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Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Calculator

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✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well 2 [h_w2]			+10% -10%
✖Total Time Interval is the amount of time required for the total change in concentration.ⓘ Total Time Interval [Δt]			+10% -10%

✖Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.ⓘ Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present [h_d]

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Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Solution

STEP 0: Pre-Calculation Summary

Formula Used

Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)
h_d = h_w2*10^((0.25*Δt)/2.303)
This formula uses 3 Variables

Variables Used

Depression Head - (Measured in Meter) - Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.
Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Total Time Interval - (Measured in Second) - Total Time Interval is the amount of time required for the total change in concentration.

STEP 1: Convert Input(s) to Base Unit

Depression Head in Well 2: 10 Meter --> 10 Meter No Conversion Required
Total Time Interval: 5 Second --> 5 Second No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h_d = h_w2*10^((0.25*Δt)/2.303) --> 10*10^((0.25*5)/2.303)

Evaluating ... ...

h_d = 34.895570235195

STEP 3: Convert Result to Output's Unit

34.895570235195 Meter --> No Conversion Required

FINAL ANSWER

34.895570235195 ≈ 34.89557 Meter <-- Depression Head

(Calculation completed in 00.020 seconds)

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< Depression Head when Pumping Stopped Calculators

Depression Head in well given pumping stopped and clay soil is present

LaTeX Go Depression Head = Depression Head in Well 2*exp(0.25*Total Time Interval)

Depression Head in Well given Pumping Stopped and Fine Sand is Present

LaTeX Go Depression Head = Depression Head in Well 2*exp(0.5*Time Interval)

Depression Head in Well given Pumping Stopped and Coarse Sand is Present

LaTeX Go Depression Head = Depression Head in Well 2*exp(1*Time Interval)

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present

LaTeX Go Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula

LaTeX Go

Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)
h_d = h_w2*10^((0.25*Δt)/2.303)

What is Clay Soil?

Clay soil is defined by its small particle size, high plasticity, excellent nutrient retention, and poor drainage. While it can be fertile and valuable for agricultural and construction purposes, its characteristics can also pose challenges in managing water and supporting healthy plant growth. Understanding clay soil's properties is essential for effective land management and agricultural practices.

How to Calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present calculator uses Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303) to calculate the Depression Head, The Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present formula is defined as the calculation of the value of depression head when we have prior information of other parameters used. Depression Head is denoted by h_d symbol.

How to calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present using this online calculator? To use this online calculator for Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present, enter Depression Head in Well 2 (h_w2) & Total Time Interval (Δt) and hit the calculate button. Here is how the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present calculation can be explained with given input values -> 34.89557 = 10*10^((0.25*5)/2.303).

FAQ

What is Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

The Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present formula is defined as the calculation of the value of depression head when we have prior information of other parameters used and is represented as h_d = h_w2*10^((0.25*Δt)/2.303) or Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303). Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped & Total Time Interval is the amount of time required for the total change in concentration.

How to calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

The Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present formula is defined as the calculation of the value of depression head when we have prior information of other parameters used is calculated using Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303). To calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present, you need Depression Head in Well 2 (h_w2) & Total Time Interval (Δt). With our tool, you need to enter the respective value for Depression Head in Well 2 & Total Time Interval and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Depression Head?

In this formula, Depression Head uses Depression Head in Well 2 & Total Time Interval. We can use 3 other way(s) to calculate the same, which is/are as follows -

Depression Head = Depression Head in Well 2*exp(0.25*Total Time Interval)
Depression Head = Depression Head in Well 2*exp(0.5*Time Interval)
Depression Head = Depression Head in Well 2*exp(1*Time Interval)

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