What is a triode region in MOSFET? Is it different from linear region?
A MOSFET is said to operate in 3 regions, cutoff, triode and saturation,based on the condition of the inversion layer existing between the source and drain.
The triode region is the operating region where the inversion region exists and current flows, but this region has begun to taper near the source. The potential requirement here is Vds < Vgs -Vth.
Here, the drain source current has a parabolic relation ship with the drain source potential. The MOSFET operates as a switch in this region.
The linear region of a MOSFET can be considered as a special portion of the triode region, where because of the very small value of the applied drain-source potential, there is a roughly linear relationship between Vds and Ids and the MOSFET behaves like a voltage-dependent resistor.
The potential condition for linear or "deep triode" region is Vds << Vgs-Vth.
How to Calculate Current Entering Drain-Source in Triode Region of NMOS?
Current Entering Drain-Source in Triode Region of NMOS calculator uses Drain Current in NMOS = Process Transconductance Parameter in NMOS*Width of Channel/Length of the Channel*((Gate Source Voltage-Threshold Voltage)*Drain Source Voltage-1/2*(Drain Source Voltage)^2) to calculate the Drain Current in NMOS, The Current entering drain-source in triode region of NMOS when Vgs is given can be found by multiplying the charge per unit channel length by the electron drift velocity. Drain Current in NMOS is denoted by Id symbol.
How to calculate Current Entering Drain-Source in Triode Region of NMOS using this online calculator? To use this online calculator for Current Entering Drain-Source in Triode Region of NMOS, enter Process Transconductance Parameter in NMOS (k'n), Width of Channel (Wc), Length of the Channel (L), Gate Source Voltage (Vgs), Threshold Voltage (VT) & Drain Source Voltage (Vds) and hit the calculate button. Here is how the Current Entering Drain-Source in Triode Region of NMOS calculation can be explained with given input values -> 239693 = 0.002*1E-05/3E-06*((10.3-1.82)*8.43-1/2*(8.43)^2).