Depression Head in Well given Pumping Stopped and Constant with Base 10 Solution

STEP 0: Pre-Calculation Summary
Formula Used
Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303))
hd = hw2*10^((K*t)/(Acs*2.303))
This formula uses 5 Variables
Variables Used
Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Constant - Constant depending on the soil at the base of the well.
Time - (Measured in Hour) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross Sectional Area - (Measured in Square Meter) - Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.
STEP 1: Convert Input(s) to Base Unit
Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required
Constant: 5 --> No Conversion Required
Time: 4 Hour --> 4 Hour No Conversion Required
Cross Sectional Area: 20 Square Meter --> 20 Square Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
hd = hw2*10^((K*t)/(Acs*2.303)) --> 10*10^((5*4)/(20*2.303))
Evaluating ... ...
hd = 27.177921486562
STEP 3: Convert Result to Output's Unit
27.177921486562 Meter --> No Conversion Required
FINAL ANSWER
27.177921486562 27.17792 Meter <-- Depression Head
(Calculation completed in 00.004 seconds)

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Depression Head when Pumping Stopped Calculators

Depression Head in well given pumping stopped and clay soil is present
​ LaTeX ​ Go Depression Head = Depression Head in Well 2*exp(0.25*Total Time Interval)
Depression Head in Well given Pumping Stopped and Fine Sand is Present
​ LaTeX ​ Go Depression Head = Depression Head in Well 2*exp(0.5*Time Interval)
Depression Head in Well given Pumping Stopped and Coarse Sand is Present
​ LaTeX ​ Go Depression Head = Depression Head in Well 2*exp(1*Time Interval)
Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present
​ LaTeX ​ Go Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula

​LaTeX ​Go
Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303))
hd = hw2*10^((K*t)/(Acs*2.303))

What is Specific Capacity?

Specific Capacity refers to the efficiency of a well in producing water. It is a measure of how much water (in volume) a well can yield per unit of drawdown (or drop in water level) over a specific period of time. The specific capacity is typically expressed in units such as gallons per minute per foot (gpm/ft) or liters per second per meter (L/s/m).

How to Calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?

Depression Head in Well given Pumping Stopped and Constant with Base 10 calculator uses Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)) to calculate the Depression Head, The Depression Head in Well given Pumping Stopped and Constant with Base 10 formula is defined as the calculation of the value of depression head in well when we have prior information of other parameters used. Depression Head is denoted by hd symbol.

How to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10 using this online calculator? To use this online calculator for Depression Head in Well given Pumping Stopped and Constant with Base 10, enter Depression Head in Well 2 (hw2), Constant (K), Time (t) & Cross Sectional Area (Acs) and hit the calculate button. Here is how the Depression Head in Well given Pumping Stopped and Constant with Base 10 calculation can be explained with given input values -> 27.17792 = 10*10^((5*14400)/(20*2.303)).

FAQ

What is Depression Head in Well given Pumping Stopped and Constant with Base 10?
The Depression Head in Well given Pumping Stopped and Constant with Base 10 formula is defined as the calculation of the value of depression head in well when we have prior information of other parameters used and is represented as hd = hw2*10^((K*t)/(Acs*2.303)) or Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)). Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped, Constant depending on the soil at the base of the well, Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future & Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.
How to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?
The Depression Head in Well given Pumping Stopped and Constant with Base 10 formula is defined as the calculation of the value of depression head in well when we have prior information of other parameters used is calculated using Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)). To calculate Depression Head in Well given Pumping Stopped and Constant with Base 10, you need Depression Head in Well 2 (hw2), Constant (K), Time (t) & Cross Sectional Area (Acs). With our tool, you need to enter the respective value for Depression Head in Well 2, Constant, Time & Cross Sectional Area and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Depression Head?
In this formula, Depression Head uses Depression Head in Well 2, Constant, Time & Cross Sectional Area. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Depression Head = Depression Head in Well 2*exp(0.25*Total Time Interval)
  • Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)
  • Depression Head = Depression Head in Well 2*exp(0.5*Time Interval)
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