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Depression Head in Well at Time T given Pumping Stopped and Constant Calculator

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Depression Head after Pumping Stopped Constant Depending upon Base Soil Cross Sectional Area of Well Depression Head when Pumping Stopped More >>

✖Depression Head in Well 1 is the depression head in the well when pumping stopped.ⓘ Depression Head in Well 1 [h_w1]			+10% -10%
✖Constant Dependent on Base Soil is the constant depending on the soil at the base of the well.ⓘ Constant Dependent on Base Soil [K_b]			+10% -10%
✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time [t]			+10% -10%
✖Cross-Sectional Area of Well is the the surface area of the interior opening of the well.ⓘ Cross-Sectional Area of Well [A_csw]			+10% -10%

✖Depression Head after Pumping Stopped is the reduction in the water table or piezometric surface that remains after pumping has ceased.ⓘ Depression Head in Well at Time T given Pumping Stopped and Constant [h_dp]

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Depression Head in Well at Time T given Pumping Stopped and Constant Solution

STEP 0: Pre-Calculation Summary

Formula Used

Depression Head after Pumping Stopped = Depression Head in Well 1/(exp((Constant Dependent on Base Soil*Time)/Cross-Sectional Area of Well))
h_dp = h_w1/(exp((K_b*t)/A_csw))
This formula uses 1 Functions, 5 Variables

Functions Used

exp - n an exponential function, the value of the function changes by a constant factor for every unit change in the independent variable., exp(Number)

Variables Used

Depression Head after Pumping Stopped - (Measured in Meter) - Depression Head after Pumping Stopped is the reduction in the water table or piezometric surface that remains after pumping has ceased.
Depression Head in Well 1 - (Measured in Meter) - Depression Head in Well 1 is the depression head in the well when pumping stopped.
Constant Dependent on Base Soil - (Measured in Cubic Meter per Second) - Constant Dependent on Base Soil is the constant depending on the soil at the base of the well.
Time - (Measured in Second) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross-Sectional Area of Well - (Measured in Square Meter) - Cross-Sectional Area of Well is the the surface area of the interior opening of the well.

STEP 1: Convert Input(s) to Base Unit

Depression Head in Well 1: 3 Meter --> 3 Meter No Conversion Required
Constant Dependent on Base Soil: 4.99 Cubic Meter per Hour --> 0.00138611111111111 Cubic Meter per Second (Check conversion here)
Time: 4 Hour --> 14400 Second (Check conversion here)
Cross-Sectional Area of Well: 13 Square Meter --> 13 Square Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h_dp = h_w1/(exp((K_b*t)/A_csw)) --> 3/(exp((0.00138611111111111*14400)/13))

Evaluating ... ...

h_dp = 0.646118518590733

STEP 3: Convert Result to Output's Unit

0.646118518590733 Meter --> No Conversion Required

FINAL ANSWER

0.646118518590733 ≈ 0.646119 Meter <-- Depression Head after Pumping Stopped

(Calculation completed in 00.004 seconds)

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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< Depression Head after Pumping Stopped Calculators

Depression Head in Well at Time T after Pumping Stopped

Go Depression Head = Depression Head in Well/exp(Specific Capacity*Time)

Depression Head in Well at Time T after Pumping Stopped with Base 10

Go Depression Head in Well 2 = Depression Head in Well 1/10^((Specific Capacity*Time)/2.303)

Depression Head in Well at Time T after Pumping Stopped with Base 10 and Clay soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600)/2.303)

Depression Head in Well at Time T after Pumping Stopped and Clay Soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600))

Depression Head in Well at Time T given Pumping Stopped and Constant Formula

Depression Head after Pumping Stopped = Depression Head in Well 1/(exp((Constant Dependent on Base Soil*Time)/Cross-Sectional Area of Well))
h_dp = h_w1/(exp((K_b*t)/A_csw))

What is Specific Capacity?

Specific Capacity refers to the efficiency of a well in producing water. It is a measure of how much water (in volume) a well can yield per unit of drawdown (or drop in water level) over a specific period of time. The specific capacity is typically expressed in units such as gallons per minute per foot (gpm/ft) or liters per second per meter (L/s/m).

How to Calculate Depression Head in Well at Time T given Pumping Stopped and Constant?

Depression Head in Well at Time T given Pumping Stopped and Constant calculator uses Depression Head after Pumping Stopped = Depression Head in Well 1/(exp((Constant Dependent on Base Soil*Time)/Cross-Sectional Area of Well)) to calculate the Depression Head after Pumping Stopped, The Depression Head in Well at Time T given Pumping Stopped and Constant formula is defined as the calculation of the value of depression head in the well when we have prior information of other parameters used. Depression Head after Pumping Stopped is denoted by h_dp symbol.

How to calculate Depression Head in Well at Time T given Pumping Stopped and Constant using this online calculator? To use this online calculator for Depression Head in Well at Time T given Pumping Stopped and Constant, enter Depression Head in Well 1 (h_w1), Constant Dependent on Base Soil (K_b), Time (t) & Cross-Sectional Area of Well (A_csw) and hit the calculate button. Here is how the Depression Head in Well at Time T given Pumping Stopped and Constant calculation can be explained with given input values -> 0.646119 = 3/(exp((0.00138611111111111*14400)/13)).

FAQ

What is Depression Head in Well at Time T given Pumping Stopped and Constant?

The Depression Head in Well at Time T given Pumping Stopped and Constant formula is defined as the calculation of the value of depression head in the well when we have prior information of other parameters used and is represented as h_dp = h_w1/(exp((K_b*t)/A_csw)) or Depression Head after Pumping Stopped = Depression Head in Well 1/(exp((Constant Dependent on Base Soil*Time)/Cross-Sectional Area of Well)). Depression Head in Well 1 is the depression head in the well when pumping stopped, Constant Dependent on Base Soil is the constant depending on the soil at the base of the well, Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future & Cross-Sectional Area of Well is the the surface area of the interior opening of the well.

How to calculate Depression Head in Well at Time T given Pumping Stopped and Constant?

The Depression Head in Well at Time T given Pumping Stopped and Constant formula is defined as the calculation of the value of depression head in the well when we have prior information of other parameters used is calculated using Depression Head after Pumping Stopped = Depression Head in Well 1/(exp((Constant Dependent on Base Soil*Time)/Cross-Sectional Area of Well)). To calculate Depression Head in Well at Time T given Pumping Stopped and Constant, you need Depression Head in Well 1 (h_w1), Constant Dependent on Base Soil (K_b), Time (t) & Cross-Sectional Area of Well (A_csw). With our tool, you need to enter the respective value for Depression Head in Well 1, Constant Dependent on Base Soil, Time & Cross-Sectional Area of Well and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Depression Head after Pumping Stopped?

In this formula, Depression Head after Pumping Stopped uses Depression Head in Well 1, Constant Dependent on Base Soil, Time & Cross-Sectional Area of Well. We can use 3 other way(s) to calculate the same, which is/are as follows -

Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600))
Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600)/2.303)
Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.5/2.303)*Time/3600)

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