LCM of two numbers

Enantiomeric Excess Calculator

Chemistry Engineering Financial Health More >>

↳

Organic Chemistry Analytical chemistry Atmospheric Chemistry Atomic structure More >>

⤿

Optical Activity Isomerism

✖Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of R [F_R]			+10% -10%
✖Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.ⓘ Mole Fraction of S [F_S]			+10% -10%

✖Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer.ⓘ Enantiomeric Excess [ee]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Chemistry Formula PDF PDF Image

Enantiomeric Excess Solution

STEP 0: Pre-Calculation Summary

Formula Used

Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)
ee = abs(F_R-F_S)
This formula uses 1 Functions, 3 Variables

Functions Used

abs - The absolute value of a number is its distance from zero on the number line. It's always a positive value, as it represents the magnitude of a number without considering its direction., abs(Number)

Variables Used

Enantiomeric Excess - Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer.
Mole Fraction of R - Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.
Mole Fraction of S - Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

STEP 1: Convert Input(s) to Base Unit

Mole Fraction of R: 0.7 --> No Conversion Required
Mole Fraction of S: 0.3 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ee = abs(F_R-F_S) --> abs(0.7-0.3)

Evaluating ... ...

ee = 0.4

STEP 3: Convert Result to Output's Unit

0.4 --> No Conversion Required

FINAL ANSWER

0.4 <-- Enantiomeric Excess

(Calculation completed in 00.004 seconds)

You are here -

Home » Chemistry » Organic Chemistry » Optical Activity » Enantiomeric Excess

Credits

Created by Sangita Kalita

National Institute of Technology, Manipur (NIT Manipur), Imphal, Manipur

Sangita Kalita has created this Calculator and 50+ more calculators!

Verified by Soupayan banerjee

National University of Judicial Science (NUJS), Kolkata

Soupayan banerjee has verified this Calculator and 900+ more calculators!

< Optical Activity Calculators

Specific Rotation of Optically Active Compound

LaTeX Go Specific Rotation = Observed Rotation/(Length Of Sample Tube*Concentration of Solution in Polarimeter)

Percent Enantiomeric Excess

LaTeX Go Percent Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)*100

Enantiomeric Excess

LaTeX Go Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)

Optical Purity

LaTeX Go Optical Purity = (Observed Specific Rotation/Maximum Specific Rotation)*100

Enantiomeric Excess Formula

LaTeX Go

Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S)
ee = abs(F_R-F_S)

What are R and S?

To name the enantiomers of a compound unambiguously, their names must include the "handedness" of the molecule. The method for this is formally known as R/S nomenclature. The letters "R" and "S" are determined by applying the Cahn-Ingold-Prelog (CIP) rules. The optical activity (+/-) can also be communicated in the name, but must be empirically derived.

How to Calculate Enantiomeric Excess?

Enantiomeric Excess calculator uses Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S) to calculate the Enantiomeric Excess, The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer. Enantiomeric Excess is denoted by ee symbol.

How to calculate Enantiomeric Excess using this online calculator? To use this online calculator for Enantiomeric Excess, enter Mole Fraction of R (F_R) & Mole Fraction of S (F_S) and hit the calculate button. Here is how the Enantiomeric Excess calculation can be explained with given input values -> 0.4 = abs(0.7-0.3).

FAQ

What is Enantiomeric Excess?

The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer and is represented as ee = abs(F_R-F_S) or Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture & Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

How to calculate Enantiomeric Excess?

The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer is calculated using Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). To calculate Enantiomeric Excess, you need Mole Fraction of R (F_R) & Mole Fraction of S (F_S). With our tool, you need to enter the respective value for Mole Fraction of R & Mole Fraction of S and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

Home

FREE PDFs

🔍 Search