Energy Loss in Hydraulic Jump given Mean Velocities Calculator

✖Depth of Point 2 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid.ⓘ Depth of Point 2 for Rectangular Channel [d_2R]			+10% -10%
✖Depth of Point 1 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid.ⓘ Depth of Point 1 for Rectangular Channel [d_1R]			+10% -10%
✖Mean velocity of a fluid in a pipe or channel normally means the flow rate divided by the cross-sectional area of the flow.ⓘ Mean velocity [v_m]			+10% -10%

✖Energy loss for Rectangular Channel is the loss of energy of flowing water.ⓘ Energy Loss in Hydraulic Jump given Mean Velocities [S_r]

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Energy Loss in Hydraulic Jump given Mean Velocities Solution

STEP 0: Pre-Calculation Summary

Formula Used

Energy loss for Rectangular Channel = ((Depth of Point 2 for Rectangular Channel-Depth of Point 1 for Rectangular Channel)^3)/(4*Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)*Mean velocity
S_r = ((d_2R-d_1R)^3)/(4*d_1R*d_2R)*v_m
This formula uses 4 Variables

Variables Used

Energy loss for Rectangular Channel - (Measured in Joule) - Energy loss for Rectangular Channel is the loss of energy of flowing water.
Depth of Point 2 for Rectangular Channel - (Measured in Meter) - Depth of Point 2 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid.
Depth of Point 1 for Rectangular Channel - (Measured in Meter) - Depth of Point 1 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid.
Mean velocity - (Measured in Meter per Second) - Mean velocity of a fluid in a pipe or channel normally means the flow rate divided by the cross-sectional area of the flow.

STEP 1: Convert Input(s) to Base Unit

Depth of Point 2 for Rectangular Channel: 1.2 Meter --> 1.2 Meter No Conversion Required
Depth of Point 1 for Rectangular Channel: 1.1 Meter --> 1.1 Meter No Conversion Required
Mean velocity: 1.1 Meter per Second --> 1.1 Meter per Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

S_r = ((d_2R-d_1R)^3)/(4*d_1R*d_2R)*v_m --> ((1.2-1.1)^3)/(4*1.1*1.2)*1.1

Evaluating ... ...

S_r = 0.000208333333333332

STEP 3: Convert Result to Output's Unit

0.000208333333333332 Joule --> No Conversion Required

FINAL ANSWER

0.000208333333333332 ≈ 0.000208 Joule <-- Energy loss for Rectangular Channel

(Calculation completed in 00.004 seconds)

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National Institute of Technology Karnataka (NITK), Surathkal

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< Hydraulic Jump in Rectangular Channel Calculators

Conjugate Depth y1 given Discharge per Unit Width of Channel

LaTeX Go Depth of Point 1 for Rectangular Channel = 0.5*Depth of Point 2 for Rectangular Channel*(-1+sqrt(1+(8*(Discharge per Unit Width^2))/([g]*Depth of Point 2 for Rectangular Channel*Depth of Point 2 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)))

Conjugate Depth y2 given Discharge per Unit Width of Channel

LaTeX Go Depth of Point 2 for Rectangular Channel = 0.5*Depth of Point 1 for Rectangular Channel*(-1+sqrt(1+(8*(Discharge per Unit Width^2))/([g]*Depth of Point 1 for Rectangular Channel*Depth of Point 1 for Rectangular Channel*Depth of Point 1 for Rectangular Channel)))

Discharge Per Unit Width of Channel given Conjugate Depths

LaTeX Go Discharge per Unit Width = sqrt((Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel*(Depth of Point 1 for Rectangular Channel+Depth of Point 2 for Rectangular Channel))*[g]*0.5)

Conjugate Depth y2 given Critical Depth

LaTeX Go Depth of Point 2 for Rectangular Channel = 0.5*Depth of Point 1 for Rectangular Channel*(-1+sqrt(1+(8*(Critical Depth of Weir^3))/(Depth of Point 1 for Rectangular Channel^3)))

Energy Loss in Hydraulic Jump given Mean Velocities Formula

LaTeX Go

What is Hydraulic Jump?

A hydraulic jump is a phenomenon in the science of hydraulics which is frequently observed in open channel flow such as rivers and spillways. When liquid at high velocity discharges into a zone of lower velocity, a rather abrupt rise occurs in the liquid surface.

How to Calculate Energy Loss in Hydraulic Jump given Mean Velocities?

Energy Loss in Hydraulic Jump given Mean Velocities calculator uses Energy loss for Rectangular Channel = ((Depth of Point 2 for Rectangular Channel-Depth of Point 1 for Rectangular Channel)^3)/(4*Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)*Mean velocity to calculate the Energy loss for Rectangular Channel, The Energy Loss in Hydraulic Jump given Mean Velocities is defined as the amount of energy lost in the gradually varied flow in the channel of the stream. Energy loss for Rectangular Channel is denoted by S_r symbol.

How to calculate Energy Loss in Hydraulic Jump given Mean Velocities using this online calculator? To use this online calculator for Energy Loss in Hydraulic Jump given Mean Velocities, enter Depth of Point 2 for Rectangular Channel (d_2R), Depth of Point 1 for Rectangular Channel (d_1R) & Mean velocity (v_m) and hit the calculate button. Here is how the Energy Loss in Hydraulic Jump given Mean Velocities calculation can be explained with given input values -> 0.000208 = ((1.2-1.1)^3)/(4*1.1*1.2)*1.1.

FAQ

What is Energy Loss in Hydraulic Jump given Mean Velocities?

The Energy Loss in Hydraulic Jump given Mean Velocities is defined as the amount of energy lost in the gradually varied flow in the channel of the stream and is represented as S_r = ((d_2R-d_1R)^3)/(4*d_1R*d_2R)*v_m or Energy loss for Rectangular Channel = ((Depth of Point 2 for Rectangular Channel-Depth of Point 1 for Rectangular Channel)^3)/(4*Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)*Mean velocity. Depth of Point 2 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid, Depth of Point 1 for Rectangular Channel is the depth of point below the free surface in a static mass of liquid & Mean velocity of a fluid in a pipe or channel normally means the flow rate divided by the cross-sectional area of the flow.

How to calculate Energy Loss in Hydraulic Jump given Mean Velocities?

The Energy Loss in Hydraulic Jump given Mean Velocities is defined as the amount of energy lost in the gradually varied flow in the channel of the stream is calculated using Energy loss for Rectangular Channel = ((Depth of Point 2 for Rectangular Channel-Depth of Point 1 for Rectangular Channel)^3)/(4*Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)*Mean velocity. To calculate Energy Loss in Hydraulic Jump given Mean Velocities, you need Depth of Point 2 for Rectangular Channel (d_2R), Depth of Point 1 for Rectangular Channel (d_1R) & Mean velocity (v_m). With our tool, you need to enter the respective value for Depth of Point 2 for Rectangular Channel, Depth of Point 1 for Rectangular Channel & Mean velocity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Energy loss for Rectangular Channel?

In this formula, Energy loss for Rectangular Channel uses Depth of Point 2 for Rectangular Channel, Depth of Point 1 for Rectangular Channel & Mean velocity. We can use 1 other way(s) to calculate the same, which is/are as follows -

Energy loss for Rectangular Channel = ((Depth of Point 2 for Rectangular Channel-Depth of Point 1 for Rectangular Channel)^3)/(4*Depth of Point 1 for Rectangular Channel*Depth of Point 2 for Rectangular Channel)

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