Cross Sectional Area given Time required to Lower Liquid for Triangular Notch Calculator

✖Time interval is the time duration between two events/entities of interest.ⓘ Time Interval [Δt]			+10% -10%
✖The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.ⓘ Coefficient of Discharge [C_d]			+10% -10%
✖The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.ⓘ Acceleration due to Gravity [g]			+10% -10%
✖Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.ⓘ Theta [θ]			+10% -10%
✖Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head on Downstream of Weir [h₂]			+10% -10%
✖Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head on Upstream of Weir [H_Upstream]			+10% -10%

✖Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.ⓘ Cross Sectional Area given Time required to Lower Liquid for Triangular Notch [A_R]

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Cross Sectional Area given Time required to Lower Liquid for Triangular Notch Solution

STEP 0: Pre-Calculation Summary

Formula Used

Cross-Sectional Area of Reservoir = (Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))))
A_R = (Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*((1/h₂^(3/2))-(1/H_Upstream^(3/2))))
This formula uses 2 Functions, 7 Variables

Functions Used

tan - The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle., tan(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Cross-Sectional Area of Reservoir - (Measured in Square Meter) - Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.
Time Interval - (Measured in Second) - Time interval is the time duration between two events/entities of interest.
Coefficient of Discharge - The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.
Acceleration due to Gravity - (Measured in Meter per Square Second) - The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
Head on Downstream of Weir - (Measured in Meter) - Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
Head on Upstream of Weir - (Measured in Meter) - Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

STEP 1: Convert Input(s) to Base Unit

Time Interval: 1.25 Second --> 1.25 Second No Conversion Required
Coefficient of Discharge: 0.66 --> No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Head on Downstream of Weir: 5.1 Meter --> 5.1 Meter No Conversion Required
Head on Upstream of Weir: 10.1 Meter --> 10.1 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A_R = (Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*((1/h₂^(3/2))-(1/H_Upstream^(3/2)))) --> (1.25*(8/15)*0.66*sqrt(2*9.8)*tan(0.5235987755982/2))/((2/3)*((1/5.1^(3/2))-(1/10.1^(3/2))))

Evaluating ... ...

A_R = 14.0636418016635

STEP 3: Convert Result to Output's Unit

14.0636418016635 Square Meter --> No Conversion Required

FINAL ANSWER

14.0636418016635 ≈ 14.06364 Square Meter <-- Cross-Sectional Area of Reservoir

(Calculation completed in 00.004 seconds)

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< Time Required to Empty a Reservoir with Rectangular Weir Calculators

Coefficient of Discharge for Time Required to Lower Liquid Surface

LaTeX Go Coefficient of Discharge = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Length of Crest for time required to Lower Liquid Surface

LaTeX Go Length of Weir Crest = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Time Interval))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Time Required to Lower Liquid Surface

LaTeX Go Time Interval = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Cross Sectional Area given Time required to Lower Liquid Surface

LaTeX Go Cross-Sectional Area of Reservoir = (Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))

Cross Sectional Area given Time required to Lower Liquid for Triangular Notch Formula

LaTeX Go

What is meant by Coefficient of Discharge?

Coefficient of Discharge is the ratio of the actual discharge to the theoretical discharge, i.e., the ratio of the mass flow rate at the discharge end.

How to Calculate Cross Sectional Area given Time required to Lower Liquid for Triangular Notch?

Cross Sectional Area given Time required to Lower Liquid for Triangular Notch calculator uses Cross-Sectional Area of Reservoir = (Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2)))) to calculate the Cross-Sectional Area of Reservoir, The Cross Sectional Area given Time required to Lower Liquid for Triangular Notch is area of a two-dimensional shape that is obtained when a three-dimensional object - such as a cylinder. Cross-Sectional Area of Reservoir is denoted by A_R symbol.

How to calculate Cross Sectional Area given Time required to Lower Liquid for Triangular Notch using this online calculator? To use this online calculator for Cross Sectional Area given Time required to Lower Liquid for Triangular Notch, enter Time Interval (Δt), Coefficient of Discharge (C_d), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) and hit the calculate button. Here is how the Cross Sectional Area given Time required to Lower Liquid for Triangular Notch calculation can be explained with given input values -> 14.06364 = (1.25*(8/15)*0.66*sqrt(2*9.8)*tan(0.5235987755982/2))/((2/3)*((1/5.1^(3/2))-(1/10.1^(3/2)))).

FAQ

What is Cross Sectional Area given Time required to Lower Liquid for Triangular Notch?

The Cross Sectional Area given Time required to Lower Liquid for Triangular Notch is area of a two-dimensional shape that is obtained when a three-dimensional object - such as a cylinder and is represented as A_R = (Δt*(8/15)*C_d*sqrt(2*g)*tan(θ/2))/((2/3)*((1/h₂^(3/2))-(1/H_Upstream^(3/2)))) or Cross-Sectional Area of Reservoir = (Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2)))). Time interval is the time duration between two events/entities of interest, The Coefficient of Discharge is ratio of actual discharge to theoretical discharge, The Acceleration due to Gravity is acceleration gained by an object because of gravitational force, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures & Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

How to calculate Cross Sectional Area given Time required to Lower Liquid for Triangular Notch?

The Cross Sectional Area given Time required to Lower Liquid for Triangular Notch is area of a two-dimensional shape that is obtained when a three-dimensional object - such as a cylinder is calculated using Cross-Sectional Area of Reservoir = (Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2)))). To calculate Cross Sectional Area given Time required to Lower Liquid for Triangular Notch, you need Time Interval (Δt), Coefficient of Discharge (C_d), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream). With our tool, you need to enter the respective value for Time Interval, Coefficient of Discharge, Acceleration due to Gravity, Theta, Head on Downstream of Weir & Head on Upstream of Weir and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Cross-Sectional Area of Reservoir?

In this formula, Cross-Sectional Area of Reservoir uses Time Interval, Coefficient of Discharge, Acceleration due to Gravity, Theta, Head on Downstream of Weir & Head on Upstream of Weir. We can use 2 other way(s) to calculate the same, which is/are as follows -

Cross-Sectional Area of Reservoir = (Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))
Cross-Sectional Area of Reservoir = (Time Interval*Bazins Coefficient*sqrt(2*Acceleration due to Gravity))/((1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))*2)

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