concentration for Single Ideal Stage Extraction calculation can be explained with given input values -> 0.499994 = 0.2028/(110/(110+(62*2.6))).