What is Duhem’s Theorem?
For any closed system formed from known amounts of prescribed chemical species, the equilibrium state is completely determined when any two independent variables are fixed. The two independent variables subject to specification may in general be either intensive or extensive. However, the number of independent intensive variables is given by the phase rule. Thus when F = 1, at least one of the two variables must be extensive, and when F = 0, both must be extensive.
How to Calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions?
Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions calculator uses Excess Gibbs Free Energy = ([R]*Temperature of Liquid Vapour System)*(Mole Fraction of Component 1 in Liquid Phase*ln(Activity Coefficient of Component 1)+Mole Fraction of Component 2 in Liquid Phase*ln(Activity Coefficient of Component 2)) to calculate the Excess Gibbs Free Energy, The Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions formula is defined as the product of the universal gas constant, temperature and the summation of the product of the mole fraction of i th component and the natural logarithm of the activity coefficient of component i, where for binary system i = 2. Excess Gibbs Free Energy is denoted by GE symbol.
How to calculate Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions using this online calculator? To use this online calculator for Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions, enter Temperature of Liquid Vapour System (TVLE), Mole Fraction of Component 1 in Liquid Phase (x1), Activity Coefficient of Component 1 (γ1), Mole Fraction of Component 2 in Liquid Phase (x2) & Activity Coefficient of Component 2 (γ2) and hit the calculate button. Here is how the Excess Gibbs Free Energy using Activity Coefficients and Liquid Mole Fractions calculation can be explained with given input values -> 388.7319 = ([R]*400)*(0.4*ln(1.13)+0.6*ln(1.12)).