How to Calculate Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem?
Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem calculator uses Diagonal 2 of Cyclic Quadrilateral = ((Side A of Cyclic Quadrilateral*Side C of Cyclic Quadrilateral)+(Side B of Cyclic Quadrilateral*Side D of Cyclic Quadrilateral))/Diagonal 1 of Cyclic Quadrilateral to calculate the Diagonal 2 of Cyclic Quadrilateral, The Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem formula is defined as the line segment joining opposite vertices (B and D) of the Cyclic Quadrilateral, calculated using Ptolemy,s Theorem. Diagonal 2 of Cyclic Quadrilateral is denoted by d2 symbol.
How to calculate Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem using this online calculator? To use this online calculator for Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem, enter Side A of Cyclic Quadrilateral (Sa), Side C of Cyclic Quadrilateral (Sc), Side B of Cyclic Quadrilateral (Sb), Side D of Cyclic Quadrilateral (Sd) & Diagonal 1 of Cyclic Quadrilateral (d1) and hit the calculate button. Here is how the Diagonal 2 of Cyclic Quadrilateral using Ptolemy's Theorem calculation can be explained with given input values -> 11.36364 = ((10*8)+(9*5))/11.