✖Net Work Output is defined as the difference of work of turbine and work of compressor.ⓘ Net Work Output [W_Net]			+10% -10%
✖Heat refers to the transfer of thermal energy between systems or objects due to a temperature difference.ⓘ Heat [Q]			+10% -10%

✖Efficiency of Joule Cycle is the ratio of network output to heat supplied.ⓘ Efficiency of Joule cycle [η_{joule cycle}]

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Efficiency of Joule cycle

Formula

`"η"_{"joule cycle"} = "W"_{"Net"}/"Q"`

Example

`"0.5"="305KJ"/"610KJ"`

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Efficiency of Joule cycle Solution

STEP 0: Pre-Calculation Summary

Formula Used

Efficiency of Joule Cycle = Net Work Output/Heat
η_{joule cycle} = W_Net/Q
This formula uses 3 Variables

Variables Used

Efficiency of Joule Cycle - Efficiency of Joule Cycle is the ratio of network output to heat supplied.
Net Work Output - (Measured in Joule) - Net Work Output is defined as the difference of work of turbine and work of compressor.
Heat - (Measured in Joule) - Heat refers to the transfer of thermal energy between systems or objects due to a temperature difference.

STEP 1: Convert Input(s) to Base Unit

Net Work Output: 305 Kilojoule --> 305000 Joule (Check conversion here)
Heat: 610 Kilojoule --> 610000 Joule (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

η_{joule cycle} = W_Net/Q --> 305000/610000

Evaluating ... ...

η_{joule cycle} = 0.5

STEP 3: Convert Result to Output's Unit

0.5 --> No Conversion Required

FINAL ANSWER

0.5 <-- Efficiency of Joule Cycle

(Calculation completed in 00.004 seconds)

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< 19 Thermodynamics and Governing Equations Calculators

Max work output in Brayton cycle

Go Maximum Work done in Brayton Cycle = (1005*1/Compressor Efficiency)*Temperature at Inlet of Compressor in Brayton*(sqrt(Temperature at Inlet to Turbine in Brayton Cycle/Temperature at Inlet of Compressor in Brayton*Compressor Efficiency*Turbine Efficiency)-1)^2

Choked Mass Flow Rate given specific heat ratio

Go Choked Mass Flow Rate = (Specific Heat Ratio/(sqrt(Specific Heat Ratio-1)))*((Specific Heat Ratio+1)/2)^(-((Specific Heat Ratio+1)/(2*Specific Heat Ratio-2)))

Choked Mass Flow Rate

Go Choked Mass Flow Rate = (Mass Flow Rate*sqrt(Specific Heat Capacity at Constant Pressure*Temperature))/(Nozzle Throat Area*Throat Pressure)

Stagnation Velocity of Sound given Specific Heat at Constant Pressure

Go Stagnation Velocity of Sound = sqrt((Specific Heat Ratio-1)*Specific Heat Capacity at Constant Pressure*Stagnation Temperature)

Specific Heat of mixed out gas

Go Specific Heat of Mixed Gas = (Specific Heat of Core Gas+Bypass Ratio*Specific Heat of Bypass Air)/(1+Bypass Ratio)

Stagnation Temperature

Go Stagnation Temperature = Static Temperature+(Velocity of Fluid Flow^2)/(2*Specific Heat Capacity at Constant Pressure)

Stagnation Velocity of Sound

Go Stagnation Velocity of Sound = sqrt(Specific Heat Ratio*[R]*Stagnation Temperature)

Speed of Sound

Go Speed of Sound = sqrt(Specific Heat Ratio*[R-Dry-Air]*Static Temperature)

Stagnation Velocity of Sound given Stagnation Enthalpy

Go Stagnation Velocity of Sound = sqrt((Specific Heat Ratio-1)*Stagnation Enthalpy)

Heat Capacity Ratio

Go Specific Heat Ratio = Specific Heat Capacity at Constant Pressure/Specific Heat Capacity at Constant Volume

Efficiency of cycle

Go Efficiency of Cycle = (Turbine Work-Compressor Work)/Heat

Internal Energy of Perfect Gas at given Temperature

Go Internal Energy = Specific Heat Capacity at Constant Volume*Temperature

Enthalpy of Ideal Gas at given Temperature

Go Enthalpy = Specific Heat Capacity at Constant Pressure*Temperature

Stagnation enthalpy

Go Stagnation Enthalpy = Enthalpy+(Velocity of Fluid Flow^2)/2

Efficiency of Joule cycle

Go Efficiency of Joule Cycle = Net Work Output/Heat

Pressure Ratio

Go Pressure Ratio = Final Pressure/Initial Pressure

Work ratio in practical cycle

Go Work Ratio = 1-(Compressor Work/Turbine Work)

Mach Number

Go Mach Number = Speed of Object/Speed of Sound

Mach Angle

Go Mach Angle = asin(1/Mach Number)

Efficiency of Joule cycle Formula

Efficiency of Joule Cycle = Net Work Output/Heat
η_{joule cycle} = W_Net/Q

What is efficiency?

Efficiency is a way of describing the amount of useful output of a process or machine can generate as a percentage of the input.

How to Calculate Efficiency of Joule cycle?

Efficiency of Joule cycle calculator uses Efficiency of Joule Cycle = Net Work Output/Heat to calculate the Efficiency of Joule Cycle, The efficiency of Joule cycle formula is defined as 100 times the ratio of net work output to heat added to the system. Efficiency of Joule Cycle is denoted by η_{joule cycle} symbol.

How to calculate Efficiency of Joule cycle using this online calculator? To use this online calculator for Efficiency of Joule cycle, enter Net Work Output (W_Net) & Heat (Q) and hit the calculate button. Here is how the Efficiency of Joule cycle calculation can be explained with given input values -> 1.557377 = 305000/610000.

FAQ

What is Efficiency of Joule cycle?

The efficiency of Joule cycle formula is defined as 100 times the ratio of net work output to heat added to the system and is represented as η_{joule cycle} = W_Net/Q or Efficiency of Joule Cycle = Net Work Output/Heat. Net Work Output is defined as the difference of work of turbine and work of compressor & Heat refers to the transfer of thermal energy between systems or objects due to a temperature difference.

How to calculate Efficiency of Joule cycle?

The efficiency of Joule cycle formula is defined as 100 times the ratio of net work output to heat added to the system is calculated using Efficiency of Joule Cycle = Net Work Output/Heat. To calculate Efficiency of Joule cycle, you need Net Work Output (W_Net) & Heat (Q). With our tool, you need to enter the respective value for Net Work Output & Heat and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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