Enthalpy of Chemical Reaction at Absolute Temperatures Solution

STEP 0: Pre-Calculation Summary
Formula Used
Enthalpy of Reaction = log10(Equilibrium constant 2/Equilibrium constant 1)*(2.303*[R])*((Absolute Temperature*Absolute temperature 2)/(Absolute temperature 2-Absolute Temperature))
ΔH = log10(K2/K1)*(2.303*[R])*((Tabs*T2)/(T2-Tabs))
This formula uses 1 Constants, 1 Functions, 5 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Functions Used
log10 - The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function., log10(Number)
Variables Used
Enthalpy of Reaction - (Measured in Joule Per Mole) - The Enthalpy of Reaction is the difference in enthalpy between products and reactants.
Equilibrium constant 2 - Equilibrium constant 2 is the value of its reaction quotient at chemical equilibrium, at absolute temperature T2.
Equilibrium constant 1 - Equilibrium constant 1 is the value of its reaction quotient at chemical equilibrium, at absolute temperature T1.
Absolute Temperature - (Measured in Kelvin) - Absolute Temperature is defined as the measurement of temperature beginning at absolute zero on the Kelvin scale.
Absolute temperature 2 - (Measured in Kelvin) - Absolute temperature 2 is the temperature of an object on a scale where 0 is taken as absolute zero.
STEP 1: Convert Input(s) to Base Unit
Equilibrium constant 2: 0.0431 --> No Conversion Required
Equilibrium constant 1: 0.026 --> No Conversion Required
Absolute Temperature: 273.15 Kelvin --> 273.15 Kelvin No Conversion Required
Absolute temperature 2: 310 Kelvin --> 310 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ΔH = log10(K2/K1)*(2.303*[R])*((Tabs*T2)/(T2-Tabs)) --> log10(0.0431/0.026)*(2.303*[R])*((273.15*310)/(310-273.15))
Evaluating ... ...
ΔH = 9658.19154673446
STEP 3: Convert Result to Output's Unit
9658.19154673446 Joule Per Mole -->9.65819154673446 KiloJoule Per Mole (Check conversion ​here)
FINAL ANSWER
9.65819154673446 9.658192 KiloJoule Per Mole <-- Enthalpy of Reaction
(Calculation completed in 00.004 seconds)

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​ LaTeX ​ Go Forward Pre-exponential Factor = Forward reaction rate constant/exp(-(Activation Energy Forward/([R]*Absolute Temperature)))
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​ LaTeX ​ Go Forward reaction rate constant = Forward Pre-exponential Factor*exp(-(Activation Energy Forward/([R]*Absolute Temperature)))
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Pre-exponential Factor in Arrhenius Equation
​ LaTeX ​ Go Pre-Exponential Factor = Rate Constant/exp(-(Activation Energy/([R]*Absolute Temperature)))

Enthalpy of Chemical Reaction at Absolute Temperatures Formula

​LaTeX ​Go
Enthalpy of Reaction = log10(Equilibrium constant 2/Equilibrium constant 1)*(2.303*[R])*((Absolute Temperature*Absolute temperature 2)/(Absolute temperature 2-Absolute Temperature))
ΔH = log10(K2/K1)*(2.303*[R])*((Tabs*T2)/(T2-Tabs))

What do you mean by activation energy?

Activation energy, in chemistry, the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation or physical transport. In transition-state theory, the activation energy is the difference in energy content between atoms or molecules in an activated or transition-state configuration and the corresponding atoms and molecules in their initial configuration. The activation energy is usually represented by the symbol Ea in mathematical expressions for such quantities as the reaction rate constant, k.

How to Calculate Enthalpy of Chemical Reaction at Absolute Temperatures?

Enthalpy of Chemical Reaction at Absolute Temperatures calculator uses Enthalpy of Reaction = log10(Equilibrium constant 2/Equilibrium constant 1)*(2.303*[R])*((Absolute Temperature*Absolute temperature 2)/(Absolute temperature 2-Absolute Temperature)) to calculate the Enthalpy of Reaction, The Enthalpy of chemical reaction at absolute temperatures is defined as the difference in activation energy between products and reactants for forward and backward reactions at absolute temperatures T1 and T2. Enthalpy of Reaction is denoted by ΔH symbol.

How to calculate Enthalpy of Chemical Reaction at Absolute Temperatures using this online calculator? To use this online calculator for Enthalpy of Chemical Reaction at Absolute Temperatures, enter Equilibrium constant 2 (K2), Equilibrium constant 1 (K1), Absolute Temperature (Tabs) & Absolute temperature 2 (T2) and hit the calculate button. Here is how the Enthalpy of Chemical Reaction at Absolute Temperatures calculation can be explained with given input values -> 0.009658 = log10(0.0431/0.026)*(2.303*[R])*((273.15*310)/(310-273.15)).

FAQ

What is Enthalpy of Chemical Reaction at Absolute Temperatures?
The Enthalpy of chemical reaction at absolute temperatures is defined as the difference in activation energy between products and reactants for forward and backward reactions at absolute temperatures T1 and T2 and is represented as ΔH = log10(K2/K1)*(2.303*[R])*((Tabs*T2)/(T2-Tabs)) or Enthalpy of Reaction = log10(Equilibrium constant 2/Equilibrium constant 1)*(2.303*[R])*((Absolute Temperature*Absolute temperature 2)/(Absolute temperature 2-Absolute Temperature)). Equilibrium constant 2 is the value of its reaction quotient at chemical equilibrium, at absolute temperature T2, Equilibrium constant 1 is the value of its reaction quotient at chemical equilibrium, at absolute temperature T1, Absolute Temperature is defined as the measurement of temperature beginning at absolute zero on the Kelvin scale & Absolute temperature 2 is the temperature of an object on a scale where 0 is taken as absolute zero.
How to calculate Enthalpy of Chemical Reaction at Absolute Temperatures?
The Enthalpy of chemical reaction at absolute temperatures is defined as the difference in activation energy between products and reactants for forward and backward reactions at absolute temperatures T1 and T2 is calculated using Enthalpy of Reaction = log10(Equilibrium constant 2/Equilibrium constant 1)*(2.303*[R])*((Absolute Temperature*Absolute temperature 2)/(Absolute temperature 2-Absolute Temperature)). To calculate Enthalpy of Chemical Reaction at Absolute Temperatures, you need Equilibrium constant 2 (K2), Equilibrium constant 1 (K1), Absolute Temperature (Tabs) & Absolute temperature 2 (T2). With our tool, you need to enter the respective value for Equilibrium constant 2, Equilibrium constant 1, Absolute Temperature & Absolute temperature 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Enthalpy of Reaction?
In this formula, Enthalpy of Reaction uses Equilibrium constant 2, Equilibrium constant 1, Absolute Temperature & Absolute temperature 2. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Enthalpy of Reaction = Activation Energy Forward-Activation Energy Backward
  • Enthalpy of Reaction = -(log10(Equilibrium constant 2/Equilibrium constant 1)*[R]*((Absolute Temperature*Absolute temperature 2)/(Absolute Temperature-Absolute temperature 2)))
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