Degree of Dissociation when Number of Moles is 2 Solution

STEP 0: Pre-Calculation Summary
Formula Used
Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density
𝝰 = (D-d)/d
This formula uses 3 Variables
Variables Used
Degree of Dissociation - The Degree of Dissociation is the extent of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.
Initial Vapour Density - Initial Vapour Density is the density of a vapour substance during the initial stages of reaction.
Equilibrium Vapour Density - Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.
STEP 1: Convert Input(s) to Base Unit
Initial Vapour Density: 250 --> No Conversion Required
Equilibrium Vapour Density: 150 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
𝝰 = (D-d)/d --> (250-150)/150
Evaluating ... ...
𝝰 = 0.666666666666667
STEP 3: Convert Result to Output's Unit
0.666666666666667 --> No Conversion Required
FINAL ANSWER
0.666666666666667 0.666667 <-- Degree of Dissociation
(Calculation completed in 00.005 seconds)

Credits

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Created by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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College Of Engineering (COEP), Pune
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Degree of Dissociation Calculators

Degree of Dissociation using Concentration of Reaction
​ LaTeX ​ Go Degree of Dissociation = ((Initial Vapour Density*Initial Concentration)/(Equilibrium Vapour Density*Initial Concentration))-1
Degree of Dissociation using Initial Vapour Density and Vapour Density at Equilibrium
​ LaTeX ​ Go Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density*(Number of Moles-1)
Degree of Dissociation given Number of Moles at Equilibrium
​ LaTeX ​ Go Degree of Dissociation = (Number of Moles at Equilibrium-1)/(Number of Moles-1)
Degree of Dissociation given Initial Vapor Density
​ LaTeX ​ Go Degree of Dissociation = (Initial Vapour Density/Equilibrium Vapour Density)-1

Degree of Dissociation when Number of Moles is 2 Formula

​LaTeX ​Go
Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density
𝝰 = (D-d)/d

What is Degree of Dissociation?

The fraction of the initial molecules that are converted at equilibrium is called the degree of Dissociation/ionization. It is unit less. The degree of dissociation is the phenomenon of generating current carrying free ions, which are dissociated from the fraction of solute at a given concentration.

How to Calculate Degree of Dissociation when Number of Moles is 2?

Degree of Dissociation when Number of Moles is 2 calculator uses Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density to calculate the Degree of Dissociation, The Degree of dissociation when number of moles is 2 formula is defined as the fraction of the total number of molecules which associate or combine together resulting in the formation of a bigger molecules in equilibrium when there are only 2 moles present in the reaction. Degree of Dissociation is denoted by 𝝰 symbol.

How to calculate Degree of Dissociation when Number of Moles is 2 using this online calculator? To use this online calculator for Degree of Dissociation when Number of Moles is 2, enter Initial Vapour Density (D) & Equilibrium Vapour Density (d) and hit the calculate button. Here is how the Degree of Dissociation when Number of Moles is 2 calculation can be explained with given input values -> 0.666667 = (250-150)/150.

FAQ

What is Degree of Dissociation when Number of Moles is 2?
The Degree of dissociation when number of moles is 2 formula is defined as the fraction of the total number of molecules which associate or combine together resulting in the formation of a bigger molecules in equilibrium when there are only 2 moles present in the reaction and is represented as 𝝰 = (D-d)/d or Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density. Initial Vapour Density is the density of a vapour substance during the initial stages of reaction & Equilibrium Vapour Density is the density of a vapour substance during the stages of reaction at equilibrium.
How to calculate Degree of Dissociation when Number of Moles is 2?
The Degree of dissociation when number of moles is 2 formula is defined as the fraction of the total number of molecules which associate or combine together resulting in the formation of a bigger molecules in equilibrium when there are only 2 moles present in the reaction is calculated using Degree of Dissociation = (Initial Vapour Density-Equilibrium Vapour Density)/Equilibrium Vapour Density. To calculate Degree of Dissociation when Number of Moles is 2, you need Initial Vapour Density (D) & Equilibrium Vapour Density (d). With our tool, you need to enter the respective value for Initial Vapour Density & Equilibrium Vapour Density and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Degree of Dissociation?
In this formula, Degree of Dissociation uses Initial Vapour Density & Equilibrium Vapour Density. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Degree of Dissociation = (Initial Vapour Density/Equilibrium Vapour Density)-1
  • Degree of Dissociation = (Number of Moles at Equilibrium-1)/(Number of Moles-1)
  • Degree of Dissociation = ((Initial Vapour Density*Initial Concentration)/(Equilibrium Vapour Density*Initial Concentration))-1
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