Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis Calculator

✖Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.ⓘ Semi Conjugate Axis of Hyperbola [b]			+10% -10%
✖Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.ⓘ Focal Parameter of Hyperbola [p]			+10% -10%

✖Eccentricity of Hyperbola is the ratio of distances of any point on the Hyperbola from focus and the directrix, or it is the ratio of linear eccentricity and semi transverse axis of the Hyperbola.ⓘ Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis [e]

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Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis Solution

STEP 0: Pre-Calculation Summary

Formula Used

Eccentricity of Hyperbola = Semi Conjugate Axis of Hyperbola/sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2)
e = b/sqrt(b^2-p^2)
This formula uses 1 Functions, 3 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Eccentricity of Hyperbola - (Measured in Meter) - Eccentricity of Hyperbola is the ratio of distances of any point on the Hyperbola from focus and the directrix, or it is the ratio of linear eccentricity and semi transverse axis of the Hyperbola.
Semi Conjugate Axis of Hyperbola - (Measured in Meter) - Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.
Focal Parameter of Hyperbola - (Measured in Meter) - Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.

STEP 1: Convert Input(s) to Base Unit

Semi Conjugate Axis of Hyperbola: 12 Meter --> 12 Meter No Conversion Required
Focal Parameter of Hyperbola: 11 Meter --> 11 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

e = b/sqrt(b^2-p^2) --> 12/sqrt(12^2-11^2)

Evaluating ... ...

e = 2.5021729686849

STEP 3: Convert Result to Output's Unit

2.5021729686849 Meter --> No Conversion Required

FINAL ANSWER

2.5021729686849 ≈ 2.502173 Meter <-- Eccentricity of Hyperbola

(Calculation completed in 00.004 seconds)

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Indian Institute of Technology, Indian School of Mines, DHANBAD (IIT ISM), Dhanbad, Jharkhand

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LaTeX Go Eccentricity of Hyperbola = Linear Eccentricity of Hyperbola/sqrt(Linear Eccentricity of Hyperbola^2-Semi Conjugate Axis of Hyperbola^2)

Eccentricity of Hyperbola

LaTeX Go Eccentricity of Hyperbola = sqrt(1+(Semi Conjugate Axis of Hyperbola^2)/(Semi Transverse Axis of Hyperbola^2))

Eccentricity of Hyperbola given Latus Rectum and Semi Transverse Axis

LaTeX Go Eccentricity of Hyperbola = sqrt(1+Latus Rectum of Hyperbola/(2*Semi Transverse Axis of Hyperbola))

Eccentricity of Hyperbola given Linear Eccentricity and Semi Transverse Axis

LaTeX Go Eccentricity of Hyperbola = Linear Eccentricity of Hyperbola/Semi Transverse Axis of Hyperbola

Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis Formula

LaTeX Go

Eccentricity of Hyperbola = Semi Conjugate Axis of Hyperbola/sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2)
e = b/sqrt(b^2-p^2)

What is Hyperbola?

A Hyperbola is a type of conic section, which is a geometric figure that results from intersecting a cone with a plane. A Hyperbola is defined as the set of all points in a plane, the difference of whose distances from two fixed points (called the foci) is constant. In other words, a Hyperbola is the locus of points where the difference between the distances to two fixed points is a constant value. The standard form of the equation for a Hyperbola is: (x - h)²/a² - (y - k)²/b² = 1

What is Eccentricity of the Hyperbola and how is it calculated?

The eccentricity of a Hyperbola is the ratio of the distances from any point on the Hyperbola to the focus and the corresponding directrix. It is calculated by the formula e = c/a where e is the eccentricity of the Hyperbola, c is the linear eccentricity of the Hyperbola and a is the semi-transverse of the Hyperbola.

How to Calculate Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis?

Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis calculator uses Eccentricity of Hyperbola = Semi Conjugate Axis of Hyperbola/sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2) to calculate the Eccentricity of Hyperbola, The Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis formula is defined as the ratio of distances of any point on the Hyperbola from focus and the directrix and is calculated using the focal parameter and semi-conjugate axis of the Hyperbola. Eccentricity of Hyperbola is denoted by e symbol.

How to calculate Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis using this online calculator? To use this online calculator for Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis, enter Semi Conjugate Axis of Hyperbola (b) & Focal Parameter of Hyperbola (p) and hit the calculate button. Here is how the Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis calculation can be explained with given input values -> 2.502173 = 12/sqrt(12^2-11^2).

FAQ

What is Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis?

The Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis formula is defined as the ratio of distances of any point on the Hyperbola from focus and the directrix and is calculated using the focal parameter and semi-conjugate axis of the Hyperbola and is represented as e = b/sqrt(b^2-p^2) or Eccentricity of Hyperbola = Semi Conjugate Axis of Hyperbola/sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2). Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola & Focal Parameter of Hyperbola is the shortest distance between any of the foci and directrix of the corresponding wing of the Hyperbola.

How to calculate Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis?

The Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis formula is defined as the ratio of distances of any point on the Hyperbola from focus and the directrix and is calculated using the focal parameter and semi-conjugate axis of the Hyperbola is calculated using Eccentricity of Hyperbola = Semi Conjugate Axis of Hyperbola/sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2). To calculate Eccentricity of Hyperbola given Focal Parameter and Semi Conjugate Axis, you need Semi Conjugate Axis of Hyperbola (b) & Focal Parameter of Hyperbola (p). With our tool, you need to enter the respective value for Semi Conjugate Axis of Hyperbola & Focal Parameter of Hyperbola and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Eccentricity of Hyperbola?

In this formula, Eccentricity of Hyperbola uses Semi Conjugate Axis of Hyperbola & Focal Parameter of Hyperbola. We can use 3 other way(s) to calculate the same, which is/are as follows -

Eccentricity of Hyperbola = sqrt(1+(Semi Conjugate Axis of Hyperbola^2)/(Semi Transverse Axis of Hyperbola^2))
Eccentricity of Hyperbola = Linear Eccentricity of Hyperbola/Semi Transverse Axis of Hyperbola
Eccentricity of Hyperbola = Linear Eccentricity of Hyperbola/sqrt(Linear Eccentricity of Hyperbola^2-Semi Conjugate Axis of Hyperbola^2)

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