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Enthalpy using Integrated Form of Clausius-Clapeyron Equation Calculator

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✖Final Pressure of System is the total final pressure exerted by the molecules inside the system.ⓘ Final Pressure of System [P_f]			+10% -10%
✖Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.ⓘ Initial Pressure of System [P_i]			+10% -10%
✖The Final temperature is the temperature at which measurements are made in final state.ⓘ Final Temperature [T_f]			+10% -10%
✖The Initial temperature is defined as the measure of heat under initial state or conditions.ⓘ Initial Temperature [T_i]			+10% -10%

✖Change in enthalpy is the thermodynamic quantity equivalent to the total difference between the heat content of a system.ⓘ Enthalpy using Integrated Form of Clausius-Clapeyron Equation [ΔH]

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Enthalpy using Integrated Form of Clausius-Clapeyron Equation Solution

STEP 0: Pre-Calculation Summary

Formula Used

Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature))
ΔH = (-ln(P_f/P_i)*[R])/((1/T_f)-(1/T_i))
This formula uses 1 Constants, 1 Functions, 5 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Functions Used

ln - The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function., ln(Number)

Variables Used

Change in Enthalpy - (Measured in Joule per Kilogram) - Change in enthalpy is the thermodynamic quantity equivalent to the total difference between the heat content of a system.
Final Pressure of System - (Measured in Pascal) - Final Pressure of System is the total final pressure exerted by the molecules inside the system.
Initial Pressure of System - (Measured in Pascal) - Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.
Final Temperature - (Measured in Kelvin) - The Final temperature is the temperature at which measurements are made in final state.
Initial Temperature - (Measured in Kelvin) - The Initial temperature is defined as the measure of heat under initial state or conditions.

STEP 1: Convert Input(s) to Base Unit

Final Pressure of System: 133.07 Pascal --> 133.07 Pascal No Conversion Required
Initial Pressure of System: 65 Pascal --> 65 Pascal No Conversion Required
Final Temperature: 700 Kelvin --> 700 Kelvin No Conversion Required
Initial Temperature: 600 Kelvin --> 600 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ΔH = (-ln(P_f/P_i)*[R])/((1/T_f)-(1/T_i)) --> (-ln(133.07/65)*[R])/((1/700)-(1/600))

Evaluating ... ...

ΔH = 25020.2945531668

STEP 3: Convert Result to Output's Unit

25020.2945531668 Joule per Kilogram --> No Conversion Required

FINAL ANSWER

25020.2945531668 ≈ 25020.29 Joule per Kilogram <-- Change in Enthalpy

(Calculation completed in 00.004 seconds)

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< Clausius Clapeyron Equation Calculators

Final Temperature using Integrated Form of Clausius-Clapeyron Equation

LaTeX Go Final Temperature = 1/((-(ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Initial Temperature))

Temperature for Transitions

LaTeX Go Temperature = -Latent Heat/((ln(Pressure)-Integration Constant)*[R])

Pressure for Transitions between Gas and Condensed Phase

LaTeX Go Pressure = exp(-Latent Heat/([R]*Temperature))+Integration Constant

August Roche Magnus Formula

LaTeX Go Saturation Vapour Pressure = 6.1094*exp((17.625*Temperature)/(Temperature+243.04))

< Important Formulas of Clausius Clapeyron Equation Calculators

August Roche Magnus Formula

LaTeX Go Saturation Vapour Pressure = 6.1094*exp((17.625*Temperature)/(Temperature+243.04))

Boiling Point using Trouton's Rule given Specific Latent Heat

LaTeX Go Boiling Point = (Specific Latent Heat*Molecular Weight)/(10.5*[R])

Boiling Point using Trouton's Rule given Latent Heat

LaTeX Go Boiling Point = Latent Heat/(10.5*[R])

Boiling Point given Enthalpy using Trouton's Rule

LaTeX Go Boiling Point = Enthalpy/(10.5*[R])

Enthalpy using Integrated Form of Clausius-Clapeyron Equation Formula

LaTeX Go

Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature))
ΔH = (-ln(P_f/P_i)*[R])/((1/T_f)-(1/T_i))

What is the Clausius–Clapeyron relation?

The Clausius–Clapeyron relation, named after Rudolf Clausius and Benoît Paul Émile Clapeyron, is a way of characterizing a discontinuous phase transition between two phases of matter of a single constituent. On a pressure–temperature (P–T) diagram, the line separating the two phases is known as the coexistence curve. The Clausius–Clapeyron relation gives the slope of the tangents to this curve.

How to Calculate Enthalpy using Integrated Form of Clausius-Clapeyron Equation?

Enthalpy using Integrated Form of Clausius-Clapeyron Equation calculator uses Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)) to calculate the Change in Enthalpy, The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system. Change in Enthalpy is denoted by ΔH symbol.

How to calculate Enthalpy using Integrated Form of Clausius-Clapeyron Equation using this online calculator? To use this online calculator for Enthalpy using Integrated Form of Clausius-Clapeyron Equation, enter Final Pressure of System (P_f), Initial Pressure of System (P_i), Final Temperature (T_f) & Initial Temperature (T_i) and hit the calculate button. Here is how the Enthalpy using Integrated Form of Clausius-Clapeyron Equation calculation can be explained with given input values -> -44014.366316 = (-ln(133.07/65)*[R])/((1/700)-(1/600)).

FAQ

What is Enthalpy using Integrated Form of Clausius-Clapeyron Equation?

The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system and is represented as ΔH = (-ln(P_f/P_i)*[R])/((1/T_f)-(1/T_i)) or Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)). Final Pressure of System is the total final pressure exerted by the molecules inside the system, Initial Pressure of System is the total initial pressure exerted by the molecules inside the system, The Final temperature is the temperature at which measurements are made in final state & The Initial temperature is defined as the measure of heat under initial state or conditions.

How to calculate Enthalpy using Integrated Form of Clausius-Clapeyron Equation?

The Enthalpy using integrated form of Clausius-Clapeyron Equation is the difference in heat on the final and initial state of the system is calculated using Change in Enthalpy = (-ln(Final Pressure of System/Initial Pressure of System)*[R])/((1/Final Temperature)-(1/Initial Temperature)). To calculate Enthalpy using Integrated Form of Clausius-Clapeyron Equation, you need Final Pressure of System (P_f), Initial Pressure of System (P_i), Final Temperature (T_f) & Initial Temperature (T_i). With our tool, you need to enter the respective value for Final Pressure of System, Initial Pressure of System, Final Temperature & Initial Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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